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What volume does 35 moles of \(\mathrm{N}_{2}\) occupy at STP?

Short Answer

Expert verified
The volume occupied by 35 moles of N₂ at STP is 784 liters.

Step by step solution

01

Convert moles of N₂ to moles of an ideal gas at STP

To find the volume, we will convert the given moles of N₂ to moles of an ideal gas under the STP condition. The given moles of N₂ are 35 moles.
02

Use the molar volume at STP to determine the volume

The molar volume of an ideal gas at STP is 22.4 L/mol. Thus, using this value, we will calculate the volume of N₂ at STP. The formula to calculate the volume is: Volume = moles * molar volume at STP
03

Calculate the volume of N₂ at STP

Now, we will plug the values into the formula to calculate the volume: \( Volume = 35\ moles * 22.4\ L/mol \) \( Volume = 784\ L \) The volume occupied by 35 moles of N₂ at STP is 784 liters.

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Most popular questions from this chapter

A sample of oxygen gas is collected by displacement of water at \(25^{\circ} \mathrm{C}\) and 1.02 atm total pressure. If the vapor pressure of water is \(23.756 \mathrm{mm} \mathrm{Hg}\) at \(25^{\circ} \mathrm{C}\) what is the partial pressure of the oxygen gas in the sample?

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