Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

If a sample of pure hydrogen gas is ignited very carefully, the hydrogen burns gently, combining with the oxygen gas of the air to form water vapor. Write the unbalanced chemical equation for this reaction.

Short Answer

Expert verified
The balanced chemical equation for the combustion of hydrogen gas with oxygen gas to form water vapor is: \[ 2H_{2} + O_{2} \rightarrow 2H_{2}O \]

Step by step solution

01

Identify the reactants and products

In this reaction, hydrogen (H2) and oxygen (O2) are the reactants, and the product is water vapor (H2O). Step 2: Writing the unbalanced equation
02

Write the chemical symbols for the reactants and products

Now that we know the reactants and products, we can write the unbalanced chemical equation: \[ H_{2} + O_{2} \rightarrow H_{2}O \] Step 3: Balancing the chemical equation
03

Adjust the coefficients to balance the equation

Currently, the equation is not balanced because there are two oxygen atoms on the left side of the equation and only one on the right side. To balance the equation, we can adjust the coefficients. Place a 2 in front of H2O: \[ H_{2} + O_{2} \rightarrow 2H_{2}O \] Now we have 2 hydrogen atoms on the left and 4 on the right. To balance the hydrogen atoms, place a 2 in front of H2: \[ 2H_{2} + O_{2} \rightarrow 2H_{2}O \] The balanced equation should look like this: \[ 2H_{2} + O_{2} \rightarrow 2H_{2}O \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free