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Sketch the \(3 d\) orbitals. How do the \(4 d\) orbitals differ from the \(3 d\) orbitals?

Short Answer

Expert verified
The 3d orbitals consist of 5 shapes: dxy, dyz, dxz, dx2-y2, and dz2. They differ from the 4d orbitals mainly in size, energy, and number of nodes; 4d are larger, higher in energy, and have one more node compared to 3d orbitals.

Step by step solution

01

Sketching the 3d Orbitals

To sketch the 3d orbitals, start with the five standard types: dxy, dyz, dxz, dx2-y2, and dz2. Each orbital has 4 lobes except the dz2 which has a donut-shaped lobe in the center. The dxy, dyz, and dxz orbitals have lobes lying between the axis, whereas the dx2-y2 orbitals have lobes along the axis. The dz2 orbital is unique because it has a donut-shaped lobe in the center and extends along the z-axis.
02

Understanding Differences in Energy Levels

The main difference between the 3d and 4d orbitals is their size and energy. 4d orbitals are higher in energy and larger in size than 3d orbitals because they belong to the fourth energy level as opposed to the third. The shapes of the 4d orbitals are similar to the 3d orbitals but they are less penetrating, meaning they have less presence close to the nucleus when compared to 3d orbitals.
03

Noting Additional Differences

In addition to size and energy, the 4d orbitals have more nodes than the 3d orbitals. A node is a region where the probability of finding an electron is zero. Each 4d orbital has one more node than its corresponding 3d orbital. This impacts the radial distribution of electrons.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Orbital Sketching
Understanding the shapes of orbitals is a fundamental concept in quantum chemistry, as it provides insights into where electrons are likely to be located around a nucleus. When sketching the 3d orbitals, it is crucial to realize that these are not two-dimensional, but rather three-dimensional shapes extending into space. The five types of 3d orbitals are: dxy, dyz, dxz, dx2-y2, and dz2.

Visualize the dxy, dyz, and dxz orbitals as four leaf clovers lying in between the x, y, and z axes. The dx2-y2 orbital has its lobes directed along the axes, resulting in a cross shape. The dz2 stands out with its two lobes extending along the z-axis and a distinctive torus, or donut-shaped lobe, circling the middle. When comparing these to the 4d orbitals, remember that the overall shapes are the same, but scaled up, illustrating a larger spatial distribution due to increased principal quantum number.
Energy Levels in Orbitals
The energy level of an orbital is a crucial factor in understanding electron configuration and chemical properties. In general, as you move from 3d to 4d orbitals, there is an increase in energy. This is dictated by the principal quantum number, which is higher for the 4d orbitals (n=4) relative to the 3d orbitals (n=3).

The larger principal quantum number translates to an electron being further from the nucleus and, therefore, less tightly bound – this contributes to the 4d orbitals having a higher energy. Notably, electrons in an atom will fill the lower energy 3d orbitals before occupying the 4d orbitals, a principle that's important when determining the electron configuration of elements.
Electron Configuration
Electron configuration outlines how electrons are distributed in an atom's orbitals, influencing chemical reactivity and bonding. Following the Aufbau principle, electrons fill up orbitals in order of increasing energy, starting with the lowest. Hund's rule and the Pauli Exclusion Principle also govern the arrangement of electrons in orbitals.

Considering 3d and 4d orbitals within electron configuration, the 3d orbitals generally fill after the 4s orbital and before the 4p, according to the configuration of transition metals. The 4d orbitals begin to fill in the fifth period of the periodic table, as seen with elements like Yttrium (Y) and Zirconium (Zr). The additional node in 4d orbitals mentioned in the exercise is one aspect that distinguishes them from their 3d counterparts and influences their energy and occupancy in the electron configuration.

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Most popular questions from this chapter

When an electron makes a transition from the \(n=3\) to the \(n=2\) hydrogen atom Bohr orbit, the energy difference between these two orbits \(\left(3.0 \times 10^{-19} \mathrm{~J}\right)\) is emitted as a photon of light. The relationship between the energy of a photon and its wavelength is given by \(E=h c / \lambda\), where \(E\) is the energy of the photon in \(J, h\) is Planck's constant \(\left(6.626 \times 10^{-34} \mathrm{~J} \cdot \mathrm{s}\right)\), and \(c\) is the speed of light \(\left(3.00 \times 10^{8} \mathrm{~m} / \mathrm{s}\right)\). Find the wavelength of light emitted by hydrogen atoms when an electron makes this transition.

Use the electron configuration of oxygen to explain why it tends to form a 2 - ion.

Choose the more metallic element from each pair. (a) Sr or \(\mathrm{Sb}\) (b) As or Bi (c) \(\mathrm{Cl}\) or \(\mathrm{O}\) (d) \(S\) or As

Write full electron configurations for each element. (a) \(\mathrm{N}\) (b) \(\mathrm{Mg}\) (c) \(\mathrm{Ar}\) (d) Se

When atoms lose more than one electron, the ionization energy to remove the second electron is always more than the ionization energy to remove the first. Similarly, the ionization energy to remove the third electron is more than the second and so on. However, the increase in ionization energy upon the removal of subsequent electrons is not necessarily uniform. For example, consider the first three ionization energies of magnesium: \(\begin{array}{ll}\text { First ionization energy } & 738 \mathrm{~kJ} / \mathrm{mol} \\ \text { Second ionization energy } & 1450 \mathrm{~kJ} / \mathrm{mol} \\ \text { Third ionization energy } & 7730 \mathrm{~kJ} / \mathrm{mol}\end{array}\) The second ionization energy is roughly twice the first ionization energy, but then the third ionization energy is over five times the second. Use the electron configuration of magnesium to explain why this is so. Would you expect the same behavior in sodium? Why or why not?

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