Chapter 12: Problem 39
Calculate the heat required to convert \(115 \mathrm{~g}\) of ice at \(0.0^{\circ} \mathrm{C}\) to steam at \(100.0^{\circ} \mathrm{C}\).
Short Answer
Expert verified
The total heat required is 346,380 J.
Step by step solution
01
Calculate the heat to melt the ice
First, we need to calculate the heat required to melt 115 g of ice at 0.0°C into water at 0.0°C. We use the formula for heat transfer: \( q_1 = mL_f \) where \( m \) is the mass in grams and \( L_f \) is the latent heat of fusion for ice, which is \( 334 \, \text{J/g} \). Therefore, \( q_1 = 115 \, \text{g} \times 334 \, \text{J/g} = 38,410 \, \text{J} \).
02
Calculate the heat to raise water temperature
Next, we calculate the heat required to raise the temperature of the resulting water from 0.0°C to 100.0°C using \( q_2 = mc\Delta T \), where \( c \) is the specific heat capacity of water (\( 4.18 \, \text{J/g} \cdot \text{°C} \)) and \( \Delta T = 100.0\, \text{°C} - 0.0\, \text{°C} = 100.0\, \text{°C} \). Thus, \( q_2 = 115 \, \text{g} \times 4.18 \, \text{J/g} \cdot \text{°C} \times 100.0 \text{°C} = 48,070 \, \text{J} \).
03
Calculate the heat to convert water to steam
Lastly, we calculate the heat needed to convert water at 100.0°C to steam at 100.0°C. We use the formula \( q_3 = mL_v \), where \( L_v \) is the latent heat of vaporization for water, which is \( 2260 \, \text{J/g} \).Therefore, \( q_3 = 115 \, \text{g} \times 2260 \, \text{J/g} = 259,900 \, \text{J} \).
04
Sum the total heat required
Finally, we sum all the amounts of heat calculated to find the total heat required: \( q_{\text{total}} = q_1 + q_2 + q_3 = 38,410 \, \text{J} + 48,070 \, \text{J} + 259,900 \, \text{J} = 346,380 \, \text{J} \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Latent Heat of Fusion
When a solid turns into a liquid, it absorbs energy without a change in temperature. This energy absorption is known as the latent heat of fusion. In simpler terms, it's the energy needed to melt a solid. For ice, this value is about 334 Joules per gram.
- "Latent" means hidden, indicating that this heat is not used to increase temperature.
- "Fusion" refers to melting, the phase change from solid to liquid.
Specific Heat Capacity
Specific heat capacity is the measure of a substance's ability to absorb heat energy. It defines how much energy is required to raise the temperature of one gram of a substance by one degree Celsius. For water, this value is 4.18 Joules per gram per degree Celsius. This means that water requires more heat to change its temperature compared to many other substances.
- Higher specific heat capacity = needs more energy to heat up.
- Crucial for understanding temperature changes within a fluid system.
Latent Heat of Vaporization
When a liquid turns into a gas, it's called vaporization. During this phase change, the substance absorbs a significant amount of energy without a change in temperature, known as the latent heat of vaporization. For water, it takes 2260 Joules per gram to transition from liquid to vapor.
- This process involves breaking intermolecular forces.
- Energy intake is entirely utilized for the phase transition.