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What does it mean to say that the balanced chemical equation for a reaction describes the stoichiometry of the reaction?

Short Answer

Expert verified
A balanced chemical equation describes the stoichiometry of a reaction by providing quantitative relationships between reactants and products. It ensures that the number of atoms of each element on the reactant side is equal to the number on the product side, maintaining the law of conservation of mass. The coefficients in the balanced equation represent the molar ratios of reactants and products, allowing us to determine how much of each substance reacts and how much of each substance is produced during the reaction.

Step by step solution

01

Understanding stoichiometry

Stoichiometry refers to the quantitative relationship between reactants and products in a balanced chemical equation. It encompasses the study of how much of each reactant is consumed and how much of each product is formed during a chemical reaction.
02

Balanced chemical equation

A chemical equation is a representation of a chemical reaction, where reactants are written on the left side and products on the right side. The equation also provides information about the elemental composition and their relative quantities in a reaction. A balanced chemical equation ensures that the number of atoms of each element on the reactant side is equal to the number of atoms of that element on the product side, maintaining the law of conservation of mass.
03

Connecting stoichiometry and balanced chemical equation

A balanced chemical equation gives us the stoichiometry of a reaction. The coefficients in the balanced equation represent the molar ratios of the reactants and products, which help to determine how much of each substance reacts and how much of each substance is produced during the reaction. For instance, consider the balanced chemical equation for the reaction between hydrogen and oxygen to produce water: \[2H_2 + O_2 \rightarrow 2H_2O\] In this equation, the numbers in front of each molecule (called coefficients) represent the stoichiometric coefficients. According to the coefficients, two moles of hydrogen gas react with one mole of oxygen gas to produce two moles of water. So, when we say that the balanced chemical equation describes the stoichiometry of a reaction, it means that the equation provides us with the quantitative relationships between the reactants and products in a chemical reaction, allowing us to calculate how much of each substance is needed or produced.

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Most popular questions from this chapter

Using the average atomic masses given inside the front cover of the text, calculate how many moles of each substance the following masses represent. a. \(4.21 \mathrm{g}\) of copper(II) sulfate b. \(7.94 \mathrm{g}\) of barium nitrate c. \(1.24 \mathrm{mg}\) of water d. 9.79 g of tungsten e. 1.45 lb of sulfur f. 4.65 g of ethyl alcohol, \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\) g. \(12.01 \mathrm{g}\) of carbon

What quantity serves as the conversion factor between the mass of a sample and how many moles the sample contains?

When elemental carbon is burned in the open atmosphere, with plenty of oxygen gas present, the product is carbon dioxide. $$\mathrm{C}(s)+\mathrm{O}_{2}(g) \rightarrow \mathrm{CO}_{2}(g)$$ However, when the amount of oxygen present during the burning of the carbon is restricted, carbon monoxide is more likely to result. $$2 \mathrm{C}(s)+\mathrm{O}_{2}(g) \rightarrow 2 \mathrm{CO}(g)$$What mass of each product is expected when a \(5.00-\mathrm{g}\) sample of pure carbon is burned under each of these conditions?

For each of the following incomplete and unbalanced equations, indicate how many moles of the second reactant would be required to react completely with 0.145 mol of the first reactant. a. \(\mathrm{BaCl}_{2}(a q)+\mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow\) b. \(\operatorname{AgNO}_{3}(a q)+\operatorname{NaCl}(a q) \rightarrow\) c. \(\operatorname{Pb}\left(\mathrm{NO}_{3}\right)_{2}(a q)+\mathrm{Na}_{2} \mathrm{CO}_{3}(a q) \rightarrow\) d. \(C_{3} \mathrm{H}_{8}(g)+\mathrm{O}_{2}(g) \rightarrow\)

A favorite demonstration among chemistry instructors, to show that the properties of a compound differ from those of its constituent elements, involves iron filings and powdered sulfur. If the instructor takes samples of iron and sulfur and just mixes them together, the two elements can be separated from one another with a magnet (iron is attracted to a magnet, sulfur is not). If the instructor then combines and heats the mixture of iron and sulfur, a reaction takes place and the elements combine to form iron(II) sulfide (which is not attracted by a magnet). $$\mathrm{Fe}(s)+\mathrm{S}(s) \rightarrow \mathrm{FeS}(s)$$ Suppose \(5.25 \mathrm{g}\) of iron filings is combined with \(12.7 \mathrm{g}\) of sulfur. What is the theoretical yield of iron(II) sulfide?

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