Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Most sulfide compounds of the transition metals are insoluble in water. Many of these metal sulfides have striking and characteristic colors by which we can identify them. Therefore, in the analysis of mixtures of metal ions, it is very common to precipitate the metal ions by using dihydrogen sulfide (commonly called hydrogen sulfide), \(\mathrm{H}_{2} \mathrm{S}\). Suppose you had a mixture of \(\mathrm{Fe}^{2+}, \mathrm{Cr}^{3+},\) and \(\mathrm{Ni}^{2+} .\) Write net ionic equations for the precipitation of these metal ions by the use of \(\mathrm{H}_{2} \mathrm{S}\).

Short Answer

Expert verified
The net ionic equations for the precipitation of the given metal ions with hydrogen sulfide are: 1. For the precipitation of Fe²⁺: \[ Fe^{2+}(aq) + H_{2}S(g) \rightarrow FeS(s) + 2 H^{+}(aq) \] 2. For the precipitation of Cr³⁺: \[ 2 Cr^{3+}(aq) + 3 H_{2}S(g) \rightarrow Cr_{2}S_{3}(s) + 6 H^{+}(aq) \] 3. For the precipitation of Ni²⁺: \[ Ni^{2+}(aq) + H_{2}S(g) \rightarrow NiS(s) + 2 H^{+}(aq) \]

Step by step solution

01

Precipitation Reaction of Fe²⁺ with H₂S

When Fe²⁺ reacts with hydrogen sulfide (H₂S), it results in the formation of precipitates of iron(II) sulfide (FeS). The balanced molecular equation for this reaction is: \[ Fe^{2+}(aq) + H_{2}S(g) \rightarrow FeS(s) + 2 H^+(aq) \] Now, we write the complete ionic equation and then cancel the common spectator ions to obtain the net ionic equation.
02

Net Ionic Equation for the Precipitation of Fe²⁺ with H₂S

The complete ionic equation for this reaction is: \[ Fe^{2+}(aq) + H_{2}S(g) \rightarrow FeS(s) + 2 H^{+}(aq) \] Since there are no spectator ions in this equation, the net ionic equation is the same as the complete ionic equation: \[ Fe^{2+}(aq) + H_{2}S(g) \rightarrow FeS(s) + 2 H^{+}(aq) \]
03

Precipitation Reaction of Cr³⁺ with H₂S

When Cr³⁺ reacts with hydrogen sulfide (H₂S), it results in the formation of precipitates of chromium(III) sulfide (Cr₂S₃). The balanced molecular equation for this reaction is: \[ 2 Cr^{3+}(aq) + 3 H_{2}S(g) \rightarrow Cr_{2}S_{3}(s) + 6 H^{+}(aq) \] Now, we write the complete ionic equation and then cancel the common spectator ions to obtain the net ionic equation.
04

Net Ionic Equation for the Precipitation of Cr³⁺ with H₂S

The complete ionic equation for this reaction is: \[ 2 Cr^{3+}(aq) + 3 H_{2}S(g) \rightarrow Cr_{2}S_{3}(s) + 6 H^{+}(aq) \] Since there are no spectator ions in this equation, the net ionic equation is the same as the complete ionic equation: \[ 2 Cr^{3+}(aq) + 3 H_{2}S(g) \rightarrow Cr_{2}S_{3}(s) + 6 H^{+}(aq) \]
05

Precipitation Reaction of Ni²⁺ with H₂S

When Ni²⁺ reacts with hydrogen sulfide (H₂S), it results in the formation of precipitates of nickel(II) sulfide (NiS). The balanced molecular equation for this reaction is: \[ Ni^{2+}(aq) + H_{2}S(g) \rightarrow NiS(s) + 2 H^{+}(aq) \] Now, we write the complete ionic equation and then cancel the common spectator ions to obtain the net ionic equation.
06

Net Ionic Equation for the Precipitation of Ni²⁺ with H₂S

The complete ionic equation for this reaction is: \[ Ni^{2+}(aq) + H_{2}S(g) \rightarrow NiS(s) + 2 H^{+}(aq) \] Since there are no spectator ions in this equation, the net ionic equation is the same as the complete ionic equation: \[ Ni^{2+}(aq) + H_{2}S(g) \rightarrow NiS(s) + 2 H^{+}(aq) \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Transition Metal Sulfides
Transition metal sulfides are formed when transition metals react with sulfide ions. These compounds are typically insoluble in water and often appear in striking and distinctive colors. This makes them useful for identifying specific metal ions in chemical analysis. For example:
  • Iron(II) sulfide (FeS): formed when iron ions react with sulfide ions, usually appearing as a black precipitate.
  • Chromium(III) sulfide (Cr₂S₃): created from chromium ions and sulfide, known for its dark green color.
  • Nickel(II) sulfide (NiS): composed of nickel ions and sulfide, typically forms a black or brown-black presence.
The precipitation of these sulfides occurs because the individual ions combine to create a solid that separates from the solution. The colorful nature of these precipitates can help in the visual detection and analysis of metal ions.
Precipitation Reactions
Precipitation reactions are a type of chemical reaction in which two soluble ions in solution react to form an insoluble solid called a precipitate. In the context of sulfide chemistry, this occurs when metal ions such as \[ Fe^{2+}, Cr^{3+}, \text{and} Ni^{2+} \] react with hydrogen sulfide (\[ H_{2}S \]).The process often follows these steps:
  • Mix solutions containing metal ions with \[ H_{2}S \] gas.
  • Sulfide ions (\[ S^{2-} \]) from \[ H_{2}S \] react with metal ions.
  • A solid precipitate forms, removing these ions from the solution.
  • The net ionic equations for these reactions do not include spectator ions, showing only the ions directly involved in forming the precipitate.
Using precipitation reactions, chemists can separate and identify specific ions based on their unique precipitates. This makes them especially valuable in analytical chemistry.
Hydrogen Sulfide Chemistry
Hydrogen sulfide (H₂S) is a colorless gas with a distinct rotten egg smell. In aqueous solutions, it behaves as a weak acid and dissociates to release sulfide ions (\[ S^{2-} \]), which are critical in forming metal sulfide precipitates.Here are some key aspects:
  • Weak Acid Behavior: Hydrogen sulfide only partially dissociates in water, providing sulfide ions needed for precipitation reactions.
  • Role in Reactions: Acts as a reagent to supply \[ S^{2-} \] ions for reactions with transition metal ions.
  • Environmental Presence: Found naturally in environments such as volcanic gases and in the breakdown of organic matter, often posing a hazard due to its toxicity and flammability.
Despite its simplicity, hydrogen sulfide is crucial in analytical and industrial processes that require the formation of metal sulfides.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

When aqueous solutions of sodium chloride, \(\mathrm{NaCl}\) and silver nitrate, \(\mathrm{AgNO}_{3}\), are mixed, a precipitate forms, but this precipitate is not sodium nitrate. What does this reaction tell you about the solubility of \(\mathrm{NaNO}_{3}\) in water?

A reaction in which a compound reacts rapidly with elemental oxygen, usually with the release of heat or light, is referred to as a ______ reaction.

Balance each of the following equations that describe decomposition reactions. a. \(\operatorname{CaSO}_{4}(s) \rightarrow \mathrm{CaO}(s)+\mathrm{SO}_{3}(g)\) b. \(\mathrm{Li}_{2} \mathrm{CO}_{3}(s) \rightarrow \mathrm{Li}_{2} \mathrm{O}(s)+\mathrm{CO}_{2}(g)\) c. \(\operatorname{LiHCO}_{3}(s) \rightarrow \mathrm{Li}_{2} \mathrm{CO}_{3}(s)+\mathrm{H}_{2} \mathrm{O}(g)+\mathrm{CO}_{2}(g)\) d. \(C_{6} H_{6}(l) \rightarrow C(s)+H_{2}(g)\) e. \(\operatorname{PBr}_{3}(l) \rightarrow \mathrm{P}_{4}(s)+\mathrm{Br}_{2}(l)\)

Identify each of the following unbalanced reaction equations as belonging to one or more of the following categories: precipitation, acid-base, or oxidation-reduction. a. \(\mathrm{H}_{2} \mathrm{O}_{2}(a q) \rightarrow \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{O}_{2}(g)\) b. \(\mathrm{H}_{2} \mathrm{SO}_{4}(a q)+\mathrm{Cu}(s) \rightarrow \mathrm{CuSO}_{4}(a q)+\mathrm{H}_{2}(g)\) c. \(\mathrm{H}_{2} \mathrm{SO}_{4}(a q)+\mathrm{NaOH}(a q) \rightarrow \mathrm{Na}_{2} \mathrm{SO}_{4}(a q)+\mathrm{H}_{2} \mathrm{O}(l)\) d. \(\mathrm{H}_{2} \mathrm{SO}_{4}(a q)+\mathrm{Ba}(\mathrm{OH})_{2}(a q) \rightarrow \mathrm{BaSO}_{4}(s)+\mathrm{H}_{2} \mathrm{O}(l)\) e. \(\mathrm{AgNO}_{3}(a q)+\mathrm{CuCl}_{2}(a q) \rightarrow \mathrm{Cu}\left(\mathrm{NO}_{3}\right)_{2}(a q)+\) \(\mathrm{AgCl}(s)\) f. \(\mathrm{KOH}(a q)+\mathrm{CuSO}_{4}(a q) \rightarrow \mathrm{Cu}(\mathrm{OH})_{2}(s)+\mathrm{K}_{2} \mathrm{SO}_{4}(a q)\) g. \(\mathrm{Cl}_{2}(g)+\mathrm{F}_{2}(g) \rightarrow \operatorname{ClF}(g)\) h. \(\mathrm{NO}(g)+\mathrm{O}_{2}(g) \rightarrow \mathrm{NO}_{2}(g)\) i. \(\mathrm{Ca}(\mathrm{OH})_{2}(s)+\mathrm{HNO}_{3}(a q) \rightarrow \mathrm{Ca}\left(\mathrm{NO}_{3}\right)_{2}(a q)+\mathrm{H}_{2} \mathrm{O}(l)\)

Classify the reactions represented by the following unbalanced equations by as many methods as possible. Balance the equations. a. \(\mathrm{I}_{4} \mathrm{O}_{9}(s) \rightarrow \mathrm{I}_{2} \mathrm{O}_{6}(s)+\mathrm{I}_{2}(s)+\mathrm{O}_{2}(g)\) b. \(\mathrm{Mg}(s)+\mathrm{AgNO}_{3}(a q) \rightarrow \mathrm{Mg}\left(\mathrm{NO}_{3}\right)_{2}(a q)+\mathrm{Ag}(s)\) c. \(\operatorname{SiCl}_{4}(l)+\operatorname{Mg}(s) \rightarrow \operatorname{MgCl}_{2}(s)+\operatorname{Si}(s)\) d. \(\mathrm{CuCl}_{2}(a q)+\mathrm{AgNO}_{3}(a q) \rightarrow\) \(\mathrm{Cu}\left(\mathrm{NO}_{3}\right)_{2}(a q)+\mathrm{AgCl}(s)\) e. \(\mathrm{Al}(s)+\mathrm{Br}_{2}(l) \rightarrow \mathrm{AlBr}_{3}(s)\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free