When atoms lose more than one electron, the ionization energy to remove the
second electron is always more than the ionization energy to remove the first.
Similarly, the ionization energy to remove the third electron is more than the
second and so on. However, the increase in ionization energy upon the removal
of subsequent electrons is not necessarily uniform. For example, consider the
first three ionization energies of magnesium:
\(\begin{array}{ll}\text { First ionization energy } & 738 \mathrm{~kJ} /
\mathrm{mol} \\ \text { Second ionization energy } & 1450 \mathrm{~kJ} /
\mathrm{mol} \\ \text { Third ionization energy } & 7730 \mathrm{~kJ} /
\mathrm{mol}\end{array}\)
The second ionization energy is roughly twice the first ionization energy, but
then the third ionization energy is over five times the second. Use the
electron configuration of magnesium to explain why this is so. Would you
expect the same behavior in sodium? Why or why not?