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Write the balanced chemical equation for the complete combustion of heptene, \(\mathrm{C}_{7} \mathrm{H}_{14}\). In combustion, heptene reacts with oxygen to produce carbon dioxide and water. What is the mole ratio that would enable you to calculate the number of moles of oxygen needed to react exactly with a given number of moles of heptene? What mole ratios would you use to calculate how many moles of each product form from a given number of moles of heptene?

Short Answer

Expert verified
The balanced chemical equation for the complete combustion of heptene (\(\mathrm{C}_{7} \mathrm{H}_{14}\)) is: \[\mathrm{C}_{7} \mathrm{H}_{14} + 14 \mathrm{O}_{2} \rightarrow 7 \mathrm{CO}_{2} + 7 \mathrm{H}_{2}\mathrm{O}\] The mole ratio of oxygen to heptene is 14:1, meaning 14 moles of \(\mathrm{O}_{2}\) are needed for each mole of \(\mathrm{C}_{7} \mathrm{H}_{14}\). Furthermore, the mole ratios for the products are 7:1 for both \(\mathrm{CO}_{2}\) and \(\mathrm{H}_{2}\mathrm{O}\), meaning 7 moles of \(\mathrm{CO}_{2}\) and 7 moles of \(\mathrm{H}_{2}\mathrm{O}\) are produced for each mole of \(\mathrm{C}_{7} \mathrm{H}_{14}\).

Step by step solution

01

Write the unbalanced chemical equation

We first write the unbalanced chemical equation for the combustion of heptene: C7H14 + O2 → CO2 + H2O
02

Balance the chemical equation

In order to balance the equation, we need to adjust the coefficients of each compound so that the number of atoms of each element is balanced on both sides of the equation. C7H14 + O2 → 7CO2 + 7H2O Now, we have 7 carbon atoms (from 7CO2) and 14 hydrogen atoms (from 7H2O) on the product side, but the number of oxygen atoms is not balanced yet. Since we have 14 oxygen atoms from CO2 and another 14 from H2O, we need 28 oxygen atoms on the reactant side. So our balanced equation becomes: C7H14 + 14O2 → 7CO2 + 7H2O
03

Find the mole ratio of oxygen to heptene

From the balanced equation, we can see that 1 mole of heptene (C7H14) reacts with 14 moles of oxygen (O2). The mole ratio of oxygen to heptene is: 14O2 : 1C7H14
04

Find the mole ratios of CO2 and H2O to heptene

We can also see the mole ratios of the products, CO2 and H2O, to heptene from the balanced equation: For CO2: 7CO2 : 1C7H14 For H2O: 7H2O : 1C7H14 To summarize the mole ratios, we have: - 14 moles of O2 are needed for each mole of C7H14. - 7 moles of CO2 are produced for each mole of C7H14. - 7 moles of H2O are produced for each mole of C7H14. These mole ratios can be used to calculate the amount of reactants and products in any given reaction involving the combustion of heptene.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combustion Reaction
When we talk about a combustion reaction, we are referring to a chemical process where a substance (typically a hydrocarbon) reacts with oxygen to produce heat and light. This type of reaction is exothermic, meaning it releases energy. In the specific case of heptene, which is a hydrocarbon with the formula \(\mathrm{C}_{7} \mathrm{H}_{14}\), its combustion involves oxygen (\(\mathrm{O}_2\)) to produce carbon dioxide (\(\mathrm{CO}_2\)) and water (\(\mathrm{H}_2\mathrm{O}\)).

The balanced equation from the example provides a clear picture of the reaction:\[\mathrm{C}_7\mathrm{H}_{14} + 14\mathrm{O}_2 \rightarrow 7\mathrm{CO}_2 + 7\mathrm{H}_2\mathrm{O}\]
This means that for the complete combustion of one mole of heptene, fourteen moles of oxygen are necessary and this combustion will produce seven moles each of carbon dioxide and water.
Mole Ratio Calculation
The mole ratio is a key component of chemical equations as it shows the proportional relationship between the amounts in moles of any two substances involved in a chemical reaction. From the balanced equation provided earlier, we can derive the mole ratios necessary for calculations in a reaction involving heptene. For instance, the mole ratio of oxygen to heptene is 14 to 1, indicating that it takes 14 moles of oxygen to completely react with 1 mole of heptene.

For products, we refer to the balanced equation to establish their mole ratios to heptene. For carbon dioxide and water, the ratios are 7 to 1 with respect to heptene, respectively. These ratios are pivotal for stoichiometric calculations because they allow us to convert between moles of different substances within a chemical reaction.
Chemical Stoichiometry
Chemical stoichiometry is an area of chemistry that involves quantitatively analyzing the relationships expressed as mole ratios in balanced chemical equations. Stoichiometry is integral for predicting the amounts of products and reactants involved in a chemical reaction. In the context of the heptene combustion reaction, stoichiometry can be utilized to determine the volume of oxygen required to react with a certain quantity of heptene or the amount of carbon dioxide and water produced from this reaction.

These estimates are achievable by applying the mole ratios laid out in the balanced equation. If, for example, one needed to find out the number of moles of water produced from the combustion of 5 moles of heptene, the mole ratio \(7\mathrm{H}_2\mathrm{O} : 1\mathrm{C}_7\mathrm{H}_{14}\) would indicate that 35 moles of water (\(7 \times 5\)) would result. Such calculations are critical in fields like environmental science and engineering, where precise measurements can impact the design of combustion systems and the control of emissions.

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Most popular questions from this chapter

Calcium carbide, \(\mathrm{CaC}_{2},\) can be produced in an electric furnace by strongly heating calcium oxide (lime) with carbon. The unbalanced cquation is $$ \mathrm{CaO}(s)+\mathrm{C}(s) \rightarrow \mathrm{CaC}_{2}(s)+\mathrm{CO}(g) $$ Calcium carbide is useful because it reacts readily with water to form the flammable gas acctylene, \(\mathrm{C}_{2} \mathrm{H}_{2},\) which is used extensively in the welding industry. The unbalanced equation is $$ \mathrm{CaC}_{2}(s)+\mathrm{H}_{2} \mathrm{O}(l) \rightarrow \mathrm{C}_{2} \mathrm{H}_{2}(g)+\mathrm{Ca}(\mathrm{OH})_{2}(s) $$ What mass of acetylene gas, \(\mathrm{C}_{2} \mathrm{H}_{2},\) would be produced by complete reaction of \(3.75 \mathrm{~g}\) of calcium carbide?

Lead(II) oxide from an ore can be reduced to elemental lead by heating in a furnace with carbon. $$ \mathrm{PbO}(s)+\mathrm{C}(s) \rightarrow \mathrm{Pb}(l)+\mathrm{CO}(g) $$ Calculate the expected yield of Icad if \(50.0 \mathrm{~kg}\) of lead oxide is heated with \(50.0 \mathrm{~kg}\) of carbon.

Although we usually think of substances as "burning" only in oxygen gas, the process of rapid oxidation to produce a flame may also take place in other strongly oxidiring gases. For cxample, when iron is heated and placed in pure chlorine gas, the iron "burns" according to the following (unbalanced) reaction: $$ \mathrm{Fe}(s)+\mathrm{Cl}_{2}(g) \rightarrow \mathrm{FeCl}_{3}(s) $$ How many milligrams of iron(III) chloride result when \(15.5 \mathrm{mg}\) of iron is reacted with an excess of chlorine gas?

A common method for determining how much chloride ion is present in a sample is to precipitate the chloride from an aqueous solution of the sample with silver nitrate solution and then to weigh the silver chloride that results. The balanced net ionic reaction is $$ \mathrm{Ag}^{+}(a q)+\mathrm{Cl}^{-}(a q) \rightarrow \mathrm{AgCl}(s) $$ Suppose a 5.45 -g sample of pure sodium chloride is dissolved in water and is then treated with a solution containing \(1.15 \mathrm{~g}\) of silver nitrate. Will this quantity of silver nitrate be capable of precipitating all the chloride ion from the sodium chloride sample?

If baking soda (sodium hydrogen carbonate) is heated strongly, the following reaction occurs: $$ 2 \mathrm{NaHCO}_{3}(s) \rightarrow \mathrm{Na}_{2} \mathrm{CO}_{3}(s)+\mathrm{H}_{2} \mathrm{O}(g)+\mathrm{CO}_{2}(g) $$ Calculate the mass of sodium carbonate that will remain if a 1.52 - \(\mathrm{g}\) sample of sodium hydrogen carbonate is heated.

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