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An expandable vessel contains \(729 \mathrm{~mL}\) of gas at \(22 \mathrm{C}\). What volume will the gas sample in the vessel have if it is placed in a boiling water bath \((100 . \quad \mathrm{C}) ?\)

Short Answer

Expert verified
The final volume of the gas, when placed in a boiling water bath at 100°C, is approximately \(923.83 \mathrm{~mL}\).

Step by step solution

01

Understand the gas law involved - Charles' Law

Charles' Law is given by the formula: \[V_1/T_1 = V_2/T_2\] In the formula, \(V_1\) and \(V_2\) represents the initial and final volumes, and \(T_1\) and \(T_2\) represent the initial and final temperatures in Kelvin. Remember that the temperatures must be in Kelvin for this law.
02

Convert given temperatures to Kelvin

First, convert the given temperatures into Kelvin: Initial temperature: 22°C = \(22 + 273.15 = 295.15 K\) Final temperature: 100 °C = \(100 + 273.15 = 373.15 K\)
03

Solve for the final volume

Now that we have the given temperatures in Kelvin, let's solve the equation using the given volume and temperatures: \[\frac{V_1}{T_1} = \frac{V_2}{T_2}\] Plug in the given values: \[\frac{729}{295.15} = \frac{V_2}{373.15}\] Now solve for \(V_2\): \[V_2 = \frac{729 \times 373.15}{295.15}\] \[V_2 = 923.83\] The final volume of the gas, when placed in a boiling water bath at 100°C, is approximately \(923.83 \mathrm{~mL}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

gas laws
Gas laws are essential principles that help us understand and predict the behavior of gases in various conditions. Charles' Law, one of the fundamental gas laws, establishes a relationship between volume and temperature. Specifically, it states that the volume of a gas is directly proportional to its absolute temperature when the pressure is held constant.
Charles' Law is mathematically expressed as: \[ V_1/T_1 = V_2/T_2 \] Where:
  • \( V_1 \) and \( V_2 \) are the initial and final volumes.
  • \( T_1 \) and \( T_2 \) are the initial and final temperatures (in Kelvin).
This equation tells us that if a gas is heated, its volume will increase, provided the pressure does not change. Conversely, cooling the gas will cause its volume to decrease under constant pressure. Using Charles' Law, you can predict how much a gas will expand or contract with a change in temperature, making it a valuable tool in various scientific and engineering applications. Understanding gas laws like Charles' Law enables us to solve practical problems and make accurate assumptions about gas behaviors in everyday life.
temperature conversion
Converting temperature units is an essential step when working with gas laws, particularly Charles' Law, as calculations must utilize the Kelvin scale. The Kelvin scale is crucial because it starts at absolute zero, where all molecular motion ceases. Hence, it provides a consistent base for temperature comparisons.
To convert temperatures from Celsius to Kelvin, a straightforward formula is applied: \[ K = °C + 273.15 \] This addition brings all values onto a scale that allows for accurate computations with various gas laws. For instance, in our exercise, the initial temperature of 22°C is converted to 295.15 K, and the final temperature of 100°C is converted to 373.15 K.
This conversion is vitally important because using Celsius or Fahrenheit would lead to incorrect results when using Charles' Law or other gas laws. Always remember: when working with gas laws, Kelvin is the key scale to bring precision and accuracy to your calculations.
Kelvin scale
The Kelvin scale is integral to thermodynamic calculations in sciences, including when dealing with gas laws. It is the Standard International (SI) unit for temperature, thus preferred in scientific calculations. This scale is unique because it defines 0 Kelvin as absolute zero, the theoretical point where no molecular kinetic energy remains in a substance.
Why is the Kelvin scale used in such calculations instead of Celsius or Fahrenheit? Because it provides a true proportional scale that maintains the accurate relationships required in scientific formulas, such as Charles' Law and other related equations.
Some key points to note about the Kelvin scale are:
  • 1 Kelvin and 1 degree Celsius have the same incremental change.
  • 273.15 K is equivalent to 0°C, making conversion between them straightforward.
  • It eliminates the need for negative temperatures in calculations, ensuring consistency and reducing errors.

By always using Kelvin, you ensure your calculations reflect the realistic behavior of gases and thermodynamic systems. It helps avoid the pitfalls that come with using relative scales like Celsius or Fahrenheit, thus maintaining the integrity of scientific investigations and analyses.

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Most popular questions from this chapter

What volume does a mixture of \(14.2 \mathrm{~g}\) of \(\mathrm{He}\) and \(21.6 \mathrm{~g}\) of \(\mathrm{H}_{2}\) occupy at \(28^{\circ} \mathrm{C}\) and \(0.985 \mathrm{~atm} ?\)

Given each of the following sets of values for an ideal gas, calculate the unknown quantity. a. \(P=782 \mathrm{~mm} \mathrm{Hg} ; V=? ; n=0.210 \mathrm{~mol} ; T=27 \quad \mathrm{C}\) b. \(P=? \mathrm{~mm} \mathrm{Hg} ; V=644 \mathrm{~mL} ; n=0.0921 \mathrm{~mol} ; T=303 \mathrm{~K}\) c. \(P=745 \mathrm{~mm} \mathrm{Hg} ; V=11.2 \mathrm{~L} ; n=0.401 \mathrm{~mol} ; T=? \mathrm{~K}\)

A 500.-mL sample of \(\mathrm{O}_{2}\) gas at 24 ' \(\mathrm{C}\) was prepared by decomposing a \(3 \%\) aqueous solution of hydrogen peroxide, \(\mathrm{H}_{2} \mathrm{O}_{2},\) in the presence of a small amount of manganese catalyst by the reaction $$ 2 \mathrm{H}_{2} \mathrm{O}_{2}(a q) \rightarrow 2 \mathrm{H}_{2} \mathrm{O}(g)+\mathrm{O}_{2}(g) $$ The oxygen thus prepared was collected by displacement of water. The total pressure of gas collected was \(755 \mathrm{~mm} \mathrm{Hg}\). What is the partial pressure of \(\mathrm{O}_{2}\) in the mixture? How many moles of \(\mathrm{O}_{2}\) are in the mixture? (The vapor pressure of water at 24 " is \(23 \mathrm{~mm} \mathrm{Hg}\).)

A helium tank contains \(25.2 \mathrm{~L}\) of helium at 8.40 atm pressure. Determine how many 1.50 -L balloons at \(755 \mathrm{~mm} \mathrm{Hg}\) can be inflated with the gas in the tank, assuming that the tank will also have to contain He at \(755 \mathrm{~mm} \mathrm{Hg}\) after the balloons are filled (that is, it is not possible to empty the tank completely). The temperature is 25 C in all cases.

Consider the following unbalanced chemical equation: $$ \mathrm{Cu}_{2} \mathrm{~S}(s)+\mathrm{O}_{2}(g) \rightarrow \mathrm{Cu}_{2} \mathrm{O}(s)+\mathrm{SO}_{2}(g) $$ What volume of oxygen gas, measured at 27.5 " \(\mathrm{C}\) and 0.998 atm, is required to react with \(25 \mathrm{~g}\) of copper(I) sulfide? What volume of sulfur dioxide gas is produced under the same conditions?

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