Question

Arrange the following substances in order of increasing mass percent of nitrogen. a. NO b. \(\mathrm{N}_{2} \mathrm{O}\) c. \(\mathrm{NH}_{3}\) d. SNH

Short answer

In increasing order of mass percent of nitrogen, the substances are arranged as: SNH (\(29.8\%\)), NO (\(46.7\%\)), N2O (\(63.6\%\)), and NH3 (\(82.2\%\)).

Step-by-step solution

Calculate the molar mass of each compound

First, let's calculate the molar mass of each compound. a. NO: For NO, the molar mass is \(1 \times M(\mathrm{N}) + 1 \times M(\mathrm{O})\) b. \(\mathrm{N}_{2} \mathrm{O}\): For N2O, the molar mass is \(2 \times M(\mathrm{N}) + 1 \times M(\mathrm{O})\) c. \(\mathrm{NH}_{3}\): For NH3, the molar mass is \(1 \times M(\mathrm{N}) + 3 \times M(\mathrm{H})\) d. SNH: For SNH, the molar mass is \(1 \times M(\mathrm{S}) + 1 \times M(\mathrm{N}) + 1 \times M(\mathrm{H})\)

Calculate the mass percent of nitrogen in each compound

Now we will calculate the mass percent of nitrogen in each compound. a. NO: The mass percent of nitrogen in NO is \(\frac{M(\mathrm{N})}{M(\mathrm{NO})} \times 100\%\) b. \(\mathrm{N}_{2} \mathrm{O}\): The mass percent of nitrogen in N2O is \(\frac{2 \times M(\mathrm{N})}{M(\mathrm{N}_{2} \mathrm{O})} \times 100\%\) c. \(\mathrm{NH}_{3}\): The mass percent of nitrogen in NH3 is \(\frac{M(\mathrm{N})}{M(\mathrm{NH}_{3})} \times 100\%\) d. SNH: The mass percent of nitrogen in SNH is \(\frac{M(\mathrm{N})}{M(\mathrm{SNH})} \times 100\%\)

Compare the mass percent of nitrogen in all compounds and arrange them

Now we will compare the mass percent of nitrogen in all compounds and arrange them in increasing order. a. NO: \(\frac{14}{14 + 16} \times 100\% = 46.7\%\) b. \(\mathrm{N}_{2} \mathrm{O}\): \(\frac{2 \times 14}{2 \times 14 + 16} \times 100\% = 63.6\%\) c. \(\mathrm{NH}_{3}\): \(\frac{14}{14 + 3 \times 1} \times 100\% = 82.2\%\) d. SNH: \(\frac{14}{32 + 14 + 1} \times 100\% = 29.8\%\) Arranging the substances in increasing order of mass percent of nitrogen, we get: SNH < NO < N2O < NH3