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What do the coefficients of a balanced chemical equation tell us about the proportions in which atoms and molecules react on an individual (microscopic) basis?

Short Answer

Expert verified
The coefficients of a balanced chemical equation represent the relative number of moles of reactants and products in the reaction, illustrating the law of conservation of mass and the principle of atom rearrangement during a chemical reaction. From an individual (microscopic) perspective, these coefficients indicate the proportions in which atoms and molecules need to react with one another to form the product(s), thereby providing crucial information on how atoms and molecules interact and rearrange in a chemical reaction.

Step by step solution

01

Understanding a balanced chemical equation

A balanced chemical equation represents a chemical reaction and the changes that occur during the reaction. In the equation, reactants (the substances that are undergoing the reaction) are written on the left side, and products (the substances that are formed as a result of the reaction) are written on the right side. Each substance is represented by its chemical formula, and coefficients are used to indicate the number of molecules or atoms involved in the reaction.
02

Law of conservation of mass

The balanced chemical equation takes into account the law of conservation of mass, which states that the total mass of the reactants must be equal to the total mass of the products. This is represented by having the same number of atoms for each element on both sides of the equation.
03

Coefficients in a balanced chemical equation

Coefficients in a balanced chemical equation represent the relative number of moles of the reactants and products in the reaction. They tell us how many molecules or atoms of each reactant are needed to yield a specific number of molecules or atoms of the product(s). In other words, they indicate the proportions in which the reactants must be present to completely react with one another and form products.
04

Relating coefficients to individual atoms and molecules

The coefficients in a balanced chemical equation also provide information on the interactions between individual (microscopic) atoms and molecules. These coefficients tell us how many individual atoms or molecules of a particular reactant are needed to react with another reactant to form the product(s). From a microscopic perspective, this illustrates how atoms and molecules rearrange during a chemical reaction and serves as a basis for understanding chemical reactions at an atomic scale.
05

Conclusion

In summary, the coefficients of a balanced chemical equation tell us about the proportions in which atoms and molecules react on an individual (microscopic) basis. They represent the relative number of moles of reactants and products in the reaction, illustrating the law of conservation of mass and the principle of atom rearrangement during a chemical reaction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coefficients
In a balanced chemical equation, you'll notice numbers in front of the chemical formulas. These numbers are called "coefficients." They are crucial because they indicate how many atoms or molecules of each substance participate in the reaction. Think of coefficients as instructions on how many pieces of each ingredient you need to make a specific recipe.
Without coefficients, you would not know the correct proportions to balance the reaction, which could lead to excess reactants or incomplete reactions.
  • Coefficients are placed in front of the chemical symbols or formulas.
  • They help maintain the reaction balance by showing how many units of each substance are needed.
Coefficients directly relate to the number of moles of a substance involved. This allows chemists and students to predict the amounts of products formed or reactants needed in a reaction.
Law of Conservation of Mass
The Law of Conservation of Mass is a fundamental concept in chemistry that states: matter cannot be created or destroyed in a chemical reaction. This means that the total mass of the reactants must equal the total mass of the products. When balancing a chemical equation, this law is illustrated by ensuring that the same number of each type of atom appears on both sides of the equation.
To achieve this balance, you'll often need to adjust the coefficients. It's similar to making sure that what you have before a reaction equals what you end up with after the reaction.
  • The same number of each kind of atom must be present before and after the reaction.
  • This law ensures that chemical equations are accurately balanced, representing real-world reactions.
Understanding this concept helps solidify why coefficients need to be adjusted in a balanced equation.
Microscopic Interactions
When we talk about chemical reactions, it's often useful to consider what's happening on a small, or "microscopic," scale. Molecules and atoms are the players in this tiny world. The coefficients in a chemical equation spotlight how many of these particles – atoms or molecules – interact to form new substances.
From a microscopic viewpoint, the coefficients show how these tiny particles are rearranged during the reaction. For instance, a coefficient tells you precisely how many individual atoms of one element need to meet and react with atoms of another element. This reflects the dynamics of atomic rearrangement which forms new bonds to create products.
  • Microscopic interactions depict the movement and bonding of atoms or molecules.
  • The coefficients show the exact amounts of atoms involved in these tiny interactions.
This concept forms the basis of understanding chemistry at an atomic level.
Chemical Reaction Proportions
The coefficients of a balanced chemical equation also reveal the proportions in which reactants combine and products form. These proportions ensure that all reactants are used efficiently.
In other words, they tell us how much of each reactant should be combined to completely react and form the desired products. This proportionate aspect helps chemists determine how much of each reactant is needed when scaling reactions up or down.
  • They show the relative ratios of reactants consumed and products formed.
  • This concept provides insights into reaction efficiency and economizes reactant usage.
By understanding reaction proportions, one can anticipate the amounts of substances required and produced, making chemical processes more efficient.

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Most popular questions from this chapter

Using the average atomic masses given inside the front cover of the text, calculate how many moles of each substance the following masses represent. a. 4.21 g of copper(II) sulfate b. \(7.94 \mathrm{~g}\) of barium nitrate c. \(1.24 \mathrm{mg}\) of water d. \(9.79 \mathrm{~g}\) of tungsten c. 1.45 lb of sulfur f. 4.65 g of ethyl alcohol, \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\) g. 12.01 g of carbon

For each of the following unbalanced equations, calculate how many moles of the second reactant would be required to react completely with 0.413 moles of the first reactant. a. \(\operatorname{Co}(s)+\mathbf{F}_{2}(g) \rightarrow \operatorname{CoF}_{3}(s)\) b. \(\mathrm{Al}(s)+\mathrm{H}_{2} \mathrm{SO}_{4}(a q) \rightarrow \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}(a q)+\mathrm{H}_{2}(g)\) c. \(\mathrm{K}(s)+\mathrm{H}_{2} \mathrm{O}(l) \rightarrow \mathrm{KOH}(a q)+\mathrm{H}_{2}(g)\) d. \(\mathrm{Cu}(s)+\mathrm{O}_{2}(g) \rightarrow \mathrm{Cu}_{2} \mathrm{O}(s)\)

A favorite demonstration among chemistry instructors, to show that the properties of a compound differ from those of its constituent clements, involves iron filings and powdered sulfur. If the instructor takes samples of iron and sulfur and just mixes them togcther, the two elements can be separated from one another with a magnet (iron is attracted to a magnet, sulfur is not ). If the instructor then combines and heats the mixture of iron and sulfur, a reaction takes place and the elements combine to form iron(II) sulfide (which is not attracted by a magnet). $$ \mathrm{Fe}(s)+\mathrm{S}(s) \rightarrow \operatorname{FeS}(s) $$ Suppose \(5.25 \mathrm{~g}\) of iron filings is combined with \(12.7 \mathrm{~g}\) of sulfur. What is the theoretical yield of iron(ll) sulfidc?

For each of the following reactions, give the balanced chemical equation for the reaction and state the meaning of the cquation in terms of individual molecules and in terms of moles of molecules. a. \(\mathrm{MnO}_{2}(s)+\mathrm{Al}(s) \rightarrow \mathrm{Mn}(s)+\mathrm{Al}_{2} \mathrm{O}_{3}(s)\) b. \(\mathrm{B}_{2} \mathrm{O}_{3}(s)+\mathrm{CaF}_{2}(s) \rightarrow \mathrm{BF}_{3}(g)+\mathrm{CaO}(s)\) c. \(\mathrm{NO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l) \rightarrow \mathrm{HNO}_{3}(a q)+\mathrm{NO}(g)\) d. \(\mathrm{C}_{6} \mathrm{H}_{6}(g)+\mathrm{H}_{2}(g) \rightarrow \mathrm{C}_{6} \mathrm{H}_{12}(g)\)

If sodium peroxide is added to water, clemental oxygen gas is generated: $$ \mathrm{Na}_{2} \mathrm{O}_{2}(s)+\mathrm{H}_{2} \mathrm{O}(l) \rightarrow \mathrm{NaOH}(a q)+\mathrm{O}_{2}(g) $$ Suppose \(3.25 \mathrm{~g}\) of sodium peroxide is added to a large excess of water. What mass of oxygen gas will be produced?

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