Chapter 9: Problem 1
What do the coefficients of a balanced chemical equation tell us about the proportions in which atoms and molecules react on an individual (microscopic) basis?
Chapter 9: Problem 1
What do the coefficients of a balanced chemical equation tell us about the proportions in which atoms and molecules react on an individual (microscopic) basis?
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Get started for freeFor each of the following unbalanced equations, suppose that exactly \(1.00 \mathrm{g}\) of each reactant is taken. Determine which reactant is limiting, and calculate what mass of the product in boldface is expected (assuming that the limiting reactant is completely consumed). a. \(\mathrm{CS}_{2}(l)+\mathrm{O}_{2}(g) \rightarrow \mathbf{C} \mathbf{O}_{2}(g)+\mathrm{SO}_{2}(g)\) b. \(\mathrm{NH}_{3}(g)+\mathrm{CO}_{2}(g) \rightarrow \mathrm{CN}_{2} \mathrm{H}_{4} \mathrm{O}(s)+\mathbf{H}_{2} \mathbf{O}(g)\) c. \(\mathrm{H}_{2}(g)+\mathrm{MnO}_{2}(s) \rightarrow \mathrm{MnO}(s)+\mathbf{H}_{2} \mathbf{O}(g)\) d. \(\mathrm{I}_{2}(l)+\mathrm{Cl}_{2}(g) \rightarrow \mathbf{I C l}(g)\)
One method for chemical analysis involves finding some reagent that will precipitate the species of interest. The mass of the precipitate is then used to determine what mass of the species of interest was present in the original sample. For example, calcium ion can be precipitated from solution by addition of sodium oxalate. The balanced equation is $$\mathrm{Ca}^{2+}(a q)+\mathrm{Na}_{2} \mathrm{C}_{2} \mathrm{O}_{4}(a q) \rightarrow \mathrm{CaC}_{2} \mathrm{O}_{4}(s)+2 \mathrm{Na}^{+}(a q)$$ Suppose a solution is known to contain approximately 15 g of calcium ion. Show by calculation whether the addition of a solution containing \(15 \mathrm{g}\) of sodium oxalate will precipitate all of the calcium from the sample.
Using the average atomic masses given inside the front cover of the text, calculate the mass in grams of each of the following samples. a. 5.0 mol of nitric acid b. 0.000305 mol of mercury c. \(2.31 \times 10^{-5}\) mol of potassium chromate d. 10.5 mol of aluminum chloride e. \(4.9 \times 10^{4}\) mol of sulfur hexafluoride f. 125 mol of ammonia g. 0.01205 mol of sodium peroxide
The more reactive halogen elements are able to replace the less reactive halogens from their compounds. $$\begin{array}{l} \mathrm{Cl}_{2}(g)+\mathrm{NaI}(a q) \rightarrow \mathrm{NaCl}(a q)+\mathrm{I}_{2}(s) \\ \mathrm{Br}_{2}(l)+\mathrm{NaI}(a q) \rightarrow \mathrm{NaBr}(a q)+\mathrm{I}_{2}(s) \end{array}$$ Suppose separate solutions each containing \(25.0 \mathrm{g}\) of NaI are available. If \(5.00 \mathrm{g}\) of \(\mathrm{Cl}_{2}\) gas is bubbled into one NaI solution, and \(5.00 \mathrm{g}\) of liquid bromine is added to the other, calculate the number of grams of elemental iodine produced in each case.
For each of the following unbalanced chemical equations, suppose that exactly \(5.00 \mathrm{g}\) of each reactant is taken. Determine which reactant is limiting, and calculate what mass of each product is expected (assuming that the limiting reactant is completely consumed). a. \(\mathrm{S}(s)+\mathrm{H}_{2} \mathrm{SO}_{4}(a q) \rightarrow \mathrm{SO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l)\) b. \(\operatorname{MnO}_{2}(s)+\mathrm{H}_{2} \mathrm{SO}_{4}(l) \rightarrow \mathrm{Mn}\left(\mathrm{SO}_{4}\right)_{2}(s)+\mathrm{H}_{2} \mathrm{O}(l)\) c. \(\mathrm{H}_{2} \mathrm{S}(g)+\mathrm{O}_{2}(g) \rightarrow \mathrm{SO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(l)\) d. \(\mathrm{AgNO}_{3}(a q)+\mathrm{Al}(s) \rightarrow \mathrm{Ag}(s)+\mathrm{Al}\left(\mathrm{NO}_{3}\right)_{3}(a q)\)
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