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Give the total number of valence electrons in each of the following molecules. a. \(\mathrm{CBr}_{4}\) b. \(\mathrm{NO}_{2}\) c. \(C_{6} H_{6}\) d. \(\mathrm{H}_{2} \mathrm{O}_{2}\)

Short Answer

Expert verified
The total number of valence electrons in each molecule are as follows: a. \(\mathrm{CBr}_{4}\): 32 valence electrons b. \(\mathrm{NO}_{2}\): 17 valence electrons c. \(C_{6} H_{6}\): 30 valence electrons d. \(\mathrm{H}_{2} \mathrm{O}_{2}\): 14 valence electrons

Step by step solution

01

Identify the valence electrons of each atom in the molecule

First, we need to identify the number of valence electrons for each atom in the molecule. Carbon (C) has 4 valence electrons, and bromine (Br) has 7 valence electrons.
02

Calculate the total valence electrons

Now, we can calculate the total valence electrons in the molecule by adding the valence electrons of each atom, multiplied by the number of atoms in the molecule: \(1 \times 4 + 4 \times 7 = 4 + 28 = 32\). Therefore, there are 32 valence electrons in \(\mathrm{CBr}_{4}\). #b. \(\mathrm{NO}_{2}\)#
03

Identify the valence electrons of each atom in the molecule

For this molecule, nitrogen (N) has 5 valence electrons, and oxygen (O) has 6 valence electrons.
04

Calculate the total valence electrons

We can calculate the total valence electrons in the molecule by adding the valence electrons of each atom, multiplied by the number of atoms in the molecule: \(1 \times 5 + 2 \times 6 = 5 + 12 = 17\). Therefore, there are 17 valence electrons in \(\mathrm{NO}_{2}\). #c. \(C_{6} H_{6}\)#
05

Identify the valence electrons of each atom in the molecule

In this molecule, carbon (C) has 4 valence electrons, and hydrogen (H) has 1 valence electron.
06

Calculate the total valence electrons

We can calculate the total valence electrons in the molecule by adding the valence electrons of each atom, multiplied by the number of atoms in the molecule: \(6 \times 4 + 6 \times 1 = 24 + 6 = 30\). Therefore, there are 30 valence electrons in \(C_{6} H_{6}\). #d. \(\mathrm{H}_{2} \mathrm{O}_{2}\)#
07

Identify the valence electrons of each atom in the molecule

For this molecule, hydrogen (H) has 1 valence electron, and oxygen (O) has 6 valence electrons.
08

Calculate the total valence electrons

We can calculate the total valence electrons in the molecule by adding the valence electrons of each atom, multiplied by the number of atoms in the molecule: \(2 \times 1 + 2 \times 6 = 2 + 12 = 14\). Therefore, there are 14 valence electrons in \(\mathrm{H}_{2} \mathrm{O}_{2}\).

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Most popular questions from this chapter

What is the geometric structure of the water molecule? How many pairs of valence electrons are there on the oxygen atom in the water molecule? What is the approximate \(\mathrm{H}-\mathrm{O}-\mathrm{H}\) bond angle in water?

On the basis of their electron configurations, predict the formula of the simple binary ionic compounds likely to form when the following pairs of elements react with each other. a. aluminum, Al, and sulfur, S b. radium, \(\mathrm{Ra}\), and oxygen, \(\mathrm{O}\) c. calcium, \(\mathrm{Ca},\) and fluorine, \(\mathrm{F}\) d. cesium, \(\mathrm{Cs}\), and nitrogen, \(\mathrm{N}\) e. rubidium, Rb, and phosphorus, \(\mathrm{P}\)

Name the noble gas atom that has the same electron configuration as each of the ions in the following compounds. a. calcium nitride, \(\mathrm{Ca}_{3} \mathrm{N}_{2}\) b. magnesium sulfide, MgS c. aluminum fluoride, \(\mathrm{AlF}_{3}\) d. radium bromide, \(\mathrm{RaBr}_{2}\) e. cesium phosphide, \(\mathrm{Cs}_{3} \mathrm{P}\)

Which of the following molecules contain polar covalent bonds? a. nitrogen, \(\mathrm{N}_{2}\) b. astatine, \(\mathrm{At}_{2}\) c. carbon monoxide, \(\mathrm{CO}\) d. hydrogen fluoride, HF

For each of the following bonds, draw a figure indicating the direction of the bond dipole, including which end of the bond is positive and which is negative. For each of the following bonds, draw a figure indicating the direction of the bond dipole, including which end of the bond is positive and which is negative. a. \(\mathrm{P}-\mathrm{F}\) b. \(\mathrm{P}-\mathrm{O}\) c. \(\mathrm{P}-\mathrm{C}\) d. \(\mathrm{P}-\mathrm{H}\)

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