Chapter 6: Problem 80
Refer to the periodic table and write the predicted electron configuration for each of the following negative ions using core notation: (a) \(\mathrm{Br}^{-}\) (b) \(\mathrm{Te}^{2-}\) (c) \(\mathrm{As}^{3-}\) (d) \(\mathrm{O}^{2-}\)
Short Answer
Expert verified
(a) [Ar] 3d^{10} 4s^{2} 4p^{6}; (b) [Kr] 4d^{10} 5s^{2} 5p^{6}; (c) [Ar] 3d^{10} 4s^{2} 4p^{6}; (d) [He] 2s^{2} 2p^{6}.
Step by step solution
01
Locate the Element on the Periodic Table
For each ion, start by identifying the element on the periodic table. Determine its atomic number, which tells you the number of protons and electrons in the neutral atom.
02
Neutral Electron Configuration
Write the electron configuration for the neutral atom of the element using core notation, where the configuration starts with the previous noble gas in brackets, followed by the remaining electron configuration beyond that noble gas.
03
Adjust for the Ion Charge
Modify the electron configuration for the ion by adding the appropriate number of electrons. For negative ions, add electrons based on the charge of the ion to the normal electron configuration.
04
Example Ion: Br^{-}
Bromine (Br) is element 35. Its neutral electron configuration is [Ar] 3d^{10} 4s^{2} 4p^{5}. For Br^{-}, add 1 electron to get [Ar] 3d^{10} 4s^{2} 4p^{6}.
05
Example Ion: Te^{2-}
Tellurium (Te) is element 52. Its neutral electron configuration is [Kr] 4d^{10} 5s^{2} 5p^{4}. Add 2 electrons for Te^{2-} to make it [Kr] 4d^{10} 5s^{2} 5p^{6}.
06
Example Ion: As^{3-}
Arsenic (As) is element 33. Its neutral electron configuration is [Ar] 3d^{10} 4s^{2} 4p^{3}. Add 3 electrons for As^{3-}, resulting in [Ar] 3d^{10} 4s^{2} 4p^{6}.
07
Example Ion: O^{2-}
Oxygen (O) is element 8. Its neutral electron configuration is [He] 2s^{2} 2p^{4}. Add 2 electrons for O^{2-} to get [He] 2s^{2} 2p^{6}.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Negative Ions
Negative ions, also known as anions, form when an atom gains one or more electrons. This process results in a net negative charge.
Atoms strive to achieve a stable electron configuration, often resembling that of the nearest noble gas.
For example:
Atoms strive to achieve a stable electron configuration, often resembling that of the nearest noble gas.
For example:
- When bromine becomes a negative ion (\( \mathrm{Br}^{-} \)), it gains one electron.
- Tellurium, as \( \mathrm{Te}^{2-} \), gains two electrons, while arsenic, as \( \mathrm{As}^{3-} \), gains three.
- Similarly, oxygen in its negative form (\( \mathrm{O}^{2-} \)) gains two electrons.
Exploring Core Notation
Core notation simplifies the representation of electron configurations. Instead of listing all orbitals, we use a noble gas to represent filled electron shells.
This method reduces complexity and highlights valence electrons more clearly.
For instance:
This method reduces complexity and highlights valence electrons more clearly.
For instance:
- Bromine's electron configuration in core notation is \([\text{Ar}] 3d^{10} 4s^{2} 4p^{5}\).
- For negative ions, additional electrons are added after the noble gas core, as seen in \( \mathrm{Br}^{-} \) becoming \([\text{Ar}] 3d^{10} 4s^{2} 4p^{6}\).
Position Matters: The Periodic Table
The periodic table is a map that helps us locate elements and predict their behavior when they form ions.
It organizes elements by increasing atomic number and similar chemical properties.
Understanding its structure is crucial for identifying electron configurations.
It organizes elements by increasing atomic number and similar chemical properties.
Understanding its structure is crucial for identifying electron configurations.
- Elements like bromine and tellurium are within groups that commonly form anions.
- Their positions hint at the number of electrons they gain to become stable.
Ion Charge Adjustment in Electron Configurations
Ion charge adjustment involves adding electrons to an atom's electron configuration to reflect its ion form.
This is especially relevant for negative ions, which gain electrons.
This is especially relevant for negative ions, which gain electrons.
- Bromine as \( \mathrm{Br}^{-} \) gains one electron to fill its outer shell, reflecting a more stable state.
- Oxygen gains two electrons in forming \( \mathrm{O}^{2-} \), achieving the same configuration as neon.