Chapter 16: Problem 55
Why does the amount of excess solid solute present in a solution not affect the amount of solute that ultimately dissolves in a given amount of solvent?
Chapter 16: Problem 55
Why does the amount of excess solid solute present in a solution not affect the amount of solute that ultimately dissolves in a given amount of solvent?
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Get started for freeFor the reaction $$2 \mathrm{H}_{2} \mathrm{O}(g) \rightleftharpoons 2 \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g)$$ \(K=2.4 \times 10^{-3}\) at a given temperature. At equilibrium it is found that \(\left[\mathrm{H}_{2} \mathrm{O}(g)\right]=1.1 \times 10^{-1} \mathrm{M}\) and \(\left[\mathrm{H}_{2}(g)\right]=1.9 \times 10^{-2} \mathrm{M} .\) What is the concentration of \(\mathrm{O}_{2}(g)\) under these conditions?
Write the equilibrium expression for each of the following reactions. a. \(\mathrm{H}_{2}(g)+\mathrm{Br}_{2}(g) \rightleftharpoons 2 \mathrm{HBr}(g)\) b. \(2 \mathrm{H}_{2}(g)+\mathrm{S}_{2}(g) \rightleftharpoons 2 \mathrm{H}_{2} \mathrm{S}(g)\) c. \(\mathrm{H}_{2}(g)+\mathrm{C}_{2} \mathrm{N}_{2}(g) \rightleftharpoons 2 \mathrm{HCN}(g)\)
When a chemical system has reached equilibrium, the concentrations of all reactants and products remain ____ with time.
Consider the reaction $$2 \operatorname{CO}(g)+\mathrm{O}_{2}(g)=2 \operatorname{CO}_{2}(g)$$ Suppose the system is already at equilibrium, and then an additional mole of \(\mathrm{CO}(g)\) is injected into the system at constant temperature. Does the amount of \(\mathrm{CO}_{2}(g)\) in the system increase or decrease? Does the value of \(K\) for the reaction change?
How does the collision model account for the fact that a reaction proceeds faster when the concentrations of the reactants are increased?
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