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Explain how one determines which reactant in a process is the limiting reactant. Does this depend only on the masses of the reactant present? Is the mole ratio in which the reactants combine involved?

Short Answer

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To determine the limiting reactant in a chemical reaction, one must consider both the masses of the reactants present and the mole ratios in which they combine. First, calculate the amount of product that can be formed from the available amounts of each reactant by dividing the moles of each reactant by their respective coefficients in the balanced chemical equation. Then, compare the results to identify the limiting reactant - the reactant that yields the least amount of product. This reactant will be consumed first, limiting the reaction's progress.

Step by step solution

01

Review the Concept of Limiting Reactants

In a chemical reaction, the limiting reactant is the reactant that is completely consumed first and limits the extent of the reaction, determining the maximum amount of product that can be formed. Essentially, the reaction stops once the limiting reactant is used up.
02

Understand the Importance of Mole Ratios

Mole ratios refer to the ratio of moles of one reactant to the moles of another reactant involved in a chemical reaction. In a balanced chemical equation, the coefficients of the reactants represent their mole ratios. Mole ratios determine how reactants react with each other and are essential for calculating the expected amount of products formed.
03

Determine the Amount of Product Formed from Each Reactant

To determine which reactant is the limiting reactant, we first need to calculate the amount of product that can be formed from the available amounts of each reactant. To do this, divide the moles of each reactant by their respective coefficients in the balanced chemical equation. This will give the maximum amount of product that can be formed from each reactant.
04

Identify the Limiting Reactant

After calculating the maximum amount of product formed from each reactant, compare the results. The reactant that yields the least amount of product will be the limiting reactant. In other words, the limiting reactant is the reactant consumed completely in producing a smaller amount of product. In conclusion, determining the limiting reactant depends on both the masses of the reactants and the mole ratios in which they combine. By comparing the amounts of product that can be formed from each reactant's given moles and considering their mole ratios, we can determine which reactant will be consumed first and limit the reaction's progress.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Reaction
Every chemical reaction involves the transformation of reactants into products. To better understand this, imagine a recipe, where ingredients are the reactants and the dish is the product. A chemical reaction is an organized way of producing new substances from existing ones by rearranging atoms.
• During a reaction, bonds between atoms in the reactants are broken, and new bonds are formed to create the products.
• Reactions can be simple, involving just a few substances, or complex, with many reactants and products.
● In practice, some reactants may not react completely, leading us to the concept of limiting reactants. This is especially crucial in understanding how much product can be formed.
In summary, a chemical reaction is the process through which new substances are formed, defined by changes in atomic bonds. Understanding this helps set the stage for figuring out potential outcomes, like the amount of product formed, and is fundamental to answering the question of limiting reactants.
Mole Ratios
Mole ratios are crucial in analyzing any chemical reaction. Simply put, a mole ratio represents the ratio between the amounts of any two substances involved in a reaction. These ratios are derived from the coefficients found in a balanced chemical equation.

For example, consider the balanced reaction:
2H₂ + O₂ → 2H₂O
Here, the mole ratio of hydrogen to oxygen is 2:1, meaning for every 2 moles of hydrogen, 1 mole of oxygen is required.
• Mole ratios let us predict how reactants will react and how much of each is needed.
• It also helps in determining which reactant might run out first, thus becoming the limiting reactant.
In any analysis regarding chemical reactions, proper understanding of mole ratios ensures accurate predictions about the extent of the reaction, making them pivotal in calculations involving limiting reactants.
Balanced Chemical Equation
A balanced chemical equation is more than just a way to represent a chemical reaction. It is a crucial tool that shows the exact proportions in which elements or compounds react and form products.
• Balancing ensures the law of conservation of mass is upheld, meaning the mass of reactants equals the mass of products.
• In balancing, coefficients are adjusted to reflect the smallest whole number ratio of reactants and products. For example, the equation for the combustion of methane:
CH₄ + 2O₂ → CO₂ + 2H₂O
Here, balancing ensures 1 carbon, 4 hydrogen, and 4 oxygen atoms are on each side.
These coefficients are vital for calculating how much of each reactant is needed and what is produced, which is particularly important when determining the limiting reactant.
Balanced equations guide us in making accurate predictions and calculations in chemical reactions, confirming their status as science's blueprint for reaction analysis.

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Most popular questions from this chapter

An experiment that led to the formation of the new field of organic chemistry involved the synthesis of urea, \(\mathrm{CN}_{2} \mathrm{H}_{4} \mathrm{O},\) by the controlled reaction of ammonia and carbon dioxide: $$2 \mathrm{NH}_{3}(g)+\mathrm{CO}_{2}(g) \rightarrow \mathrm{CN}_{2} \mathrm{H}_{4} \mathrm{O}(s)+\mathrm{H}_{2} \mathrm{O}(l)$$ What is the theoretical yield of urea when \(100 .\) g of ammonia is reacted with \(100 .\) g of carbon dioxide?

Natural waters often contain relatively high levels of calcium ion, \(\mathrm{Ca}^{2+},\) and hydrogen carbonate ion (bicarbonate), \(\mathrm{HCO}_{3}^{-}\), from the leaching of minerals into the water. When such water is used commercially or in the home, heating of the water leads to the formation of solid calcium carbonate, \(\mathrm{CaCO}_{3}\) which forms a deposit ("scale") on the interior of boilers, pipes, and other plumbing fixtures. $$\mathrm{Ca}\left(\mathrm{HCO}_{3}\right)_{2}(a q) \rightarrow \mathrm{CaCO}_{3}(s)+\mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l)$$ If a sample of well water contains \(2.0 \times 10^{-3} \mathrm{mg}\) of \(\mathrm{Ca}\left(\mathrm{HCO}_{3}\right)_{2}\) per milliliter, what mass of \(\mathrm{CaCO}_{3}\) scale would \(1.0 \mathrm{mL}\) of this water be capable of depositing?

When the hydroxide compound of many metals is heated, water is driven off and the oxide of the metal remains. For example, if cobalt(II) hydroxide is heated, cobalt(II) oxide is produced. $$\mathrm{Co}(\mathrm{OH})_{2}(s) \rightarrow \operatorname{CoO}(s)+\mathrm{H}_{2} \mathrm{O}(g)$$ What mass of cobalt(II) oxide would remain if \(5.75 \mathrm{g}\) of cobalt(II) hydroxide were heated strongly?

Explain why, in the balanced chemical equation \(\mathrm{C}+\mathrm{O}_{2} \rightarrow \mathrm{CO}_{2},\) we know that \(1 \mathrm{g}\) of \(\mathrm{C}\) will not react exactly with \(1 \mathrm{g}\) of \(\mathrm{O}_{2}\).

Silicon carbide, \(\mathrm{SiC},\) is one of the hardest materials known. Surpassed in hardness only by diamond, it is sometimes known commercially as carborundum. Silicon carbide is used primarily as an abrasive for sandpaper and is manufactured by heating common sand (silicon dioxide, \(\mathrm{SiO}_{2}\) ) with carbon in a furnace. $$\mathrm{SiO}_{2}(s)+\mathrm{C}(s) \rightarrow \mathrm{CO}(g)+\mathrm{SiC}(s)$$ What mass of silicon carbide should result when 1.0 kg of pure sand is heated with an excess of carbon?

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