Chapter 2: Problem 3
Why is scientific notation useful?
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chapter 2: Problem 3
Why is scientific notation useful?
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for freeA vase is said to be solid platinum. It displaces \(18.65 \mathrm{~mL}\) of water and has a mass of \(157 \mathrm{~g}\). Could the vase be solid platinum?
In 1999, scientists discovered a new class of black holes with masses 100 to 10,000 times the mass of our sun but occupying less space than our moon. Suppose that one of these black holes has a mass of \(1 \times 10^{3}\) suns and a radius equal to one-half the radius of our moon. What is its density in grams per cubic centimeter? The mass of the sun is \(2.0 \times 10^{30} \mathrm{~kg}\), and the radius of the moon is \(2.16 \times 10^{3} \mathrm{mi}\). (Volume of a sphere \(=\frac{4}{3} \pi r^{3}\).)
Perform each calculation to the correct number of significant figures. (a) \((78.4-44.889) \div 0.0087\) (b) \((34.6784 \times 5.38)+445.56\) (c) \(\left(78.7 \times 10^{5} \div 88.529\right)+356.99\) (d) \((892 \div 986.7)+5.44\)
Correct any answers that have the incorrect number of significant figures. (a) \((908.4-3.4) \div 3.52 \times 10^{4}=0.026\) (b) \((1206.7-0.904) \times 89=1.07 \times 10^{5}\) (c) \((876.90+98.1) \div 56.998=17.11\) (d) \((4.55 \div 407859)+1.00098=1.00210\)
A supposedly gold crown is tested to determine its density. It displaces \(10.7 \mathrm{~mL}\) of water and has a mass of \(206 \mathrm{~g}\). Could the crown be made of gold?
What do you think about this solution?
We value your feedback to improve our textbook solutions.