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What does a small equilibrium constant tell you about a reaction? A large equilibrium constant?

Short Answer

Expert verified
A small equilibrium constant suggests that the reaction favors the reactants, whereas a large equilibrium constant indicates that the reaction favors the products.

Step by step solution

01

Understanding Equilibrium Constant

The equilibrium constant (K) is a value that tells us the ratio of the concentrations of products to reactants at equilibrium. It gives an idea of the relative amounts of products and reactants present after the reaction has reached its equilibrium state.
02

Interpreting a Small Equilibrium Constant

If the equilibrium constant is small (much less than 1), it indicates that at equilibrium, the concentration of the reactants is much greater than the concentration of the products. This suggests that the reaction favors the reactants and does not proceed significantly towards the products.
03

Interpreting a Large Equilibrium Constant

On the other hand, if the equilibrium constant is large (much greater than 1), it implies that at equilibrium, the concentration of the products is much greater than the concentration of the reactants. This indicates that the reaction favors the formation of products and goes nearly to completion.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Equilibrium
In chemical reactions, the state of chemical equilibrium is reached when the rate at which the reactants convert into products is equal to the rate at which the products revert back to reactants. This dynamic equilibrium does not imply that the reactants and products are present in equal amounts, but rather that their concentrations have stabilized and remain constant over time.

At equilibrium, a reversible chemical reaction can proceed in both the forward (form products) and reverse (re-form reactants) directions, yet there is no net change in the concentration of either reactants or products. It's essential to understand that equilibrium is a balance of processes, not quantities. How far the reaction proceeds either towards the products or back to the reactants can be understood by evaluating the equilibrium constant of the reaction.
Reaction Quotient
The reaction quotient (Q) is a measure that tells you about the current state of a reaction—whether or not it has reached equilibrium. Defined similarly to the equilibrium constant, it involves the concentrations of the products and reactants at any given point in time.

The formula for the reaction quotient is akin to that of the equilibrium constant: \[ Q = \frac{[products]}{[reactants]} \]However, while the equilibrium constant only describes concentrations at equilibrium, Q can be calculated at any stage of the reaction. By comparing the reaction quotient (Q) to the equilibrium constant (K), you can predict the direction in which the reaction must proceed in order to reach equilibrium. If \( Q < K \), the reaction will shift forward to produce more products. Conversely, if \( Q > K \), the reaction will shift in the reverse direction, producing more reactants. This comparison provides crucial insight into the status and progress of a reaction.
Le Chatelier's Principle
Le Chatelier's principle provides a qualitative prediction about how a system at equilibrium will respond to external changes. If a stress is applied to a system in equilibrium, the system adjusts to partially counteract the imposed change and re-establish equilibrium.

Such stresses can include changes in concentration, temperature, or pressure. For instance, increasing the concentration of reactants will shift the equilibrium to produce more products, while increasing the temperature for an exothermic reaction will shift the equilibrium in favor of the reactants. Similarly, a pressure increase by reducing the volume of a gaseous system will favor the side with fewer gas molecules.)

The principle is a fundamental guideline in chemical processes, as it assists chemists in predicting the effects of varying conditions and is crucial for optimizing yields in industrial chemical reactions. In essence, Le Chatelier's principle helps you understand the resilience of chemical systems and the mechanisms by which they maintain equilibrium in the face of change.

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Most popular questions from this chapter

Consider the effect of a volume change on this reaction at equilibrium. $$ \mathrm{I}_{2}(g)+\mathrm{Cl}_{2}(g) \rightleftharpoons 2 \mathrm{ICl}(g) $$ Predict the effect (shift right, shift left, or no effect) of these changes. (a) increasing the reaction volume (b) decreasing the reaction volume

For each compound, write an equation showing how the compound dissolves in water and write an expression for \(K_{\text {sp }}\). (a) \(\mathrm{Mg}(\mathrm{OH})_{2}\) (b) \(\mathrm{FeCO}_{3}\) (c) \(\mathrm{PbS}\) (d) \(\mathrm{PbSO}_{4}\)

The solubility of \(\mathrm{CaCrO}_{4}\) at \(25^{\circ} \mathrm{C}\) is \(4.15 \mathrm{~g} / \mathrm{L}\). Calculate \(K_{\mathrm{sp}}\) for \(\mathrm{CaCrO}_{4}\).

Write an equilibrium expression for each chemical equation involving one or more solid or liquid reactants or products. (a) \(\mathrm{HCHO}_{2}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \rightleftharpoons \mathrm{H}_{3} \mathrm{O}^{+}(a q)+\mathrm{CHO}_{2}^{-}(a q)\) (b) \(\mathrm{CO}_{3}^{2-}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \rightleftharpoons \mathrm{HCO}_{3}^{-}(a q)+\mathrm{OH}^{-}(a q)\) (c) \(2 \mathrm{C}(s)+\mathrm{O}_{2}(g) \rightleftharpoons 2 \mathrm{CO}(g)\) (d) \(\mathrm{C}(s)+\mathrm{CO}_{2}(g) \rightleftharpoons 2 \mathrm{CO}(g)\)

Consider this reaction at equilibrium. $$ \mathrm{C}(s)+\mathrm{H}_{2} \mathrm{O}(g) \rightleftharpoons \mathrm{CO}(g)+\mathrm{H}_{2}(g) $$ Predict the effect (shift right, shift left, or no effect) of these changes. (a) adding \(C\) to the reaction mixture (b) condensing \(\mathrm{H}_{2} \mathrm{O}\) and removing it from the reaction mixture (c) adding \(\mathrm{CO}\) to the reaction mixture (d) removing \(\mathrm{H}_{2}\) from the reaction mixture

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