Consider the gas-phase reaction \(3 \mathrm{O}_{2}(g) \rightleftarrows 2
\mathrm{O}_{3}(g) .\) Suppose \(K_{\mathrm{eq}}\) for this
reaction is \(\sim 1\) (it is not, but assume it is for this problem). Suppose
you want pure ozone \(\left(\mathrm{O}_{3}\right)\) that is uncontaminated with
oxygen \(\left(\mathrm{O}_{2}\right)\).
(a) Why can't you simply remove the oxygen from the reaction vessel once the
reaction has come to equilibrium to obtain pure ozone?
(b) In fact, \(K_{\text {eq }}\) for this reaction at room temperature is \(2.5
\times 10^{-29}\). Knowing this, how important would you say Le Châtelier's
principle is for this reaction when it comes to influencing the amount of
ozone present at equilibrium? Explain.