Chapter 8: Problem 104
Although exact isotopic masses are known with great precision for most elements, we use the average mass of an element's atoms in most chemical calculations. Explain.
Chapter 8: Problem 104
Although exact isotopic masses are known with great precision for most elements, we use the average mass of an element's atoms in most chemical calculations. Explain.
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Get started for freeA compound has the following percentages by mass: aluminum, 32.13\%; fluorine, 67.87\%. Calculate the empirical formula of the compound.
Calculate the mass of carbon in grams, the percent carbon by mass, and the number of individual carbon atoms present in each of the following samples. a. 7.819 g of carbon suboxide, \(\mathrm{C}_{3} \mathrm{O}_{2}\) b. \(1.53 \times 10^{21}\) molecules of carbon monoxide c. 0.200 mol of phenol, \(C_{6} \mathrm{H}_{6} \mathrm{O}\)
A \(0.7221-g\) sample of a new compound has been analyzed and found to contain the following masses of elements: carbon, 0.2990 g; hydrogen, 0.05849 g; nitrogen, 0.2318 g; oxygen, 0.1328 g. Calculate the empirical formula of the compound.
Calculate the number of atoms of each element present in each of the following samples. a. 4.21 g of water b. \(6.81 \mathrm{g}\) of carbon dioxide c. \(0.000221 \mathrm{g}\) of benzene, \(\mathrm{C}_{6} \mathrm{H}_{6}\) d. \(2.26 \mathrm{mol}\) of \(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\)
A binary compound of boron and hydrogen has the following percentage composition: \(78.14\%\) boron, \(21.86 \%\) hydrogen. If the molar mass of the compound is determined by experiment to be between 27 and 28 g, what are the empirical and molecular formulas of the compound?
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