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Write the equilibrium expression for each of the following reactions. a. \(\mathrm{H}_{2}(g)+\mathrm{Br}_{2}(g) \rightleftharpoons 2 \mathrm{HBr}(g)\) b. \(2 \mathrm{H}_{2}(g)+\mathrm{S}_{2}(g) \rightleftharpoons 2 \mathrm{H}_{2} \mathrm{~S}(g)\) c. \(\mathrm{H}_{2}(g)+\mathrm{C}_{2} \mathrm{~N}_{2}(g) \rightleftharpoons 2 \mathrm{HCN}(g)\)

Short Answer

Expert verified
The short answers for the equilibrium expressions are: a. \(K_c = \frac{[\mathrm{HBr}]^2}{[\mathrm{H}_2][\mathrm{Br}_2]}\) b. \(K_c = \frac{[\mathrm{H}_{2}\mathrm{S}]^2}{[\mathrm{H}_2]^2[\mathrm{S}_2]}\) c. \(K_c = \frac{[\mathrm{HCN}]^2}{[\mathrm{H}_2][\mathrm{C}_2\mathrm{N}_2]}\)

Step by step solution

01

Identify the reactants and products

In the reaction \(\mathrm{H}_{2}(g)+\mathrm{Br}_{2}(g) \rightleftharpoons 2 \mathrm{HBr}(g)\), the reactants are \(\mathrm{H}_{2}\) and \(\mathrm{Br}_{2}\), and the product is \(\mathrm{HBr}\).
02

Write the equilibrium expression

For the given reaction, the equilibrium expression is given by: \[K_c = \frac{[\mathrm{HBr}]^2}{[\mathrm{H}_2][\mathrm{Br}_2]}\] #b. Writing the equilibrium expression for reaction b#
03

Identify the reactants and products

In the reaction \(2 \mathrm{H}_{2}(g)+\mathrm{S}_{2}(g) \rightleftharpoons 2 \mathrm{H}_{2}\mathrm{S}(g)\), the reactants are \(\mathrm{H}_{2}\) and \(\mathrm{S}_{2}\), and the product is \(\mathrm{H}_{2}\mathrm{S}\).
04

Write the equilibrium expression

For the given reaction, the equilibrium expression is given by: \[K_c = \frac{[\mathrm{H}_{2}\mathrm{S}]^2}{[\mathrm{H}_2]^2[\mathrm{S}_2]}\] #c. Writing the equilibrium expression for reaction c#
05

Identify the reactants and products

In the reaction \(\mathrm{H}_{2}(g)+\mathrm{C}_{2}\mathrm{N}_{2}(g) \rightleftharpoons 2 \mathrm{HCN}(g)\), the reactants are \(\mathrm{H}_{2}\) and \(\mathrm{C}_{2}\mathrm{N}_{2}\), and the product is \(\mathrm{HCN}\).
06

Write the equilibrium expression

For the given reaction, the equilibrium expression is given by: \[K_c = \frac{[\mathrm{HCN}]^2}{[\mathrm{H}_2][\mathrm{C}_2\mathrm{N}_2]}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equilibrium Expression
In chemical equilibrium, the equilibrium expression is a mathematical formula that represents the state at which the concentrations of reactants and products are constant. It is crucial to understanding how reactions behave under different conditions. Let's look deeper into how this works.

The equilibrium constant, commonly denoted as \(K_c\), relates the concentrations of products and reactants in a reversible chemical reaction at equilibrium. The general form of an equilibrium expression for a reaction \(aA + bB \rightleftharpoons cC +dD\) is given by:
  • \(K_c = \frac{[C]^c[D]^d}{[A]^a[B]^b}\)
Here, \([C]\) and \([D]\) are the concentrations of the products, \(A\) and \(B\) are the reactants, and \(a\), \(b\), \(c\), and \(d\) are their respective coefficients from the balanced chemical equation.

Understanding how to construct and interpret these expressions can help predict how changes in conditions might shift the balance of a reaction. This insight is vital for fields like chemical engineering and environmental science.
Reactants and Products
In any chemical reaction, identifying reactants and products is an essential first step. Reactants are substances that start a reaction, while products are the new substances formed as a result of the reaction.

For example, consider the following reaction: \(\mathrm{H}_{2}(g)+\mathrm{Br}_{2}(g) \rightleftharpoons 2 \mathrm{HBr}(g)\). Here, \(\mathrm{H}_{2}\) and \(\mathrm{Br}_{2}\) are reactants, and \(\mathrm{HBr}\) is the product. These molecules undergo a transformation, forming new chemical bonds to create the product.
  • Reactants have their bonds broken, which requires energy.
  • Products are formed by creating new bonds, often releasing energy.
This simple concept of breaking and forming bonds lies at the heart of understanding chemical reactions and dictates the resulting equilibrium state, playing a significant role in what you'll see in an equilibrium expression.
Chemical Reactions
Chemical reactions are processes in which substances undergo conversion to form new substances. An essential aspect of these reactions is determining their direction and extent, aspects inherently connected to the concept of equilibrium.

Each chemical reaction can reach a state of equilibrium where the rates of the forward and reverse reactions are equal, meaning that the concentrations of reactants and products remain constant over time. Recognizing this balance is crucial for applications such as drug interactions in medicine or nutrient cycles in ecology.

Reactions can be manipulated or driven to completion by changing:
  • Temperature
  • Pressure
  • Concentration of reactants and products
By influencing these factors, one can steer the equilibrium position. For instance, adding more reactants typically shifts equilibrium toward the products, according to Le Chatelier's Principle. Understanding and predicting these shifts is fundamental for optimizing reactions in both laboratory and industrial settings.

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Most popular questions from this chapter

Suppose the reaction system $$ 2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) \rightleftharpoons 2 \mathrm{NO}_{2}(g) $$ has already reached equilibrium. Predict the effect of each of the following changes on the position of the equilibrium. Tell whether the equilibrium will shift to the right, will shift to the left, or will not be affected. a. Additional oxygen is injected into the system. b. \(\mathrm{NO}_{2}\) is removed from the reaction vessel. c. 1.0 mole of helium is injected into the system.

Approximately \(9.0 \times 10^{-4} \mathrm{~g}\) of silver chloride, \(\mathrm{AgCl}(s),\) dissolves per liter of water at 10 ' \(\mathrm{C}\). Calculate \(K_{\mathrm{sp}}\) for \(\mathrm{AgCl}(s)\) at this temperature.

In general terms, what does the equilibrium constant for a reaction represent? What is the algebraic form of the equilibrium constant for a typical reaction? What do square brackets indicate when we write an equilibrium constant?

Consider the general reaction $$ 2 \mathrm{~A}(g)+\mathrm{B}(s) \rightleftharpoons \mathrm{C}(g)+3 \mathrm{D}(g) \quad \Delta H=+115 \mathrm{~kJ} / \mathrm{mol} $$ which has already come to equilibrium. Predict whether the equilibrium will shift to the left, will shift to the right, or will not be affected if the changes indicated below are made to the system. a. Additional \(\mathrm{B}(s)\) is added to the system. b. \(\mathrm{C}(g)\) is removed from the system as it forms. c. The volume of the system is decreased by a factor of 2 . d. The temperature is increased.

When a reaction system has reached chemical equilibrium, the concentrations of the reactants and products no longer change with time. Why does the amount of product no longer increase, even though large concentrations of the reactants may still be present?

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