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For each of the following reactions, give the balanced cquation for the reaction and state the meaning of the equation in terms of numbers of individual molecules and in terms of moles of molccules. a. \(\mathrm{UO}_{2}(s)+\mathrm{HF}(a q) \rightarrow \mathrm{UF}_{4}(a q)+\mathrm{H}_{2} \mathrm{O}(l)\) b. \(\mathrm{NaC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}(a q)+\mathrm{H}_{2} \mathrm{SO}_{4}(a q) \rightarrow \mathrm{Na}_{2} \mathrm{SO}_{4}(a q)+\mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}(a q)\) c. \(\mathrm{Mg}(s)+\mathrm{HCl}(a q) \rightarrow \mathrm{MgCl}_{2}(a q)+\mathrm{H}_{2}(g)\) d. \(\mathrm{B}_{2} \mathrm{O}_{3}(s)+\mathrm{H}_{2} \mathrm{O}(l) \rightarrow \mathrm{B}(\mathrm{OH})_{3}(a q)\)

Short Answer

Expert verified
a. The balanced equation is: \( \mathrm{UO}_{2}(s) + 4\mathrm{HF}(aq) \rightarrow \mathrm{UF}_{4}(aq) + 2\mathrm{H}_{2}\mathrm{O}(l) \). It means that one molecule of \(\mathrm{UO}_{2}\) reacts with four molecules of \(\mathrm{HF}\) to produce one molecule of \(\mathrm{UF}_{4}\) and two molecules of \(\mathrm{H}_{2}\mathrm{O}\). In terms of moles, one mole of \(\mathrm{UO}_{2}\) reacts with four moles of \(\mathrm{HF}\) to produce one mole of \(\mathrm{UF}_{4}\) and two moles of \(\mathrm{H}_{2}\mathrm{O}\). b. The balanced equation is: \( 2\mathrm{NaC}_{2}\mathrm{H}_{3}\mathrm{O}_{2}(aq) + \mathrm{H}_{2}\mathrm{SO}_{4}(aq) \rightarrow \mathrm{Na}_{2}\mathrm{SO}_{4}(aq) + 2\mathrm{HC}_{2}\mathrm{H}_{3}\mathrm{O}_{2}(aq) \). It means that two molecules of \(\mathrm{NaC}_{2}\mathrm{H}_{3}\mathrm{O}_{2}\) react with one molecule of \(\mathrm{H}_{2}\mathrm{SO}_{4}\) to produce one molecule of \(\mathrm{Na}_{2}\mathrm{SO}_{4}\) and two molecules of \(\mathrm{HC}_{2}\mathrm{H}_{3}\mathrm{O}_{2}\). In terms of moles, two moles of \(\mathrm{NaC}_{2}\mathrm{H}_{3}\mathrm{O}_{2}\) react with one mole of \(\mathrm{H}_{2}\mathrm{SO}_{4}\) to produce one mole of \(\mathrm{Na}_{2}\mathrm{SO}_{4}\) and two moles of \(\mathrm{HC}_{2}\mathrm{H}_{3}\mathrm{O}_{2}\). c. The balanced equation is: \( \mathrm{Mg}(s) + 2\mathrm{HCl}(aq) \rightarrow \mathrm{MgCl}_{2}(aq) + \mathrm{H}_{2}(g) \). It means that one molecule of \(\mathrm{Mg}\) reacts with two molecules of \(\mathrm{HCl}\) to produce one molecule of \(\mathrm{MgCl}_{2}\) and one molecule of \(\mathrm{H}_{2}\). In terms of moles, one mole of \(\mathrm{Mg}\) reacts with two moles of \(\mathrm{HCl}\) to produce one mole of \(\mathrm{MgCl}_{2}\) and one mole of \(\mathrm{H}_{2}\). d. The balanced equation is: \( \mathrm{B}_{2}\mathrm{O}_{3}(s) + 3\mathrm{H}_{2}\mathrm{O}(l) \rightarrow 2\mathrm{B}(\mathrm{OH})_{3}(aq) \). It means that one molecule of \(\mathrm{B}_{2}\mathrm{O}_{3}\) reacts with three molecules of \(\mathrm{H}_{2}\mathrm{O}\) to produce two molecules of \(\mathrm{B}(\mathrm{OH})_{3}\). In terms of moles, one mole of \(\mathrm{B}_{2}\mathrm{O}_{3}\) reacts with three moles of \(\mathrm{H}_{2}\mathrm{O}\) to produce two moles of \(\mathrm{B}(\mathrm{OH})_{3}\).

Step by step solution

01

1. Balance the equation

To balance the chemical equation for the reaction between \(\mathrm{UO}_{2}(s)\) and \(\mathrm{HF}(aq)\), we need to adjust the coefficients as follows: \[ \mathrm{UO}_{2}(s) + 4\mathrm{HF}(aq) \rightarrow \mathrm{UF}_{4}(aq) + 2\mathrm{H}_{2}\mathrm{O}(l) \]
02

2. Meaning in terms of individual molecules

The balanced equation means that one molecule of solid uranium dioxide reacts with four molecules of aqueous hydrogen fluoride to produce one molecule of aqueous uranium tetrafluoride and two molecules of liquid water.
03

3. Meaning in terms of moles of molecules

The balanced equation means that one mole of solid uranium dioxide reacts with four moles of aqueous hydrogen fluoride to produce one mole of aqueous uranium tetrafluoride and two moles of liquid water. b.
04

1. Balance the equation

To balance the chemical equation for the reaction between \(\mathrm{NaC}_{2}\mathrm{H}_{3}\mathrm{O}_{2}(aq)\) and \(\mathrm{H}_{2}\mathrm{SO}_{4}(aq)\), we need to adjust the coefficients as follows: \[ 2\mathrm{NaC}_{2}\mathrm{H}_{3}\mathrm{O}_{2}(aq) + \mathrm{H}_{2}\mathrm{SO}_{4}(aq) \rightarrow \mathrm{Na}_{2}\mathrm{SO}_{4}(aq) + 2\mathrm{HC}_{2}\mathrm{H}_{3}\mathrm{O}_{2}(aq) \]
05

2. Meaning in terms of individual molecules

The balanced equation means that two molecules of aqueous sodium acetate react with one molecule of aqueous sulfuric acid to produce one molecule of aqueous sodium sulfate and two molecules of aqueous acetic acid.
06

3. Meaning in terms of moles of molecules

The balanced equation means that two moles of aqueous sodium acetate react with one mole of aqueous sulfuric acid to produce one mole of aqueous sodium sulfate and two moles of aqueous acetic acid. c.
07

1. Balance the equation

To balance the chemical equation for the reaction between \(\mathrm{Mg}(s)\) and \(\mathrm{HCl}(aq)\), we need to adjust the coefficients as follows: \[ \mathrm{Mg}(s) + 2\mathrm{HCl}(aq) \rightarrow \mathrm{MgCl}_{2}(aq) + \mathrm{H}_{2}(g) \]
08

2. Meaning in terms of individual molecules

The balanced equation means that one molecule of solid magnesium reacts with two molecules of aqueous hydrogen chloride to produce one molecule of aqueous magnesium chloride and one molecule of gaseous hydrogen.
09

3. Meaning in terms of moles of molecules

The balanced equation means that one mole of solid magnesium reacts with two moles of aqueous hydrogen chloride to produce one mole of aqueous magnesium chloride and one mole of gaseous hydrogen. d.
10

1. Balance the equation

To balance the chemical equation for the reaction between \(\mathrm{B}_{2}\mathrm{O}_{3}(s)\) and \(\mathrm{H}_{2}\mathrm{O}(l)\), we need to adjust the coefficients as follows: \[ \mathrm{B}_{2}\mathrm{O}_{3}(s) + 3\mathrm{H}_{2}\mathrm{O}(l) \rightarrow 2\mathrm{B}(\mathrm{OH})_{3}(aq) \]
11

2. Meaning in terms of individual molecules

The balanced equation means that one molecule of solid boron oxide reacts with three molecules of liquid water to produce two molecules of aqueous boron hydroxide.
12

3. Meaning in terms of moles of molecules

The balanced equation means that one mole of solid boron oxide reacts with three moles of liquid water to produce two moles of aqueous boron hydroxide.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Balancing Chemical Equations
When it comes to chemical reactions, one of the fundamental tasks is balancing the chemical equation. This involves ensuring that the number of atoms of each element on the reactant side is equal to the number on the product side. This is crucial because it complies with the Law of Conservation of Mass, which states that matter cannot be created or destroyed in a chemical reaction. To balance a chemical equation:
  • First, write down the unbalanced equation.
  • Count the number of atoms for each element on both sides.
  • Adjust the coefficients in front of the chemical formulas to balance the atoms for each element.
Remember: Never change the subscripts within a chemical formula, as doing so changes the compound itself. For example, when balancing \( \mathrm{UO}_{2} + \mathrm{HF} \rightarrow \mathrm{UF}_{4} + \mathrm{H}_{2}\mathrm{O} \), we adjust to obtain: \[ \mathrm{UO}_{2} + 4\mathrm{HF} \rightarrow \mathrm{UF}_{4} + 2\mathrm{H}_{2}\mathrm{O} \]This means one uranium atom and four hydrogen fluoride molecules react to give one uranium tetrafluoride molecule and two water molecules.
Moles and Molecules
Understanding moles and molecules is vital in chemistry, especially when interpreting chemical equations. A mole is a basic unit in chemistry that is used to describe an amount of substance. It is equivalent to Avogadro's number, which is \(6.022 \times 10^{23}\) particles per mole.
The idea behind moles allows chemists to count atoms, molecules, and ions in a given mass of a substance in a practical and manageable way. For instance, in the reaction:\[ \mathrm{Mg}(s) + 2\mathrm{HCl}(aq) \rightarrow \mathrm{MgCl}_{2}(aq) + \mathrm{H}_{2}(g) \],
The balanced equation can be interpreted in terms of moles as follows:
  • One mole of magnesium (\( \mathrm{Mg} \)) reacts with two moles of hydrochloric acid (\( \mathrm{HCl} \)).
  • This reaction produces one mole of magnesium chloride (\( \mathrm{MgCl}_{2} \)) and one mole of hydrogen gas (\( \mathrm{H}_{2} \)).
The concept of moles connects the macroscopic world to the molecular level, allowing chemists to make predictions about amounts of substances consumed and produced in reactions.
Stoichiometry
Stoichiometry is the area of chemistry that involves calculating the quantities of reactants and products in chemical reactions. It uses balanced chemical equations and the mole concept to relate different substances in a reaction.
In stoichiometry, you often perform calculations to determine:
  • How much product can be produced from given reactants.
  • How much of a reactant is needed to produce a desired amount of product.
  • Limiting reactants that may stop a reaction from proceeding.
These calculations begin by identifying the ratios of reactants and products as described in a balanced equation. For instance, in the reaction:\[ 2\mathrm{NaC}_{2}\mathrm{H}_{3}\mathrm{O}_{2} + \mathrm{H}_{2}\mathrm{SO}_{4} \rightarrow \mathrm{Na}_{2}\mathrm{SO}_{4} + 2\mathrm{HC}_{2}\mathrm{H}_{3}\mathrm{O}_{2} \],
The stoichiometric coefficients tell us that two moles of sodium acetate react with one mole of sulfuric acid to produce one mole of sodium sulfate and two moles of acetic acid. This molar relationship allows for precise calculations between reactants and products, ensuring that chemists can predict outcomes accurately in both lab and industrial scenarios.

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Most popular questions from this chapter

For each of the following balanced chemical cquations, calculate how many moles of product(s) would be produced if 0.500 mole of the first reactant were to react completely. a. \(\mathrm{CO}_{2}(g)+4 \mathrm{H}_{2}(g) \rightarrow \mathrm{CH}_{4}(g)+2 \mathrm{H}_{2} \mathrm{O}(l)\) b. \(\mathrm{BaCl}_{2}(a q)+2 \mathrm{AgNO}_{3}(a q) \rightarrow 2 \mathrm{AgCl}(s)+\mathrm{Ba}\left(\mathrm{NO}_{3}\right)_{2}(a q)\) c. \(\mathrm{C}_{3} \mathrm{H}_{8}(g)+5 \mathrm{O}_{2}(g) \rightarrow 4 \mathrm{H}_{2} \mathrm{O}(l)+3 \mathrm{CO}_{2}(g)\) d. \(3 \mathrm{H}_{2} \mathrm{SO}_{4}(a q)+2 \mathrm{Fe}(s) \rightarrow \mathrm{Fe}_{2}\left(\mathrm{SO}_{4}\right)_{3}(a q)+3 \mathrm{H}_{2}(g)\)

Hydrazine, \(\mathrm{N}_{2} \mathrm{H}_{4}\), cmits a large quantity of energy when it reacts with oxygen, which has led to hydrazine's use as a fuel for rockets: $$ \mathrm{N}_{2} \mathrm{H}_{4}(I)+\mathrm{O}_{2}(g) \rightarrow \mathrm{N}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(g) $$ How many moles of each of the gaseous products are produced when \(20.0 \mathrm{~g}\) of pure hydrazine is ignited in the presence of \(20.0 \mathrm{~g}\) of pure oxygen? How many grams of each product are produced?

Solid copper can be produced by passing gaseous ammonia over solid copper(II) oxide at high temperatures. The other products of the reaction are nitrogen gas and water vapor. The balanced equation for this reaction is: $$ 2 \mathrm{NH}_{3}(g)+3 \mathrm{CuO}(s) \rightarrow \mathrm{N}_{2}(g)+3 \mathrm{Cu}(s)+3 \mathrm{H}_{2} \mathrm{O}(g) $$ What is the theoretical yield of solid copper that should form when \(18.1 \mathrm{~g}\) of \(\mathrm{NH}_{3}\) is reacted with \(90.4 \mathrm{~g}\) of \(\mathrm{CuO}\) ? If only \(45.3 \mathrm{~g}\) of copper is actually collected, what is the percent yield?

Which of the following statements is(are) true? a. A balanced equation relates the numbers of molecules of reactants and products (or numbers of moles of reactants and products). b. To convert between moles of reactants and moles of products, we use mole ratios derived from the balanced equation. c. Often reactants are not mixed in stoichiometric quantities (they do not "run out" at the same time). In that case, we must use the limiting reactant to calculate the amounts of products formed. d. When a chemical reaction occurs, it must follow the law of conservation of mass.

When elemental copper is placed in a solution of silver nitrate, the following oxidationreduction reaction takes place, forming clemental silver: $$ \mathrm{Cu}(s)+2 \mathrm{AgNO}_{3}(a q) \rightarrow \mathrm{Cu}\left(\mathrm{NO}_{3}\right)_{2}(a q)+2 \mathrm{Ag}(s) $$ What mass of copper is required to remove all the silver from a silver nitrate solution containing \(1.95 \mathrm{mg}\) of silver nitrate?

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