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An ion with two more electrons than it has protons has a charge.

Short Answer

Expert verified
The ion has a charge of \(-2\).

Step by step solution

01

Identify given information

In the problem, we are given an ion with two more electrons than protons.
02

Analyze the charge of protons and electrons

We know that the charge of a proton is +1, and the charge of an electron is -1.
03

Determine the total charge of the ion

Let "x" represent the number of protons in the ion. Since there are two more electrons than protons, the number of electrons is x+2. Now we can calculate the total charge of the ion by multiplying the number of protons by their charge (+1) and the number of electrons by their charge (-1), and then adding the two products: Ion charge = (Number of protons × Charge of a proton) + (Number of electrons × Charge of an electron) Ion charge = (x × +1) + ((x+2) × -1)
04

Simplify the expression

Now we simplify the expression: Ion charge = x - (x + 2) Ion charge = x - x - 2 Ion charge = -2 So the ion has a charge of -2.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proton Charge
Protons are tiny particles found in the nucleus of an atom. They carry a positive charge, which is essential for balancing the negative charge carried by electrons. Each proton has a charge of +1, which means if an atom has "n" protons, its total positive charge is "+n".
  • Protons determine the identity of an element.
  • Although protons are small, they have a significant impact on the atom’s properties.
Understanding the fundamental role of proton charges can help in comprehending how different atoms interact and form molecules.
Electron Charge
Electrons are negatively charged particles that orbit the nucleus of an atom. Each electron carries a charge of -1. Therefore, if an atom has "n" electrons, its total negative charge is "-n".
  • Electrons are responsible for many of the chemical properties of elements.
  • The interaction between electron charges affects how atoms bond with each other.
Unlike protons, electrons can be gained or lost, which leads to the formation of ions, either negatively or positively charged. This behavior is a key concept in chemistry, especially when studying ions and their properties.
Balancing Charges
To understand ionic charges, one must grasp the concept of balancing charges. Atoms tend to have an equal number of protons and electrons, resulting in a neutral charge. When there is an unequal amount, the atom becomes an ion.
  • If there are more electrons than protons, the ion will have a negative charge.
  • If there are more protons than electrons, the ion will have a positive charge.
Charge balance is crucial in chemical reactions and in the stability of compounds. Learning to calculate ion charges helps in predicting how substances will interact and react with each other.
Introductory Chemistry
Introductory chemistry lays the foundation for understanding more complex chemical concepts. At its core, it involves understanding the basic structure of atoms and how they form molecules through chemical bonding.
  • Chemistry examines the properties, composition, and changes of matter.
  • Key aspects include atomic structure, the periodic table, and bonding types.
Embracing these basic principles allows students to make sense of how everyday materials are created and how they behave. From the topic of ions to balancing equations, introductory chemistry sets the stage for more advanced topics.

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Most popular questions from this chapter

For the following pairs of ions, use the principle of electrical neutrality to predict the formula of the binary compound that the ions are most likely to form. a. \(\mathrm{Na}^{+}\) and \(\mathrm{S}^{2-}\) b. \(\mathrm{K}^{+}\) and \(\mathrm{Cl}^{-}\) c. \(\mathrm{Ba}^{2+}\) and \(\mathrm{O}^{2-}\) d. \(\mathrm{Mg}^{2+}\) and \(\mathrm{Se}^{2-}\) e. \(\mathrm{Cu}^{2+}\) and \(\mathrm{Br}^{-}\) f. \(\mathrm{Al}^{3+}\) and \(\mathrm{I}^{-}\) g. \(\mathrm{Al}^{3+}\) and \(\mathrm{O}^{2-}\) h. \(\mathrm{Ca}^{2+}\) and \(\mathrm{N}^{3-}\)

For the oxyanions of sulfur, the ending -ite is used for \(\mathrm{SO}_{3}{ }^{2-}\) to indicate that it contains than does \(\mathrm{SO}_{4}^{2-}\)

Give the name of each of the following polyatomic anions. a. \(\mathrm{CO}_{3}^{2-}\) b. \(\mathrm{ClO}_{3}^{-}\) c. \(\mathrm{SO}_{4}^{2-}\) d. \(\mathrm{PO}_{4}^{3-}\) e. \(\mathrm{ClO}_{4}^{-}\) f. \(\mathrm{MnO}_{4}^{-}\)

Write the formula for each of the following binary compounds of nonmetallic elements. a. diphosphorus monoxide b. sulfur dioxide c. diphosphorus pentoxide d. carbon tetrachloride e. nitrogen tribromide f. silicon tetrafluoride g. sulfur dichloride

For each of the following processes that show the formation of ions, complete the process by indicating the number of electrons that must be gained or lost to form the ion. Indicate the total number of electrons in the ion, and in the atom from which it was made. a. \(\mathrm{Al} \rightarrow \mathrm{Al}^{3+}\) b. \(\mathrm{S} \rightarrow \mathrm{S}^{2-}\) c. \(\mathrm{Cu} \rightarrow \mathrm{Cu}^{+}\) \(\mathrm{d} . \mathrm{F} \rightarrow \mathrm{F}^{-}\) e. \(\mathrm{Zn} \rightarrow \mathrm{Zn}^{2+}\) \(\mathrm{f} . \mathrm{P} \rightarrow \mathrm{P}^{3-}\)

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