Chapter 6: Problem 58
Write a balanced chemical equation for the complete combustion of pentene, \(\mathrm{C}_{7} \mathrm{H}_{14} .\) In combustion, pentene reacts with oxygen to produce carbon dioxide and water.
Short Answer
Expert verified
The balanced equation for the complete combustion of pentene is:
\(2C_7H_{14} + 21O_2 \rightarrow 14CO_2 + 14H_2O\)
Step by step solution
01
Write the unbalanced equation
Write the unbalanced equation representing the complete combustion of pentene with oxygen gas as the reactant and carbon dioxide and water as the products:
C7H14 + O2 -> CO2 + H2O
02
Balance the carbon atoms
There are 7 carbon atoms on the reactant side (in C7H14) and only 1 carbon atom in CO2 on the product side, so we need to multiply CO2 by 7 to balance the carbon atoms:
C7H14 + O2 -> 7CO2 + H2O
Now we have 7 carbon atoms on both sides.
03
Balance the hydrogen atoms
There are 14 hydrogen atoms on the reactant side (in C7H14) and 2 hydrogen atoms in H2O on the product side, so we need to multiply H2O by 7 to balance the hydrogen atoms:
C7H14 + O2 -> 7CO2 + 7H2O
Now we have 14 hydrogen atoms on both sides.
04
Balance the oxygen atoms
Finally, we need to balance the oxygen atoms. On the product side, we have 14 oxygen atoms in CO2 and another 7 oxygen atoms in H2O, making a total of 21 oxygen atoms. On the reactant side, we have 2 oxygen atoms in O2, so we need to multiply O2 by 10.5 to balance the oxygen atoms:
C7H14 + 10.5O2 -> 7CO2 + 7H2O
However, it is not common to see fractions in balanced chemical equations. To get rid of the fraction, we will multiply the entire equation by 2:
2C7H14 + 21O2 -> 14CO2 + 14H2O
05
Write the final balanced equation
The balanced equation for the complete combustion of pentene is:
2C7H14 + 21O2 -> 14CO2 + 14H2O
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Combustion Reactions
Combustion reactions are a type of chemical process where a substance reacts with oxygen to produce heat and new chemical products. In our case with pentene, the combustion is classified as a complete combustion. This occurs when a hydrocarbon burns in the presence of ample oxygen. The primary products of complete combustion reactions are carbon dioxide \(\text{(CO}_2)\) and water \(\text{(H}_2\text{O)}\).
Complete combustion reactions are highly exothermic, meaning they release a significant amount of energy, usually in the form of heat and light.
In practical terms, this is what happens when fuels like gasoline burn in car engines or natural gas is used in heaters.
Key features of combustion reactions include:
Complete combustion reactions are highly exothermic, meaning they release a significant amount of energy, usually in the form of heat and light.
In practical terms, this is what happens when fuels like gasoline burn in car engines or natural gas is used in heaters.
Key features of combustion reactions include:
- Involvement of oxygen as a reactant.
- Hydrocarbons, like pentene, serving as common fuel sources.
- Production of water and carbon dioxide as common by-products.
- Release of energy, often making flames appear.
Hydrocarbons
Hydrocarbons are organic compounds composed entirely of hydrogen and carbon atoms. They serve as the base structure for many important substances like fuels, plastics, and even some pharmaceuticals. Pentene, the hydrocarbon involved in our exercise, is an unsaturated hydrocarbon classified as an alkene.
An alkene is characterized by having at least one double bond between carbon atoms.
This double bond gives alkenes unique properties like reactivity, which makes them suitable for combustion reactions.
There are different classes of hydrocarbons:
In environmental terms, combustion of hydrocarbons is a major source of energy but also contributes to greenhouse gas emissions. Hence, understanding hydrocarbons is crucial in discussions around sustainable energy and environmental impact.
An alkene is characterized by having at least one double bond between carbon atoms.
This double bond gives alkenes unique properties like reactivity, which makes them suitable for combustion reactions.
There are different classes of hydrocarbons:
- Alkanes: Only single bonds between carbon atoms, making them less reactive.
- Alkenes: One or more double bonds, like pentene, with increased reactivity.
- Alkynes: One or more triple bonds, making them even more reactive.
In environmental terms, combustion of hydrocarbons is a major source of energy but also contributes to greenhouse gas emissions. Hence, understanding hydrocarbons is crucial in discussions around sustainable energy and environmental impact.
Stoichiometry
Stoichiometry is the branch of chemistry that deals with measuring the amounts of reactants and products in chemical reactions. It essentially ensures that chemical equations adhere to the law of conservation of mass, which dictates that matter cannot be created or destroyed in chemical processes.
A balanced chemical equation is a fundamental application of stoichiometry.In the balanced equation for the combustion of pentene:\[2\text{C}_7\text{H}_{14} + 21\text{O}_2 \rightarrow 14\text{CO}_2 + 14\text{H}_2\text{O}\]Every atom present in the reactants must be accounted for in the products.
This means the number of atoms for each element is the same on both sides of the equation:
Overall, stoichiometry is key in ensuring that all reactions conducted, whether in a lab or by natural processes, observe the inherent law of conservation of mass.
A balanced chemical equation is a fundamental application of stoichiometry.In the balanced equation for the combustion of pentene:\[2\text{C}_7\text{H}_{14} + 21\text{O}_2 \rightarrow 14\text{CO}_2 + 14\text{H}_2\text{O}\]Every atom present in the reactants must be accounted for in the products.
This means the number of atoms for each element is the same on both sides of the equation:
- 14 carbon atoms on both sides.
- 28 hydrogen atoms on each side.
- 42 oxygen atoms on both sides (21 O2 molecules consumed).
Overall, stoichiometry is key in ensuring that all reactions conducted, whether in a lab or by natural processes, observe the inherent law of conservation of mass.