Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Without referring to your textbook or a periodic table, write the full electron configuration, the orbital box diagram, and the noble gas shorthand configuration for the elements with the following atomic numbers. a. Z=21 b. Z=15 c. Z=36 d. Z=38 e. Z=30

Short Answer

Expert verified
a. Z=21 1. Electron Configuration: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹ 2. Orbital Box Diagram: 1s: ↑↓ | 2s: ↑↓ | 2p: ↑↓ ↑↓ ↑↓ | 3s: ↑↓ | 3p: ↑↓ ↑↓ ↑↓ | 4s: ↑↓ | 3d: ↑ 3. Noble Gas Shorthand Configuration: [Ar] 4s² 3d¹ b. Z=15 1. Electron Configuration: 1s² 2s² 2p⁶ 3s² 3p³ 2. Orbital Box Diagram: 1s: ↑↓ | 2s: ↑↓ | 2p: ↑↓ ↑↓ ↑↓ | 3s: ↑↓ | 3p: ↑ ↑ ↑ 3. Noble Gas Shorthand Configuration: [Ne] 3s² 3p³ c. Z=36 1. Electron Configuration: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d² 2. Orbital Box Diagram: 1s: ↑↓ | 2s: ↑↓ | 2p: ↑↓ ↑↓ ↑↓ | 3s: ↑↓ | 3p: ↑↓ ↑↓ ↑↓ | 4s: ↑↓ | 3d: ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ | 4p: ↑↓ ↑↓ ↑↓ | 5s: ↑↓ | 4d: ↑ ↑ 3. Noble Gas Shorthand Configuration: [Kr] d. Z=38 1. Electron Configuration: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d³ 2. Orbital Box Diagram: 1s: ↑↓ | 2s: ↑↓ | 2p: ↑↓ ↑↓ ↑↓ | 3s: ↑↓ | 3p: ↑↓ ↑↓ ↑↓ | 4s: ↑↓ | 3d: ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ | 4p: ↑↓ ↑↓ ↑↓ | 5s: ↑↓ | 4d: ↑ ↑ ↑ 3. Noble Gas Shorthand Configuration: [Kr] 5s² 4d³ e. Z=30 1. Electron Configuration: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 2. Orbital Box Diagram: 1s: ↑↓ | 2s: ↑↓ | 2p: ↑↓ ↑↓ ↑↓ | 3s: ↑↓ | 3p: ↑↓ ↑↓ ↑↓ | 4s: ↑↓ | 3d: ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ 3. Noble Gas Shorthand Configuration: [Ar] 4s² 3d¹⁰

Step by step solution

01

1. Electron Configuration

For an element with Z=21, the electron configuration would be: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹
02

2. Orbital Box Diagram

The orbital box diagram for Z=21 can be represented as: 1s: ↑↓ | 2s: ↑↓ | 2p: ↑↓ ↑↓ ↑↓ | 3s: ↑↓ | 3p: ↑↓ ↑↓ ↑↓ | 4s: ↑↓ | 3d: ↑
03

3. Noble Gas Shorthand Configuration

The noble gas preceding Z=21 is Argon (Ar, Z=18). So the shorthand configuration would be: [Ar] 4s² 3d¹ b. Z=15
04

1. Electron Configuration

For an element with Z=15, the electron configuration would be: 1s² 2s² 2p⁶ 3s² 3p³
05

2. Orbital Box Diagram

The orbital box diagram for Z=15 can be represented as: 1s: ↑↓ | 2s: ↑↓ | 2p: ↑↓ ↑↓ ↑↓ | 3s: ↑↓ | 3p: ↑ ↑ ↑
06

3. Noble Gas Shorthand Configuration

The noble gas preceding Z=15 is Neon (Ne, Z=10). So the shorthand configuration would be: [Ne] 3s² 3p³ c. Z=36
07

1. Electron Configuration

For an element with Z=36, the electron configuration would be: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d²
08

2. Orbital Box Diagram

The orbital box diagram for Z=36 can be represented as: 1s: ↑↓ | 2s: ↑↓ | 2p: ↑↓ ↑↓ ↑↓ | 3s: ↑↓ | 3p: ↑↓ ↑↓ ↑↓ | 4s: ↑↓ | 3d: ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ | 4p: ↑↓ ↑↓ ↑↓ | 5s: ↑↓ | 4d: ↑ ↑
09

3. Noble Gas Shorthand Configuration

The noble gas preceding Z=36 is Krypton (Kr, Z=36). So the shorthand configuration would be: [Kr] d. Z=38
10

1. Electron Configuration

For an element with Z=38, the electron configuration would be: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d³
11

2. Orbital Box Diagram

The orbital box diagram for Z=38 can be represented as: 1s: ↑↓ | 2s: ↑↓ | 2p: ↑↓ ↑↓ ↑↓ | 3s: ↑↓ | 3p: ↑↓ ↑↓ ↑↓ | 4s: ↑↓ | 3d: ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ | 4p: ↑↓ ↑↓ ↑↓ | 5s: ↑↓ | 4d: ↑ ↑ ↑
12

3. Noble Gas Shorthand Configuration

The noble gas preceding Z=38 is Krypton (Kr, Z=36). So the shorthand configuration would be: [Kr] 5s² 4d³ e. Z=30
13

1. Electron Configuration

For an element with Z=30, the electron configuration would be: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰
14

2. Orbital Box Diagram

The orbital box diagram for Z=30 can be represented as: 1s: ↑↓ | 2s: ↑↓ | 2p: ↑↓ ↑↓ ↑↓ | 3s: ↑↓ | 3p: ↑↓ ↑↓ ↑↓ | 4s: ↑↓ | 3d: ↑↓ ↑↓ ↑↓ ↑↓ ↑↓
15

3. Noble Gas Shorthand Configuration

The noble gas preceding Z=30 is Argon (Ar, Z=18). So the shorthand configuration would be: [Ar] 4s² 3d¹⁰

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free