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When small quantities of elemental hydrogen gas are needed for laboratory work, the hydrogen is often generated by chemical reaction of a metal with acid. For example, zinc reacts with hydrochloric acid, releasing gaseous elemental hydrogen: $$\mathrm{Zn}(s)+2 \mathrm{HCl}(a q) \rightarrow \mathrm{ZnCl}_{2}(a q)+\mathrm{H}_{2}(g)$$ What mass of hydrogen gas is produced when \(2.50 \mathrm{g}\) of zinc is reacted with excess aqueous hydrochloric acid?

Short Answer

Expert verified
When 2.50 g of zinc reacts with excess aqueous hydrochloric acid, 0.077 g of hydrogen gas is produced.

Step by step solution

01

Write down the balanced chemical equation

The balanced chemical equation is: \( \mathrm{Zn}(s) + 2 \mathrm{HCl}(aq) \rightarrow \mathrm{ZnCl}_{2}(aq) + \mathrm{H}_{2}(g) \)
02

Find the molar mass of the substances involved in the reaction

Using the periodic table, we find the molar masses of the substances involved in the reaction: - Molar mass of Zn: 65.38 g/mol - Molar mass of H₂: 2.02 g/mol
03

Calculate the moles of zinc reacted

Use the molar mass of Zn to convert the mass of zinc reacted into moles: Moles of Zn = (Mass of Zn) / (Molar mass of Zn) = (2.50 g) / (65.38 g/mol) = 0.0383 mol
04

Use the stoichiometry of the balanced equation

From the equation, we know that one mole of zinc reacts to produce one mole of hydrogen gas: 1 mole Zn → 1 mole H₂ So, the moles of hydrogen gas produced is the same as the moles of zinc reacted, which is 0.0383 moles.
05

Calculate the mass of hydrogen gas produced

Use the molar mass of H₂ to convert moles of hydrogen gas produced to mass: Mass of H₂ = (Moles of H₂) * (Molar mass of H₂) = (0.0383 mol) * (2.02 g/mol) = 0.077 g Therefore, when 2.50 g of zinc reacts with excess aqueous hydrochloric acid, 0.077 g of hydrogen gas is produced.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Reactions
Understanding chemical reactions is fundamental to grasping various concepts in chemistry. A chemical reaction involves the transformation of one or more substances, known as reactants, into one or more different substances, known as products. This transformation occurs through the breaking and forming of chemical bonds.

As seen in the textbook exercise, zinc reacts with hydrochloric acid, a reaction that is critical for laboratory procedures that require elemental hydrogen gas. The hydrogen gas is not just a byproduct; it is essential in various scientific experiments. The chemical equation \( \text{Zn}(s) + 2 \text{HCl}(aq) \rightarrow \text{ZnCl}_2(aq) + \text{H}_2(g) \) illustrates a single replacement reaction where zinc displaces hydrogen in hydrochloric acid, leading to the creation of zinc chloride and hydrogen gas.

What makes this reaction particularly interesting is the 1:1 molar ratio between zinc and hydrogen gas, which becomes the basis for stoichiometric calculations. This ratio means that for every mole of zinc reacting, a mole of hydrogen gas is produced.
Molar Mass Calculation
The concept of molar mass is a cornerstone in stoichiometry, as it relates the mass of a substance to the amount of substance in moles. Calculating the molar mass of a substance requires knowing the atomic masses of the constituent elements and combining them according to the molecular formula.

For example, to find the molar mass of zinc \( \text{Zn} \), one would look up the atomic mass on the periodic table, which is approximately 65.38 g/mol. Similarly, hydrogen gas \( \text{H}_2 \) has a molar mass calculated by doubling the atomic mass of hydrogen since there are two hydrogen atoms in each molecule of hydrogen gas. Thus, the molar mass of \( \text{H}_2 \) is approximately 2.02 g/mol.

These numbers are not arbitrary; they represent the amount of the substance that contains Avogadro's number of molecules or atoms. In other words, one mole of any substance contains the same number of entities as there are atoms in exactly 12 grams of carbon-12.
Reacting Masses
Reacting masses in stoichiometry refer to the quantities of reactants and products involved in a chemical reaction, often measured in grams. Stoichiometric calculations allow us to predict the mass of a substance that will react or be produced in a chemical reaction based on the balanced chemical equation.

The key to these calculations is the mole ratio derived from the balanced equation. This is critical for problems where one needs to calculate the number of moles of each reactant needed to produce a given amount of product, or conversely, the amount of product generated from specific moles or masses of reactants.

In the case of the zinc and hydrochloric acid reaction given in the original exercise, one uses the molar mass of zinc to determine the moles of zinc reacted. Those moles, in turn, provide the ratio needed to calculate the mass of hydrogen gas produced. The solution is straightforward because the mole ratio is 1:1, illustrating the elegance and simplicity of stoichiometric principles in relating the reacting masses of substances through their molar equivalences.

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Most popular questions from this chapter

For each of the following balanced chemical equations, calculate how many moles and how many grams of each product would be produced by the complete conversion of 0.50 mol of the reactant indicated in boldface. State clearly the mole ratio used for each conversion. a. \(\mathbf{N} \mathbf{H}_{3}(g)+\mathrm{HCl}(g) \rightarrow \mathrm{NH}_{4} \mathrm{Cl}(s)\) b. \(\mathrm{CH}_{4}(g)+\mathbf{4} \mathbf{S}(s) \rightarrow \mathrm{CS}_{2}(l)+2 \mathrm{H}_{2} \mathrm{S}(g)\) c. \(\mathbf{P C I}_{3}+3 \mathrm{H}_{2} \mathrm{O}(l) \rightarrow \mathrm{H}_{3} \mathrm{PO}_{3}(a q)+3 \mathrm{HCl}(a q)\) d. \(\mathbf{N a O H}(s)+\mathrm{CO}_{2}(g) \rightarrow \mathrm{NaHCO}_{3}(s)\)

Using the average atomic masses given inside the front cover of this book, calculate how many moles of each substance the following masses represent. a. \(12.7 \mathrm{g}\) of hydrogen gas, \(\mathrm{H}_{2}\) b. \(5.2 \mathrm{g}\) of calcium hydride, \(\mathrm{CaH}_{2}\) c. 41.6 mg of potassium hydroxide, KOH d. \(6.93 \mathrm{g}\) of hydrogen sulfide, \(\mathrm{H}_{2} \mathrm{S}\) e. \(94.7 \mathrm{g}\) of water, \(\mathrm{H}_{2} \mathrm{O}\) f. 321 mg of lead g. 8.79 g of silver nitrate, \(\mathrm{AgNO}_{3}\)

The traditional method of analysis for the amount of chloride ion present in a sample was to dissolve the sample in water and then slowly to add a solution of silver nitrate. Silver chloride is very insoluble in water, and by adding a slight excess of silver nitrate, it is possible effectively to remove all chloride ion from the sample. $$ \mathrm{Ag}^{+}(a q)+\mathrm{Cl}^{-}(a q) \rightarrow \mathrm{AgCl}(s) $$ Suppose a \(1.054-\mathrm{g}\) sample is known to contain \(10.3 \%\) chloride ion by mass. What mass of silver nitrate must be used to completely precipitate the chloride ion from the sample? What mass of silver chloride will be obtained?

Silicon carbide, \(\mathrm{SiC},\) is one of the hardest materials known. Surpassed in hardness only by diamond, it is sometimes known commercially as carborundum. Silicon carbide is used primarily as an abrasive for sandpaper and is manufactured by heating common sand (silicon dioxide, \(\mathrm{SiO}_{2}\) ) with carbon in a furnace. $$\mathrm{SiO}_{2}(s)+\mathrm{C}(s) \rightarrow \mathrm{CO}(g)+\mathrm{SiC}(s)$$ What mass of silicon carbide should result when 1.0 kg of pure sand is heated with an excess of carbon?

Ammonium nitrate has been used as a high explosive because it is unstable and decomposes into several gaseous substances. The rapid expansion of the gaseous substances produces the explosive force. $$\mathrm{NH}_{4} \mathrm{NO}_{3}(s) \rightarrow \mathrm{N}_{2}(g)+\mathrm{O}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(g)$$ Calculate the mass of each product gas if \(1.25 \mathrm{g}\) of ammonium nitrate reacts.

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