Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Predict the formula for lithium nitride, made from lithium, \(\mathrm{Li}\), and nitrogen, \(\mathrm{N}\). Explain your reasoning.

Short Answer

Expert verified
The formula for lithium nitride is \(\text{Li}_3\text{N}\). This is because lithium forms a +1 ion and nitrogen forms a -3 ion. To create a neutral compound, we need three lithium ions to balance the charge of one nitrogen ion. This results in the formula \(\text{Li}_3\text{N}\).

Step by step solution

01

Determine the charges of the ions

Lithium, as an alkali metal, tends to lose its single valence electron to form a positive ion with a charge of +1. Following the formula: \(\text{Charge of Lithium ion} = +1\) Nitrogen, on the other hand, tends to gain 3 more electrons to complete its outer electron shell, forming a negative ion with a charge of -3. Using the formula: \(\text{Charge of Nitrogen ion} = -3\)
02

Combine the ions to form a neutral compound

Now, we have the charges of each ion, we need to combine them in a ratio that results in a neutral compound. In this case, we can balance the charges by using 3 lithium ions and 1 nitrogen ion, as the total charge will be 0 in this ratio. \((\text{Charge of Lithium ion} \times 3) + (\text{Charge of Nitrogen ion} \times 1) = 0\) \((+1 \times 3) + (-3 \times 1) = 0\) \((+3) + (-3) = 0\)
03

Write the formula for lithium nitride

Having found the ratio of the ions needed for a neutral charge (3 lithium ions to 1 nitrogen ion), we can write the formula for lithium nitride: \[\text{Li}_3\text{N}\] Thus, the formula for lithium nitride, made from lithium (Li) and nitrogen (N), is \(\text{Li}_3\text{N}\), with the reasoning based on achieving a neutral charge in the compound by combining the ions in a specific ratio.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ionic Compounds
Ionic compounds are chemical compounds made up of charged particles known as ions. These ions form when an atom loses or gains electrons, leading to a positive or negative charge, respectively. In an ionic compound, these ions are held together by strong electrostatic forces in a lattice structure, creating a stable compound.

Here's what happens in the case of lithium nitride:
  • Positive Ions (Cations): Lithium ( \(\mathrm{Li}\) ) loses its single valence electron, resulting in a positively charged ion with a charge of +1.
  • Negative Ions (Anions): Nitrogen ( \(\mathrm{N}\) ) gains electrons to fill its outer shell, becoming negatively charged with a charge of -3.
The critical aspect of ionic compounds like lithium nitride is that the total charges from the ions must balance to zero. This means that the positive and negative charges cancel each other out, creating a neutral compound overall. This balance is why three lithium ions combine with one nitrogen ion to form lithium nitride, achieving the stable neutral charge needed.
Valence Electrons
Valence electrons are the electrons in the outermost shell of an atom. These are the electrons involved in chemical bonding and determine how an atom will interact and bond with other atoms. Understanding valence electrons is key to predicting the formation of ionic compounds.

In the formation of lithium nitride:
  • Lithium: Possesses one valence electron. Because it belongs to Group 1 in the periodic table, this electron is readily lost, forming a positively charged ion with a charge of +1.
  • Nitrogen: Has five valence electrons, as it is part of Group 15. It needs three additional electrons to complete its outer electron shell, making it inclined to gain electrons and form an ion with a -3 charge.
The interactions between the valence electrons of lithium and nitrogen dictate how these elements form ions and subsequently bond to create a stable ionic compound. This activity is fundamental in determining the chemical formulas of compounds.
Chemical Formula
A chemical formula conveys the proportions of atoms that make up a compound. It uses element symbols and numerical subscripts to indicate the number of each kind of atom in the simplest unit of the compound.

For instance, the chemical formula for lithium nitride is \(\mathrm{Li}_3\mathrm{N}\) :
  • Subscript in Li: The subscript '3' after lithium indicates there are three lithium ions for every one nitrogen ion.
  • Balance of Charge: This ratio results from balancing the total positive charge from lithium \((+1 \times 3 = +3)\) with the total negative charge from nitrogen \((-3)\).
  • Representation of Neutrality: The chemical formula \(\mathrm{Li}_3\mathrm{N}\) shows that the compound is neutral, with no overall charge.
Understanding the chemical formula is crucial for predicting the structure and reactivity of the compound. It provides insights into how the compound is constructed at an atomic level, ensuring the stability and balance of charges necessary for the compound's existence.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Draw a Bohr model for an Al atom and for an \(\mathrm{Al}^{3+}\) ion. How many electrons are there in the valence shell in each drawing?

What is the total number of \(p\) -subshell electrons for each of the following atoms: \(\mathrm{P}, \mathrm{Mg}\), Se, \(\mathrm{Zn} ?\)

Below are data on the first four ionization energies for a fictitious element \(X\). First ionization energy \(=500 \mathrm{~kJ} / \mathrm{mol}\) Second ionization energy \(=2000 \mathrm{~kJ} / \mathrm{mol}\) Third ionization energy \(=3500 \mathrm{~kJ} / \mathrm{mol}\) Fourth ionization energy \(=25,000 \mathrm{~kJ} / \mathrm{mol}\) From the data, which of the following statements is(are) incorrect? (a) \(\mathrm{X}\) could belong to group IIIA. (b) The fourth ionization energy is so much greater than the third ionization energy because \(\mathrm{X}^{3+}\) consists of a noble-gas core or a pseudo- noble-gas core. (c) The third ionization energy is greater than the second ionization energy because \(\mathrm{X}^{2+}\) has a bigger charge than \(\mathrm{X}^{+}\). (d) \(\mathrm{X}\) could belong to group IIIB. (e) \(X\) could belong to group VA.

According to the Bohr model, why do atoms get larger as you proceed down a group in the periodic table?

When a hydrogen atom is excited in a flame, a line of blue-violet light is emitted. This happens when an electron makes a transition between the \(n=5\) and the \(n=2\) orbit of the atom. If the energy of this light is \(2.9 \mathrm{eVs}\) and the energy of an electron in the \(n=2\) hydrogen orbit is \(11.2 \mathrm{eVs}\), what must be the energy of the \(n=5\) orbit?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free