Chapter 8: Problem 97
Oxygen can be produced by the decomposition of potassium chlorate, \(\mathrm{KClO}_{3}\). The products of the reaction are \(\mathrm{KCl}\) and \(\mathrm{O}_{2}\). Write a balanced equation for the reaction.
Short Answer
Expert verified
The balanced equation for the decomposition of potassium chlorate into potassium chloride and oxygen is \(2\mathrm{KClO}_{3} \rightarrow 2\mathrm{KCl} + 3\mathrm{O}_{2}\).
Step by step solution
01
Write the unbalanced equation
First, let's write down the unbalanced chemical equation using the chemical formula of the reactants and products:
\(\mathrm{KClO}_{3} \rightarrow \mathrm{KCl} + \mathrm{O}_{2}\)
02
Balance the equation
Now, we will balance the equation by adjusting the coefficients (the numbers in front of the chemical formulas) of the reactants and products.
1. Count the number of atoms for each element on both sides of the equation:
Reactant side:
- 1 K atom
- 1 Cl atom
- 3 O atoms
Product side:
- 1 K atom
- 1 Cl atom
- 2 O atoms (in one O₂ molecule)
2. Notice that the number of oxygen atoms is not balanced. To balance the oxygen atoms, place a coefficient of 2 in front of the potassium chlorate molecule:
\(2\mathrm{KClO}_{3} \rightarrow \mathrm{KCl} + \mathrm{O}_{2}\)
Now, we have:
Reactant side:
- 2 K atoms
- 2 Cl atoms
- 6 O atoms
3. To balance the K and Cl atoms, place a coefficient of 2 in front of the potassium chloride molecule:
\(2\mathrm{KClO}_{3} \rightarrow 2\mathrm{KCl} + \mathrm{O}_{2}\)
Now, we have:
Product side:
- 2 K atoms
- 2 Cl atoms
- 2 O atoms (in one O₂ molecule) * 2 = 4 O atoms
4. Finally, place a coefficient of 3 in front of the oxygen molecule to balance the oxygen atoms:
\(2\mathrm{KClO}_{3} \rightarrow 2\mathrm{KCl} + 3\mathrm{O}_{2}\)
Now, we have:
Product side:
- 2 K atoms
- 2 Cl atoms
- 2 O atoms (in one O₂ molecule) * 3 = 6 O atoms
The equation is now balanced, and the final balanced chemical equation is:
\(2\mathrm{KClO}_{3} \rightarrow 2\mathrm{KCl} + 3\mathrm{O}_{2}\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Oxygen Production
Oxygen is a vital component for all forms of life. Producing oxygen through chemical reactions is an essential area of research and practice in chemistry. One common method involves the decomposition of compounds that contain oxygen, such as potassium chlorate (\(\mathrm{KClO}_3\)).
- Oxygen is released as one of the products in the decomposition of potassium chlorate.
- The reaction not only highlights the production of oxygen but also serves as a classic example of generating gases from solids in a laboratory setting.
Chemical Decomposition
Chemical decomposition is a type of chemical reaction where a single compound breaks down into two or more simpler substances. It is the opposite of combination reactions, where substances combine to form a new compound. In the decomposition of potassium chlorate (\(\mathrm{KClO}_3\)), it breaks down into potassium chloride (\(\mathrm{KCl}\)) and oxygen gas (\(\mathrm{O}_2\)).
- This reaction is significant because it demonstrates how a more complex compound can be broken down into simpler components.
- Decomposition requires energy, often in the form of heat, to overcome the forces holding the compound together.
Chemical Reaction
A chemical reaction involves the transformation of reactants into products. When potassium chlorate decompose, a chemical reaction takes place converting it into potassium chloride and oxygen gas. This type of reaction is fundamental in chemistry as it establishes an understanding of how substances interact.
- During a chemical reaction, bonds between atoms are broken and reformed, leading to new substances being produced.
- Not all systems require visible changes; some reactions, like color changes or gas production, are more detectable.
Stoichiometry
Stoichiometry is a branch of chemistry dealing with quantitative relationships in chemical reactions. It involves using balanced chemical equations to calculate the amounts of reactants and products involved in a reaction.In the decomposition reaction of potassium chlorate, stoichiometry helps us determine:
- The coefficients needed to balance the equation ensuring mass conservation.
- This tells us, precisely, how much product we can expect from a given amount of reactant.