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The value of the equilibrium constant, \(K\), is dependent on which of the following? (There may be more than one answer.) a. the initial concentrations of the reactants b. the initial concentrations of the products c. the temperature of the system d. the nature of the reactants and products Explain.

Short Answer

Expert verified
The value of the equilibrium constant, \(K\), is dependent on the temperature of the system (option c) and the nature of the reactants and products (option d). Initial concentrations of reactants and products do not affect the value of \(K\), but may influence the time it takes for the reaction to reach equilibrium.

Step by step solution

01

Understand chemical equilibrium and the equilibrium constant

Chemical equilibrium is a state in a reversible chemical reaction where the rate of the forward reaction equals the rate of the reverse reaction. In an equilibrium state, the concentrations of reactants and products remain constant. The equilibrium constant, K, is a value that shows the relationship between the concentrations of the reactants and products at equilibrium. It depends on the chemical reaction and temperature.
02

Assess the impact of initial concentrations of reactants (Option a)

The equilibrium constant K is related to the concentrations of reactants and products at equilibrium, not their initial concentrations. The initial concentrations may affect the time it takes for the reaction to reach equilibrium, but they do not affect the value of the equilibrium constant. Hence, option a is incorrect.
03

Assess the impact of initial concentrations of products (Option b)

Similar to the initial concentrations of reactants, the initial concentrations of products may affect the time it takes for the reaction to reach equilibrium, but they do not affect the value of the equilibrium constant. Therefore, option b is also incorrect.
04

Assess the impact of the temperature of the system (Option c)

The equilibrium constant, K, is temperature-dependent. Changes in temperature can affect the equilibrium position and the values of the equilibrium constant. In fact, the Van't Hoff equation relates the change in the equilibrium constant with temperature change. Therefore, option c is correct.
05

Assess the impact of the nature of reactants and products (Option d)

The equilibrium constant, K, depends on the chemical reaction, which, in turn, depends on the nature of the reactants and products involved. Different reactants and products in a chemical reaction can result in different equilibrium constants. Therefore, option d is correct. In conclusion, the value of the equilibrium constant, K, is dependent on the temperature of the system (option c) and the nature of reactants and products (option d).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Equilibrium
When learning about chemical reactions, it's essential to understand the concept of chemical equilibrium. This state is reached in a reversible chemical reaction when the rate of the forward reaction equals that of the reverse reaction, leading to no net change in the concentrations of reactants and products over time. At this point, it appears as though the reaction has stopped, but in reality, it's dynamically balanced; both the forward and reverse reactions are still occurring, but at equal rates.

The key to chemical equilibrium is the equilibrium constant, denoted as 'K'. This value isn't random but rather a precise indicator of the relationship between the reactants and products at this balanced state. When we depict a balanced chemical equation, coefficients become exponents in the mathematical expression of K, providing a formula that can predict reaction behavior under consistent conditions. However, it is crucial to note that 'K' specifically reflects a particular temperature and set of reactants and is not influenced by the initial concentrations of those reactants.
Temperature Dependence
Under the umbrella of chemical equilibrium lies an important characteristic: temperature dependence. Temperature can be imagined as the silent puppeteer of chemical reactions, having the power to shift the position of equilibrium. When the temperature of a system changes, it can favor either the production of reactants or products, thus altering the concentrations at which equilibrium is achieved.

This is important because temperature changes essentially rewrite the rules of the equilibrium condition, which must be recognized by a corresponding change in the equilibrium constant, ‘K’. As temperature increases or decreases, reaction rates adjust, and in turn, ‘K’ shifts to reflect the new balance of reactants and products. Such temperature dependence is not just a small footnote in chemistry; it is a foundational concept that enables chemists to predict and control the outcomes of reactions in various conditions.
Van't Hoff Equation
At the heart of understanding the temperature dependence of the equilibrium constant is the Van't Hoff equation. This relationship is elegantly captured in an equation that expresses how the equilibrium constant varies with temperature. It is formulated as \(\frac{dlnK}{dT} = \frac{\Delta H^o}{R T^2}\), where \(\Delta H^o\) represents the standard enthalpy change of the reaction, 'R' is the universal gas constant, and 'T' is the temperature in Kelvin.

What the Van't Hoff equation tells us is profound: a reaction’s equilibrium constant is not locked in place, but can move with temperature. Moreover, it provides a quantitative way to calculate the direction and magnitude of this shift. For instance, if the reaction in question is exothermic (\(\Delta H^o < 0\)), an increase in temperature will lead to a decrease in 'K', favoring the reactants. Conversely, for an endothermic reaction (\(\Delta H^o > 0\)), 'K' will increase with temperature, favoring the products. Understanding this dynamic can significantly enhance a chemist’s ability to manipulate reactions for desired outcomes.

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Most popular questions from this chapter

You are browsing through the Handbook of Hypothetical Chemistry when you come across a solid that is reported to have a \(K_{\mathrm{sp}}\) value of zero in water at \(25^{\circ} \mathrm{C}\) What does this mean?

What do you suppose happens to the \(K_{\mathrm{sp}}\) value of a solid as the temperature of the solution changes? Consider both increasing and decreasing temperatures, and explain your answer.

Consider an equilibrium mixture consisting of \(\mathrm{H}_{2} \mathrm{O}(g), \mathrm{CO}(g), \mathrm{H}_{2}(g),\) and \(\mathrm{CO}_{2}(g)\) reacting in a closed vessel according to the equation $$\mathrm{H}_{2} \mathrm{O}(g)+\mathrm{CO}(g) \rightleftharpoons \mathrm{H}_{2}(g)+\mathrm{CO}_{2}(g)$$ a. You add more \(\mathrm{H}_{2} \mathrm{O}\) to the flask. How does the new equilibrium concentration of each chemical com- pare to its original equilibrium concentration after equilibrium is reestablished? Justify your answer. b. You add more \(\mathrm{H}_{2}\) to the flask. How does the concentration of each chemical compare to its original concentration after equilibrium is reestablished? Justify your answer.

Consider an equilibrium mixture of four chemicals (A, B, C, and D, all gases) reacting in a closed flask according to the following equation: $$ A+B \rightleftharpoons C+D $$ a. You add more \(A\) to the flask. How does the concentration of each chemical compare to its original concentration after equilibrium is reestablished? Justify your answer. b. You have the original set-up at equilibrium, and add more D to the flask. How does the concentration of each chemical compare to its original concentration after equilibrium is reestablished? Justify your answer.

Consider the reaction \(A+B \rightleftharpoons C+D . A\) friend asks the following: "I know we have been told that if a mixture of \(\mathrm{A}, \mathrm{B}, \mathrm{C},\) and \(\mathrm{D}\) is in equilibrium and more A is added, more \(\mathrm{C}\) and \(\mathrm{D}\) will form. But how can more \(C\) and \(D\) form if we do not add more \(B ? "\) What do you tell your friend?

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