Chapter 13: Problem 4
For the equilibrium \(\mathrm{N}_{2} \mathrm{O}_{4}+57 \mathrm{~kJ} \rightleftarrows 2 \mathrm{NO}_{2}\) list four stresses that serve to increase the amount of \(\mathrm{NO}_{2}\).
Short Answer
Expert verified
Increase temperature, decrease pressure, remove \( \text{NO}_2 \), add \( \text{N}_2\text{O}_4 \).
Step by step solution
01
Understand the Equilibrium Reaction
The given equilibrium reaction is \( \text{N}_2\text{O}_4 + 57 \text{ kJ} \rightleftharpoons 2 \text{NO}_2 \). This means that \( \text{N}_2\text{O}_4 \) decomposes into \( \text{NO}_2 \) while absorbing 57 kJ of energy. It is important to note that this is an endothermic reaction.
02
Le Chatelier's Principle
Le Chatelier's Principle states that if an external stress is applied to a system at equilibrium, the system adjusts in such a way as to counteract the stress and establish a new equilibrium. We will apply this principle to find stresses that shift the equilibrium towards \( \text{NO}_2 \).
03
Increase Temperature
Since the reaction is endothermic, increasing the temperature will favor the formation of \( \text{NO}_2 \). According to Le Chatelier's Principle, the system will shift to absorb the added heat.
04
Decrease Pressure
In the given reaction, one mole of \( \text{N}_2\text{O}_4 \) produces two moles of \( \text{NO}_2 \). By decreasing the pressure, the equilibrium will shift towards the side with more moles of gas, which is the right side, thereby increasing \( \text{NO}_2 \).
05
Remove \( \text{NO}_2 \) from the System
By continuously removing \( \text{NO}_2 \) from the system, the equilibrium will shift to the right to produce more \( \text{NO}_2 \) to replace what was removed.
06
Add \( \text{N}_2\text{O}_4 \) to the System
Adding more \( \text{N}_2\text{O}_4 \) to the system will shift the equilibrium to the right, resulting in more \( \text{NO}_2 \) being formed, trying to use up the excess reactant.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Le Chatelier's Principle
Le Chatelier's Principle is a fundamental concept in chemical equilibrium. It helps predict how a system in equilibrium responds to external changes or stresses. When a system at equilibrium experiences a change in concentration, temperature, or pressure, it adjusts itself to minimize that change and re-establish equilibrium.
For example, if a reactant is added to the system, the equilibrium will shift to consume the excess reactant, producing more product in the process. Similarly, if a product is removed, the system will shift to produce more of that product.
For example, if a reactant is added to the system, the equilibrium will shift to consume the excess reactant, producing more product in the process. Similarly, if a product is removed, the system will shift to produce more of that product.
- **Stress Addition**: The system counteracts any added stress by shifting equilibrium in the direction that decreases the effect of the change.
- **Direction of Shift**: Depending on the nature of the external change, equilibrium may shift to the right (towards products) or to the left (towards reactants).
Endothermic Reactions
Endothermic reactions are processes where energy is absorbed from the surroundings. This absorption is typically in the form of heat. In the chemical reaction \(\text{N}_2\text{O}_4 + 57\text{ kJ} \rightleftharpoons 2 \text{NO}_2\), energy is absorbed during the conversion of \(\text{N}_2\text{O}_4\) into \(\text{NO}_2\).
- **Heat as a Reactant**: For endothermic reactions, temperature and heat can be considered as additional reactants. Increasing the temperature increases the system's heat, shifting the equilibrium towards the products.
- **Effect on \(\Delta H\)**: In these reactions, the enthalpy change (\(\Delta H\)) is positive, indicating energy input rather than release.
Pressure Effects on Equilibrium
The effect of pressure on equilibrium depends on the number of moles of gas present on the reactant and product sides of the equation. Le Chatelier's Principle helps us understand how varying pressure influences the reaction: In this equilibrium between \(\text{N}_2\text{O}_4\) and \(\text{NO}_2\):
- **Unequal Molar Quantity**: There are fewer moles of gas on the left side (1 mole of \(\text{N}_2\text{O}_4\)) compared to the right side (2 moles of \(\text{NO}_2\)).
- **Pressure Decrease**: Reducing the system’s pressure favors the shift toward the side with more moles of gas, thus producing more \(\text{NO}_2\).
- **Practical Application**: Industrially, pressure adjustments become crucial in maximizing the yields of desired products by focusing on gas phase reactions.
Temperature Effects on Equilibrium
Temperature changes significantly impact chemical equilibria, especially in endothermic and exothermic reactions. According to Le Chatelier's Principle, adding heat to an endothermic reaction like \(\text{N}_2\text{O}_4 + 57 \text{kJ} \rightleftharpoons 2 \text{NO}_2\) will drive the equilibrium towards product formation because heat acts as a reactant.
- **Temperature Increase**: For endothermic reactions, increasing the temperature supplies additional energy, which shifts the equilibrium to favor the product side.
- **Dynamic Changes**: The equilibrium constant, \(K\), itself can change with temperature changes, reflecting the new balance point.
- **Economic Considerations**: In industrial settings, understanding how temperature shifts equilibrium is crucial for designing energy-efficient processes.