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Complete and balance each of the following molecular equations for strong acid/strong base reactions. Underline the formula of the salt produced in each reaction. a. \(\mathrm{HNO}_{3}(a q)+\mathrm{KOH}(a q) \rightarrow\) b. \(\mathrm{H}_{2} \mathrm{SO}_{4}(a q)+\mathrm{Ba}(\mathrm{OH})_{2}(a q) \rightarrow\) c. \(\mathrm{HClO}_{4}(a q)+\mathrm{NaOH}(a q) \rightarrow\) d. \(\mathrm{HCl}(a q)+\mathrm{Ca}(\mathrm{OH})_{2}(a q) \rightarrow\)

Short Answer

Expert verified
a. \( HNO_{3}(aq) + KOH(aq) \rightarrow \underline{KNO_{3}(aq)} + H_{2}O(l) \) b. \( H_{2}SO_{4}(aq) + Ba(OH)_{2}(aq) \rightarrow \underline{BaSO_{4}(aq)} + 2H_{2}O(l) \) c. \( HClO_{4}(aq) + NaOH(aq) \rightarrow \underline{NaClO_{4}(aq)} + H_{2}O(l) \) d. \( 2HCl(aq) + Ca(OH)_{2}(aq) \rightarrow \underline{CaCl_{2}(aq)} + 2H_{2}O(l) \)

Step by step solution

01

a. HNO3(aq) + KOH(aq) ->

In this reaction, the strong acid is nitric acid (HNO3) and the strong base is potassium hydroxide (KOH). The general form of an acid-base reaction is: Acid + Base -> Salt + Water In this case, the hydrogen ion (H⁺) from nitric acid reacts with the hydroxide ion (OH⁻) from potassium hydroxide to form water (H2O), and the remaining ions form the salt. \( HNO_{3}(aq) + KOH(aq) \rightarrow KNO_{3}(aq) + H_{2}O(l) \) Here, the salt produced is potassium nitrate (KNO3). This reaction is already balanced.
02

b. H2SO4(aq) + Ba(OH)2(aq) ->

In this reaction, the strong acid is sulfuric acid (H2SO4) and the strong base is barium hydroxide (Ba(OH)2). Following the general form of an acid-base reaction: \( H_{2}SO_{4}(aq) + Ba(OH)_{2}(aq) \rightarrow BaSO_{4}(aq) + 2H_{2}O(l) \) Here, the salt produced is barium sulfate (BaSO4). This reaction is already balanced.
03

c. HClO4(aq) + NaOH(aq) ->

In this reaction, the strong acid is perchloric acid (HClO4) and the strong base is sodium hydroxide (NaOH). Following the general form of an acid-base reaction: \( HClO_{4}(aq) + NaOH(aq) \rightarrow NaClO_{4}(aq) + H_{2}O(l) \) Here, the salt produced is sodium perchlorate (NaClO4). This reaction is already balanced.
04

d. HCl(aq) + Ca(OH)2(aq) ->

In this reaction, the strong acid is hydrochloric acid (HCl) and the strong base is calcium hydroxide (Ca(OH)2). Following the general form of an acid-base reaction: \( 2HCl(aq) + Ca(OH)_{2}(aq) \rightarrow CaCl_{2}(aq) + 2H_{2}O(l) \) Here, the salt produced is calcium chloride (CaCl2). We had to balance this reaction by adding a coefficient of 2 in front of HCl and H2O.

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Most popular questions from this chapter

What is an oxidation-reduction reaction? What is transferred during such a reaction?

Balance each of the following oxidation-reduction reactions. In each, indicate which substance is being oxidized and which is being reduced. a. \(\mathrm{Na}(s)+\mathrm{S}(s) \rightarrow \mathrm{Na}_{2} \mathrm{S}(s)\) b. \(\operatorname{Mg}(s)+\mathrm{O}_{2}(g) \rightarrow \mathrm{MgO}(s)\) c. \(\mathrm{Ca}(s)+\mathrm{F}_{2}(g) \rightarrow \mathrm{CaF}_{2}(s)\) d. \(\operatorname{Fe}(s)+\mathrm{Cl}_{2}(g) \rightarrow \operatorname{Fe} \mathrm{Cl}_{3}(s)\)

By now, you are familiar with enough chemical compounds to begin to write your own chemical reaction equations. Write two examples each of what we mean by a synthesis reaction and by a decomposition reaction.

Many plants are poisonous because their stems and leaves contain oxalic acid, \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4},\) or sodium oxalate, \(\mathrm{Na}_{2} \mathrm{C}_{2} \mathrm{O}_{4} ;\) when ingested, these substances cause swelling of the respiratory tract and suffocation. A standard analysis for determining the amount of oxalate ion, \(\mathrm{C}_{2} \mathrm{O}_{4}^{2-},\) in a sample is to precipitate this species as calcium oxalate, which is insoluble in water. Write the net ionic equation for the reaction between sodium oxalate and calcium chloride, \(\mathrm{CaCl}_{2},\) in aqueous solution.

When aqueous solutions of sodium chloride, \(\mathrm{NaCl}\) and silver nitrate, \(\mathrm{AgNO}_{3}\), are mixed, a precipitate forms, but this precipitate is not sodium nitrate. What does this reaction tell you about the solubility of \(\mathrm{NaNO}_{3}\) in water?

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