Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Why is the formula for calcium sulfide \(\mathrm{CaS}\) and not \(\mathrm{Ca}_{2} \mathrm{~S} ?\)

Short Answer

Expert verified
The formula for calcium sulfide is CaS because the valencies of calcium (+2) and sulfur (-2) balance each other without the need for a subscript. This is determined by understanding valency and elements' combining capacity. Calcium loses 2 electrons and sulfur gains 2 electrons, resulting in a stable compound with electrical neutrality.

Step by step solution

01

Understanding Valency

Valency is the measure of an element's combining capacity with other elements to form compounds. It's determined by the number of electrons an element can gain, lose, or share in order to achieve a stable electronic configuration (a full outer shell of electrons).
02

Identifying the Valency of Calcium and Sulfur

Calcium (Ca) belongs to Group 2 of the periodic table, which means it has 2 valence electrons. Calcium's valency is +2, since it prefers to lose these 2 electrons to achieve a stable electronic configuration with a full outer shell. Sulfur (S) belongs to Group 16 of the periodic table, which means it has 6 valence electrons. Sulfur requires 2 more electrons to achieve a stable electronic configuration, so its valency is -2.
03

Applying the Valency Rule to Form the Compound

When elements combine to form a compound, their valencies should be balanced to maintain electrical neutrality in the compound. To do this, we can use the 'cross-over rule' or simply swap the valency numbers of the elements. Calcium (Ca) has a valency of +2, while sulfur (S) has a valency of -2. When we cross over the valencies, we use the absolute value of the valency and write the compound as: Calcium Sulfide: Ca (with subscript 2) S (with subscript 2) However, since the valency numbers (2) are the same, we can simplify this by removing the subscripts 2: Calcium Sulfide: CaS
04

Conclusion

The formula for calcium sulfide is CaS and not Ca₂S because the valencies of calcium and sulfur balance each other without the need for a subscript in their chemical formula. By understanding the concept of valency and combining capacity, we can determine the correct formula for compounds.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Chemical Formula
A chemical formula is a concise way of expressing information about the atoms that constitute a particular chemical compound. It provides insights into the elemental composition of the compound at the atomic level. In the case of calcium sulfide, its proper chemical formula is the result of balancing the charges from the constituent elements, calcium (Ca) and sulfur (S).
To represent the compound, each element's symbol is used along with subscripts indicating the number of each type of atom in the compound. For calcium sulfide, the formula is written as \( \text{CaS} \). This indicates that for every calcium atom, there is one sulfur atom, balancing out their respective charges.
Using the Periodic Table
The periodic table is an essential tool for chemists, providing valuable information about the elements. Each element is characterized by its atomic number, which is the number of protons in its nucleus.
Knowing an element’s position on the periodic table helps to determine its properties, such as valency, which influences how it will bond with other elements. For example:
  • Calcium is in Group 2, suggesting it is an alkaline earth metal with a valency of +2.
  • Sulfur is in Group 16, indicating it is a nonmetal with a valency of -2.
These groups provide a visual guide to an element's properties and typical chemical behavior.
Exploring Electron Configuration
Electron configuration reveals the distribution of electrons in an atom's orbitals. Understanding this arrangement helps in predicting and explaining an atom's chemical properties and its tendency to form bonds. The electrons are organized into energy levels or shells.
For calcium, which has 20 electrons, the configuration is \( 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 \). Calcium strives to lose the 2 electrons in its outermost shell (4s) to reach a stable configuration equivalent to the noble gas argon.
Similarly, sulfur, with 16 electrons, has the configuration \( 1s^2 2s^2 2p^6 3s^2 3p^4 \). It needs to acquire 2 additional electrons to achieve the electron configuration of argon, making it energetically favorable to accept electrons.
Essentials of Compound Formation
Compound formation involves the combination of elements to create a new substance with unique properties. Key factors in this process include valency and electrical neutrality.
In the formation of calcium sulfide, calcium donates its two electrons to sulfur, which needs two electrons to fill its valence shell. This electron exchange results in calcium giving up its valence electrons to achieve a noble gas configuration, while sulfur completes its outer shell, forming an ionic bond.
  • This exchange maintains electrical neutrality, as the positive charge of the two lost electrons balances with the negative charge of the two gained electrons.
  • The resulting compound, calcium sulfide (\(\text{CaS}\)), reflects equal numbers of positive and negative charges, ensuring a stable compound formation.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Predict the formula for the compound aluminum nitride made from the elements aluminum and nitrogen, and explain how you made your prediction.

As you move from left to right across a period you add more subatomic particles to the atoms, and yet the atoms become smaller. (a) What subatomic particles are you adding? (b) If you are adding particles, why don't the atoms become larger?

Identify the period 2 element that is described by the ionization data below. \(\mathrm{M}(\mathrm{g}) \rightarrow \mathrm{M}^{+} 1 \mathrm{e}^{-} \quad \mathrm{IE}(1)=1.40 \times 10^{3} \mathrm{~J} / \mathrm{mol}\) \(\mathrm{M}^{+}(\mathrm{g}) \rightarrow \mathrm{M}^{2+} 1 \mathrm{e}^{-} \mathrm{IE}(2)=2.86 \times 10^{3} \mathrm{~J} / \mathrm{mol}\) \(\mathrm{M}^{2+}(\mathrm{g}) \rightarrow \mathrm{M}^{3+} 1 \mathrm{e}^{-} \mathrm{IE}(3)=4.58 \times 10^{3} \mathrm{~J} / \mathrm{mol}\) \(\mathrm{M}^{3+}(\mathrm{g}) \rightarrow \mathrm{M}^{4+} 1 \mathrm{e}^{-} \mathrm{IE}(4)=7.48 \times 10^{3} \mathrm{~J} / \mathrm{mol}\) \(\mathrm{M}^{4+}(\mathrm{g}) \rightarrow \mathrm{M}^{5+} 1 \mathrm{e}^{-} \mathrm{IE}(5)=9.44 \times 10^{3} \mathrm{~J} / \mathrm{mol}\) \(\mathrm{M}^{5+}(\mathrm{g}) \rightarrow \mathrm{M}^{6+} 1 \mathrm{e}^{-} \mathrm{IE}(6)=5.33 \times 10^{4} \mathrm{~J} / \mathrm{mol}\) \(\mathrm{M}^{6+}(\mathrm{g}) \rightarrow \mathrm{M}^{7+} 1 \mathrm{e}^{-} \mathrm{IE}(7)=6.44 \times 10^{4} \mathrm{~J} / \mathrm{mol}\)

If gamma radiation has a wavelength of \(1.00 \times 10^{-12} \mathrm{~m}\), what is the energy of gamma radiation in joules?

The second ionization energy of an atom is the minimum energy required to remove an electron from the \(+1\) cation of the atom, and it is always larger than the first ionization energy. Why is this so? (Hint: Think of atomic electrons as clouds, and each electron must "look" through every other electron cloud in the atom to "see" (feel) the nucleus.)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free