Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Consider the reaction \(A+B \rightleftharpoons C+D . A\) friend asks the following: "I know we have been told that if a mixture of \(\mathrm{A}, \mathrm{B}, \mathrm{C},\) and \(\mathrm{D}\) is in equilibrium and more A is added, more \(\mathrm{C}\) and \(\mathrm{D}\) will form. But how can more \(C\) and \(D\) form if we do not add more \(B ? "\) What do you tell your friend?

Short Answer

Expert verified
When more A is added to the equilibrium mixture without adding more B, the system will adjust to maintain equilibrium according to Le Chatelier's principle. The reaction will shift in the forward direction, consuming the excess A and forming more C and D. Although we do not add more B, the existing B is still able to participate in the reaction, eventually establishing a new equilibrium state with higher concentrations of C and D.

Step by step solution

01

Understand the reaction and equilibrium

In the given reaction, A and B are reactants that combine to form the products C and D: \[A+B \rightleftharpoons C+D\] When this reaction reaches equilibrium, the concentrations of A, B, C, and D become constant, and the forward reaction rate equals the reverse reaction rate.
02

Introduce Le Chatelier's Principle

Le Chatelier's principle states that if a change is made to a system in equilibrium, the system will adjust in such a way to counteract that change and restore the equilibrium. In this case, by adding more A to the system without changing the amount of B, we are altering the equilibrium concentrations of the reactants and products.
03

Explain the effect of adding more A

When we increase the concentration of A without adding more B, according to Le Chatelier's principle, the system will try to counteract this change and restore the equilibrium. To do this, the reaction will shift in the direction that consumes the excess A, which is the forward reaction: \[A+B \longrightarrow C+D\] As a result, more C and D will form to maintain the balance of the reaction.
04

Explain the role of B in the reaction

Even though we are not adding more B, there is still some B present in the equilibrium mixture, which can react with the added A. As more C and D are formed due to the excess A, this will ultimately cause a decrease in the concentration of B. Since the reaction is trying to restore the original equilibrium, it will now shift in the reverse direction to regenerate some of the lost B: \[A+B \longleftarrow C+D\] This back-and-forth shifting will continue until a new equilibrium is established, with higher concentrations of C and D compared to the initial equilibrium state.
05

Sum up the explanation to your friend

In summary, when more A is added to the equilibrium mixture without adding more B, the reaction shifts in the direction that consumes the excess A, which is the forward direction. This leads to the formation of more C and D. Although we do not add more B, the existing B is still able to participate in the reaction, which eventually results in a new equilibrium state with higher concentrations of C and D. This is in accordance with Le Chatelier's principle, which dictates how the system adjusts to maintain equilibrium in response to external changes.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Le Chatelier's Principle
Le Chatelier's Principle is a fundamental concept in chemistry that explains how equilibrium systems respond to changes. It states that if an external change, such as concentration, pressure, or temperature, is applied to a system in equilibrium, the system will adjust in a way to counteract that change and restore equilibrium.

In our example, when more of reactant A is added to the equilibrium mixture of the reaction \( A + B \rightleftharpoons C + D \), the equilibrium is disturbed. Le Chatelier's principle predicts that the system will try to counter this change by forming more products C and D. This attempt to "use up" the extra A results in a shift of the reaction towards the right, or forward direction.

Thus, Le Chatelier's principle helps us understand how equilibrium reacts to changes, ensuring that systems remain balanced despite external influences.
Reaction Rates
Reaction rates refer to the speed at which reactants are converted into products in a chemical reaction. At equilibrium, the rates of the forward and reverse reactions are equal, meaning that the concentrations of reactants and products remain constant.

In the context of our reaction \( A + B \rightleftharpoons C + D \), the equilibrium is characterized by equal forward and reverse reaction rates. When more A is added, the reaction rate for \( A + B \to C + D \) increases to accommodate the higher concentration of A.

This increase in the forward reaction rate temporarily disrupts the balance, producing more products C and D until a new equilibrium is found. The reaction rates adjust accordingly to maintain the new equilibrium where the forward and reverse reactions are again equal in rate.
Concentration Changes
Concentration changes are crucial in understanding how equilibrium systems react and adjust. In the scenario where more A is added to the mixture, the concentration of A increases, leading to a shift in equilibrium.

Even though B is not added, its existing concentration is still sufficient to react with the additional A. The increase in A's concentration shifts the reaction toward the production of more C and D. Because equilibrium systems tend to balance reactant and product levels, the system "forces" the reaction to move forward to decrease the surplus of A.

As the reaction progresses, both C and D concentrations increase while B concentration decreases, reflecting the consumption of B. Eventually, equilibrium is re-established with new concentration levels.
Equilibrium Systems
Equilibrium systems serve as the basis for understanding how chemical reactions maintain balance. In a reversible reaction like \( A + B \rightleftharpoons C + D \), equilibrium is the state where the formation of reactants and products occurs at the same rate.

Equilibrium systems are dynamic. Even though concentrations of reactants and products remain steady, the individual molecules continuously convert between states. When external changes are imposed, such as adding more A, the equilibrium adjusts dynamically.

This dynamic adjustment reflects the system's tendency to counteract changes, whether they're in concentration, pressure, or temperature. The "goal" is always to return to a state of balance, even if the levels of specific substances change to achieve it.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Equilibrium is microscopically dynamic but macroscopically static. Explain what this means.

Consider an equilibrium mixture of four chemicals (A, B, C, and D, all gases) reacting in a closed flask according to the following equation: $$ A+B \rightleftharpoons C+D $$ a. You add more \(A\) to the flask. How does the concentration of each chemical compare to its original concentration after equilibrium is reestablished? Justify your answer. b. You have the original set-up at equilibrium, and add more D to the flask. How does the concentration of each chemical compare to its original concentration after equilibrium is reestablished? Justify your answer.

Explain why the development of a vapor pressure above a liquid in a closed container represents an equilibrium. What are the opposing processes? How do we recognize when the system has reached a state of equilibrium.

Consider an equilibrium mixture consisting of \(\mathrm{H}_{2} \mathrm{O}(g), \mathrm{CO}(g), \mathrm{H}_{2}(g),\) and \(\mathrm{CO}_{2}(g)\) reacting in a closed vessel according to the equation $$\mathrm{H}_{2} \mathrm{O}(g)+\mathrm{CO}(g) \rightleftharpoons \mathrm{H}_{2}(g)+\mathrm{CO}_{2}(g)$$ a. You add more \(\mathrm{H}_{2} \mathrm{O}\) to the flask. How does the new equilibrium concentration of each chemical com- pare to its original equilibrium concentration after equilibrium is reestablished? Justify your answer. b. You add more \(\mathrm{H}_{2}\) to the flask. How does the concentration of each chemical compare to its original concentration after equilibrium is reestablished? Justify your answer.

The value of the equilibrium constant, \(K\), is dependent on which of the following? (There may be more than one answer.) a. the initial concentrations of the reactants b. the initial concentrations of the products c. the temperature of the system d. the nature of the reactants and products Explain.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free