Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

What is the effect of decreasing the concentration of a reactant in a reaction mixture at equilibrium?

Short Answer

Expert verified
Decreasing the concentration of a reactant causes the equilibrium to shift towards the reactant side, thereby increasing the rate of the reverse reaction to produce more reactant, which decreases the concentration of products.

Step by step solution

01

Understand Le Châtelier's Principle

First, recall Le Châtelier's Principle which states that if an external change is applied to a system at equilibrium, the system will adjust itself in such a way as to partially counteract that change.
02

Identify the Change in the System

Next, identify the change being described: the concentration of a reactant is being decreased.
03

Predict the Effect of Decreased Reactant Concentration

According to Le Châtelier's Principle, the equilibrium will shift to counteract the decrease in reactant concentration. This means the equilibrium will shift towards the side of the reaction where the reactant is located to increase its concentration again.
04

Analyze the Consequences of the Shift

When the equilibrium shifts towards the reactants side, the rate of the reverse reaction will increase, effectively producing more reactants. This results in a decrease in the concentration of the products as the equilibrium position moves.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Equilibrium
Chemical equilibrium is a dynamic state in which the rates of the forward and reverse reactions in a closed system are equal, resulting in no net change in the concentrations of reactants and products over time. It is essential to understand that at equilibrium, the reactions do not stop; instead, they continue to occur at equal rates. The equilibrium state is represented by the equilibrium constant (K_{eq}), which is a ratio expressing the relative concentrations of products to reactants at equilibrium under a specific set of conditions.

When a system reaches equilibrium, it is said to be balanced. However, if any changes are made to the conditions, such as temperature, pressure, or concentration of the reactants or products, the system will respond to restore a new equilibrium. This behavior is governed by Le Châtelier's Principle, a fundamental concept that predicts how a system at equilibrium reacts to disturbances.
Reactant Concentration
The concentration of reactants in a chemical reaction plays a vital role in the position of the equilibrium. When reactants are consumed during a reaction, they form products. Conversely, products can decompose into reactants through a reverse reaction. At equilibrium, these two processes occur at equal rates, which results in constant concentrations of both reactants and products.

In the context of Le Châtelier's Principle, a change in the concentration of a reactant will cause the equilibrium to adjust itself in an attempt to restore balance. This is because equilibrium is influenced not only by the inherent nature of the reaction but also by the relative amounts of substances present. Hence, changes in reactant concentration are a common way to manipulate a system in order to increase or decrease the yield of products.
Equilibrium Shift
An equilibrium shift occurs when a system that is at chemical equilibrium experiences a change in conditions, such as concentration, pressure, or temperature, causing it to adjust in an attempt to reach a new state of equilibrium. Le Châtelier's Principle allows us to predict the direction of this shift.

For example, if the concentration of a reactant is decreased, the system will respond by shifting the equilibrium toward the side of the reaction where the reactant is consumed, effectively increasing the rate of the reverse reaction. This shift allows for the production of more reactants, partially compensating for the decrease in their concentration. Similarly, any removal or addition of products or reactants will cause the equilibrium to shift in a way that tries to counter the change, thus maintaining the ratio defined by the equilibrium constant for that reaction.
Reverse Reaction
The reverse reaction in a chemical process is the reaction that converts the products back into the reactants. In an equilibrium situation, both the forward and reverse reactions are occurring simultaneously and at the same rate, which means there is no overall change in the concentrations of the reactants and products.

In response to a decrease in reactant concentration, Le Châtelier's Principle implies that the system will shift to increase the rate of the reverse reaction. This compensates for the loss of reactants by producing more of them from the available products, thereby working to restore equilibrium. Understanding the interplay between forward and reverse reactions is crucial for manipulating chemical reactions in industrial processes, pharmaceutical development, and various scientific research applications.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider the reaction. $$ \mathrm{Fe}^{3+}(a q)+\mathrm{SCN}^{-}(a q) \rightleftharpoons \mathrm{FeSCN}^{2+}(a q) $$ Asolution is made containing initial \(\left[\mathrm{Fe}^{3+}\right]=1.0 \times 10^{-3} \mathrm{M}\) and initial \(\left[\mathrm{SCN}^{-}\right]=8.0 \times 10^{-4} \mathrm{M}\). At equilibrium, \(\left[\mathrm{FeSCN}^{2+}\right]=1.7 \times 10^{-4} \mathrm{M}\). Calculate the value of the equilibrium constant. Hint: Use the chemical reaction stoichiometry to calculate the equilibrium concentrations of \(\mathrm{Fe}^{3+}\) and \(\mathrm{SCN}^{-}\).

For each equilibrium constant, indicate if you would expect an equilibrium reaction mixture to be dominated by reactants or by products, or to contain significant amounts of both. (a) \(K_{\mathrm{eq}}=5.2 \times 10^{17}\) (b) \(K_{\mathrm{eq}}=1.24\) (c) \(K_{\mathrm{eq}}=3.22 \times 10^{-21}\) (d) \(K_{\mathrm{eq}}=0.47\)

The solubility of nickel(II) carbonate at \(25^{\circ} \mathrm{C}\) is \(0.042 \mathrm{~g} / \mathrm{L}\). Calculate \(K_{\mathrm{sp}}\) for nickel(II) carbonate.

Consider this reaction at equilibrium. $$ 2 \operatorname{BrNO}(g) \rightleftharpoons 2 \mathrm{NO}(g)+\mathrm{Br}_{2}(g) $$ Predict the effect (shift right, shift left, or no effect) of these changes. (a) adding BrNO to the reaction mixture (b) adding NO to the reaction mixture (c) adding \(\mathrm{Br}_{2}\) to the reaction mixture

$$ 2 \mathrm{KClO}_{3}(s) \rightleftharpoons 2 \mathrm{KCl}(s)+3 \mathrm{O}_{2}(g) $$ Predict the effect (shift right, shift left, or no effect) of these changes. (a) adding \(\mathrm{KCl}\) to the reaction mixture (b) adding \(\mathrm{KClO}_{3}\) to the reaction mixture (c) adding \(\mathrm{O}_{2}\) to the reaction mixture (d) removing \(\mathrm{O}_{2}\) from the reaction mixture

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free