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What does it mean to say that the balanced chemical equation for a reaction describes the stoichiometry of the reaction?

Short Answer

Expert verified
A balanced chemical equation describes the stoichiometry of a reaction because it provides the precise ratio in which reactants combine to form products, ensuring the conservation of mass. The coefficients in a balanced equation represent the number of moles of each substance involved in the reaction, indicating the quantitative relationships or ratios between the amounts of substances participating in the reaction. For example, in the equation \(2 H_2 + O_2 \rightarrow 2 H_2O\), 2 moles of hydrogen react with 1 mole of oxygen to produce 2 moles of water, representing the stoichiometry of the reaction.

Step by step solution

01

Definition of a balanced chemical equation

A balanced chemical equation is a representation of a chemical reaction in which the number of atoms of each element on the reactant side is equal to the number of atoms of that element on the product side. This is achieved by adjusting the coefficients (the numbers in front of the chemical formula) in the reaction.
02

Definition of stoichiometry

Stoichiometry is the study of the quantitative relationships or ratios between the amounts of substances participating in a chemical reaction. It's based on the law of conservation of mass, which states that matter cannot be created or destroyed, only rearranged.
03

Relationship between a balanced chemical equation and stoichiometry

A balanced chemical equation describes the stoichiometry of a reaction because it provides the precise ratio in which reactants combine to form products. The coefficients in a balanced equation represent the number of moles of each substance involved in the reaction. For example, consider the balanced chemical equation for a reaction between hydrogen and oxygen: \[2 H_2 + O_2 \rightarrow 2 H_2O\] Here, the coefficients tell us that 2 moles of hydrogen (H₂) react with 1 mole of oxygen (O₂) to produce 2 moles of water (H₂O). This numerical relationship represents the stoichiometry of the reaction, and it helps chemists to understand how much of each substance is required for the reaction to occur as well as the amount of product(s) formed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stoichiometry
Stoichiometry is a fundamental concept in chemistry that focuses on the quantitative aspects of chemical reactions. It revolves around the precise measurement of reactants and products involved in a chemical reaction. Understanding stoichiometry allows chemists to compute how much of a substance is needed or produced in a reaction.

A balanced chemical equation lays the foundation for stoichiometry by showing the exact mole ratios of ingredients (reactants) transforming into end products. This is very much like following a recipe for a cake, where exact amounts of flour, sugar, and eggs are determined to yield a certain size of cake.

Key points to remember about stoichiometry include:
  • Relies on the law of conservation of mass, ensuring mass remains constant in a reaction.
  • Uses coefficients from the balanced equations to guide calculations.
  • Helps predict the amounts of substances consumed and produced.
By using stoichiometry, scientists can efficiently plan chemical reactions and ensure maximum utility of materials, helping industries economize and reduce waste.
Law of Conservation of Mass
The law of conservation of mass is a principle stating that mass cannot be created or destroyed in a chemical reaction. It underpins the process of balancing chemical equations.

This concept was first formulated by Antoine Lavoisier in the 18th century and it ensures that the mass of the reactants equals the mass of the products. Balance is crucial to this law, as it respects the idea that atoms are simply rearranged during reactions.

A typical example when considering this law is the combination of hydrogen and oxygen to form water. Despite the change in substance type—from gases to liquid—the total mass stays constant. The implications of this law are profound, as they:
  • Ensure our equations reflect physical reality.
  • Help predict the outcome of reactions precisely.
  • Confirm that chemical equations need correcting until the same number of each type of atom appears on both sides.
Without the law of conservation of mass, calculations based on chemical reactions would be unreliable and unpredictable.
Chemical Reaction Coefficients
Coefficients in a chemical reaction are numbers that appear before the formulas of reactants and products. They play a vital role in balancing chemical equations and representing stoichiometric relationships.

These coefficients indicate the proportions or amounts of each reactant and product involved in the reaction. They are not randomly chosen and hold significant importance in defining stoichiometric calculations for any given chemical equation.

For instance, in the equation \(2 H_2 + O_2 \rightarrow 2 H_2O\), the coefficients 2 and 1 represent mole ratios. These coefficients imply that two moles of hydrogen react with one mole of oxygen to produce two moles of water.
  • Ensure that the equation adheres to the law of conservation of mass.
  • Define the exact proportions for substances undergoing transformation.
  • Assist in determining the limiting reactant and theoretical yields in reactions.
Chemical reaction coefficients bridge the gap between theoretical chemistry and practical application, facilitating accurate predictions and managing expectations in laboratory settings.

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Most popular questions from this chapter

For each of the following unbalanced equations, calculate how many moles of the second reactant would be required to react completely with 0.413 moles of the first reactant. a. \(\operatorname{Co}(s)+\mathbf{F}_{2}(g) \rightarrow \operatorname{CoF}_{3}(s)\) b. \(\mathrm{Al}(s)+\mathrm{H}_{2} \mathrm{SO}_{4}(a q) \rightarrow \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}(a q)+\mathrm{H}_{2}(g)\) c. \(\mathrm{K}(s)+\mathrm{H}_{2} \mathrm{O}(l) \rightarrow \mathrm{KOH}(a q)+\mathrm{H}_{2}(g)\) d. \(\mathrm{Cu}(s)+\mathrm{O}_{2}(g) \rightarrow \mathrm{Cu}_{2} \mathrm{O}(s)\)

For cach of the following reactions, give the balanced cquation for the reaction and state the meaning of the equation in terms of the numbers of individual molecules and in terms of moles of molecules. a. \(\mathrm{PCl}_{3}(l)+\mathrm{H}_{2} \mathrm{O}(l) \rightarrow \mathrm{H}_{3} \mathrm{PO}_{3}(a q)+\mathrm{HCl}(g)\) b. \(\mathrm{XeF}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l) \rightarrow \mathrm{Xe}(g)+\mathrm{HF}(g)+\mathrm{O}_{2}(g)\) c. \(\mathrm{S}(s)+\mathrm{HNO}_{3}(a q) \rightarrow \mathrm{H}_{2} \mathrm{SO}_{4}(a q)+\mathrm{H}_{2} \mathrm{O}(l)+\mathrm{NO}_{2}(g)\) d. \(\mathrm{NaHSO}_{3}(s) \rightarrow \mathrm{Na}_{2} \mathrm{SO}_{3}(s)+\mathrm{SO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l)\)

Using the average atomic masses given inside the front cover of this book, calculate the mass in grams of each of the following samples. a. 2.17 moles of germanium, Ge b. \(4.24 \mathrm{mmol}\) of lead(II) chloride ( \(1 \mathrm{mmol}=1 / 1000 \mathrm{~mol}\) ) c. 0.0971 mole of ammonia, \(\mathrm{NH}_{3}\) d. \(4.26 \times 10^{3}\) moles of hexane, \(\mathrm{C}_{6} \mathrm{H}_{14}\) e. 1.71 moles of iodine monochloride, \(1 \mathrm{C}=\)

For each of the following balanced chemical cquations, calculate how many moles of product(s) would be produced if 0.500 mole of the first reactant were to react completely. a. \(\mathrm{CO}_{2}(g)+4 \mathrm{H}_{2}(g) \rightarrow \mathrm{CH}_{4}(g)+2 \mathrm{H}_{2} \mathrm{O}(l)\) b. \(\mathrm{BaCl}_{2}(a q)+2 \mathrm{AgNO}_{3}(a q) \rightarrow 2 \mathrm{AgCl}(s)+\mathrm{Ba}\left(\mathrm{NO}_{3}\right)_{2}(a q)\) c. \(\mathrm{C}_{3} \mathrm{H}_{8}(g)+5 \mathrm{O}_{2}(g) \rightarrow 4 \mathrm{H}_{2} \mathrm{O}(l)+3 \mathrm{CO}_{2}(g)\) d. \(3 \mathrm{H}_{2} \mathrm{SO}_{4}(a q)+2 \mathrm{Fe}(s) \rightarrow \mathrm{Fe}_{2}\left(\mathrm{SO}_{4}\right)_{3}(a q)+3 \mathrm{H}_{2}(g)\)

For each of the following unbalanced reactions, suppose exactly 5.00 moles of each reactant are taken. Determine which reactant is limiting, and also determine what mass of the excess reagent will remain after the limiting reactant is consumed. For cach reaction, solve the problem three ways: i. Set up and use Before-Change-After (BCA) tables. ii. Compare the moles of reactants to see which runs out first. iii. Consider the amounts of products that can be formed by completcly consuming cach reactant. a. \(\mathrm{CaC}_{2}(s)+\mathrm{H}_{2} \mathrm{O}(l) \rightarrow \mathrm{Ca}(\mathrm{OH})_{2}(s)+\mathrm{C}_{2} \mathrm{H}_{2}(g)\) b. \(\operatorname{AgNO}_{3}(a q)+\mathbf{A l}(s) \rightarrow \mathbf{A}_{\mathbf{g}}(s)+\mathbf{A l}\left(\mathrm{NO}_{3}\right)_{3}(a q)\)

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