Chapter 6: Problem 41
The formulas for the chlorides of potassium, calcium, boron, and germanium are, respectively, \(\mathrm{KCl}, \mathrm{CaCl}_{2}, \mathrm{BCl}_{3}\), and \(\mathrm{GeCl}_{4}\). Using the periodic table, predict the chemical formulas for each of the following similar compounds: (a) potassium fluoride (b) calcium fluoride (c) boron bromide (d) germanium iodide
Short Answer
Step by step solution
Determine Valence Electrons
Identify Halogens' Valence
Predict Potassium Fluoride Formula
Predict Calcium Fluoride Formula
Predict Boron Bromide Formula
Predict Germanium Iodide Formula
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Valence Electrons
This desire for stability drives atoms to either transfer or share valence electrons, forming different kinds of chemical bonds. For example:
- Potassium (K) has one valence electron and tends to lose it to achieve a full outer shell, making it highly reactive.
- Calcium (Ca), with two valence electrons, will typically lose both to achieve stability.
- Boron (B) has three valence electrons and often shares these through covalent bonds.
- Germanium (Ge) contains four valence electrons, allowing it to form multiple bonds, usually with nonmetals from Group 17.
Understanding valence electrons helps predict the type of bond formed and thus, the chemical formula of a compound.
Periodic Table
The vertical columns, called groups or families, indicate elements with similar properties and the same number of valence electrons. For example:
- Group 1 contains alkali metals like potassium, each with one valence electron.
- Group 2 hosts alkaline earth metals such as calcium, with two valence electrons.
- Group 13 includes elements like boron, with three valence electrons.
- Group 14, featuring germanium, consists of elements with four valence electrons.
- Group 17, known as halogens, comprises elements like fluorine, chlorine, bromine, and iodine, each with seven valence electrons.
By understanding the layout of the periodic table, students can predict the likely formulas of compounds by identifying how many electrons each element tends to gain or lose.
Ionic and Covalent Bonds
- Potassium fluoride (KF) is a classic example of an ionic bond, where potassium (a metal) loses an electron to become K extsuperscript{+}, and fluorine (a nonmetal) gains an electron to form F extsuperscript{−}. The attraction between these charged ions forms the compound.
- Calcium fluoride (CaF extsubscript{2}) also forms through ionic bonding, with calcium losing two electrons to form Ca extsuperscript{2+} and each fluorine gaining one to form F extsuperscript{−}. Two fluoride ions pair with one calcium ion.
- Boron bromide (BBr extsubscript{3}) results from covalent bonding, where boron shares its three electrons with three bromine atoms.
- Similarly, germanium iodide (GeI extsubscript{4}) forms through covalent bonds, sharing electrons between germanium and iodine atoms.
Recognizing the type of bond helps in understanding the behavior and structure of the resulting compounds.