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Which of the following solutions contains the great est number of particles? Support your answer. a. \(400.0 \mathrm{mL}\) of \(0.10 \mathrm{M}\) sodium chloride b. \(300.0 \mathrm{mL}\) of \(0.10 \mathrm{M}\) calcium chloride c. \(200.0 \mathrm{mL}\) of \(0.10 \mathrm{M}\) iron(III) chloride d. \(200.0 \mathrm{mL}\) of \(0.10 \mathrm{M}\) potassium bromide e. \(800.0 \mathrm{mL}\) of \(0.10 \mathrm{M}\) sucrose (table sugar)

Short Answer

Expert verified
The solution with the greatest number of particles is b. \(300.0 \mathrm{mL}\) of \(0.10 \mathrm{M}\) calcium chloride containing 0.09 moles of particles.

Step by step solution

01

Identify the number of ions produced by each solute when dissolved in water

First, we need to determine how many ions each solute produces: a. Sodium chloride (NaCl) dissociates into 2 ions: Na+ + Cl- b. Calcium chloride (CaCl2) dissociates into 3 ions: Ca2+ + 2Cl- c. Iron(III) chloride (FeCl3) dissociates into 4 ions: Fe3+ + 3Cl- d. Potassium bromide (KBr) dissociates into 2 ions: K+ + Br- e. Sucrose (C12H22O11) does not dissociate into ions, as it is a non-electrolyte.
02

Calculate moles of particles for each solution

Now, we will calculate the moles of particles in each solution by using the formula: moles of particles = volume (L) * molarity (M) * (number of ions produced by the solute) a. Moles of particles in NaCl solution = (400 mL / 1000) * 0.10 M * 2 = 0.08 moles b. Moles of particles in CaCl2 solution = (300 mL / 1000) * 0.10 M * 3 = 0.09 moles c. Moles of particles in FeCl3 solution = (200 mL / 1000) * 0.10 M * 4 = 0.08 moles d. Moles of particles in KBr solution = (200 mL / 1000) * 0.10 M * 2 = 0.04 moles e. Moles of particles in sucrose solution = (800 mL / 1000) * 0.10 M * 1 = 0.08 moles
03

Compare the moles of particles in each solution

Now that we've calculated the moles of particles in each solution, compare the values to find the greatest quantity: a. 0.08 moles b. 0.09 moles c. 0.08 moles d. 0.04 moles e. 0.08 moles
04

Identify the solution with the greatest number of particles

The solution with the greatest number of particles is b. \(300.0 \mathrm{mL}\) of \(0.10 \mathrm{M}\) calcium chloride containing 0.09 moles of particles.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molarity
Molarity is a key concept in chemistry that refers to the concentration of a solution. It describes the number of moles of a solute that are dissolved in one liter of solution. The formula to calculate molarity is given by:
\[ M = \frac{n}{V} \]where
  • \( M \) represents molarity,
  • \( n \) is the number of moles of solute, and
  • \( V \) is the volume of the solution in liters.
Understanding molarity is essential for determining how substances interact in solutions. In the given exercise, all solutions have the same molarity of 0.10 M, which means each liter of these solutions contains 0.10 moles of their respective compounds.
The volume of the solutions varies, leading to different amounts of particles when we consider ionic compounds that dissociate into multiple ions.
Ionic Compounds
Ionic compounds consist of positively charged ions (cations) and negatively charged ions (anions) bonded together through ionic bonds. They typically dissolve in water, dissociating into their constituent ions which allow them to conduct electricity in solution.
In our exercise context, examples of ionic compounds include sodium chloride (NaCl), calcium chloride (CaCl2), iron(III) chloride (FeCl3), and potassium bromide (KBr). When these compounds dissolve in water, they separate into their respective ions:
  • NaCl dissociates into Na+ and Cl-, producing 2 ions.
  • CaCl2 dissociates into Ca2+ and 2 Cl-, producing 3 ions.
  • FeCl3 dissociates into Fe3+ and 3 Cl-, producing 4 ions.
  • KBr dissociates into K+ and Br-, producing 2 ions.
Each type of ionic compound can impact the solution's total particle count differently due to their unique dissociation behavior.
Dissociation
Dissociation refers to the process by which an ionic compound separates into individual ions when dissolved in a solvent like water. This is a fundamental process that affects the way solutions conduct electricity and the number of particles present in a solution.
For example, calcium chloride (CaCl2) dissociates into three ions: one Ca2+ ion and two Cl- ions. This means that when one mole of calcium chloride is dissolved, it produces three moles of ions.
In the exercise, comparing the resulting ions from different solutions helps in determining which one contains the most total particles. Although all the solutions have the same molarity, those that dissociate into more ions lead to higher numbers of particles in the solution.
Mole Concept
The mole concept is central to understanding and solving quantitative problems in stoichiometry. It provides a bridge between the atomic world and the macroscopic amounts we work with in the lab. A mole is a unit that quantifies the amount of substance, typically containing Avogadro's number of entities, which is approximately \(6.022 \times 10^{23}\) particles.
Using the mole concept allows chemists to count entities at the atomic level conveniently. When calculating the moles of particles in solutions, as demonstrated in the exercise, this concept is indispensable.
  • We can determine the number of moles through the formula: \[ \text{moles} = \text{volume (L)} \times \text{molarity (M)} \times \text{number of ions} \]
In our example, calcium chloride, when dissolved, produces more ions per mole compared to sucrose, thereby leading to a higher number of moles of particles despite having the same molarity and volume adjustments. Understanding this principle allows accurate predictions of particle amounts in chemical reactions and processes.

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Most popular questions from this chapter

Consider separate aqueous solutions of \(\mathrm{HCl}\) and \(\mathrm{H}_{2} \mathrm{SO}_{4}\) with the same concentrations in terms of molarity. You wish to neutralize an aqueous solution of NaOH. For which acid solution would you need to add more volume (in \(\mathrm{mL}\) ) to neutralize the base? a. The HCl solution. b. The \(\mathrm{H}_{2} \mathrm{SO}_{4}\) solution. c. You need to know the acid concentrations to answer this question. d. You need to know the volume and concentration of the NaOH solution to answer this question. e. \(\mathrm{c}\) and \(\mathrm{d}\) Explain your answer.

Consider a sugar solution (solution A) with concentration \(x .\) You pour one- third of this solution into a beaker, and add an equivalent volume of water (solution B). a. What is the ratio of sugar in solutions \(A\) and \(B ?\) b. Compare the volumes of solutions \(A\) and \(B\). c. What is the ratio of the concentrations of sugar in solutions A and B?

Can one solution have a greater concentration than another in terms of weight percent, but a lower concentration in terms of molarity? Explain.

Explain why the formula \(M_{1} V_{1}=M_{2} V_{2}\) works when solving dilution problems.

As with all quantitative problems in chemistry, make sure not to get "lost in the math." In particular, work on visualizing solutions at a molecular level. For example, consider the following. You have two separate beakers with aqueous solutions, one with 4 "units" of potassium sulfate and one with 3 "units" of barium nitrate. a. Draw molecular-level diagrams of both solutions. b. Draw a molecular-level diagram of the mixture of the two solutions before a reaction has taken place. c. Draw a molecular-level diagram of the product and solution formed after the reaction has taken place.

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