Chapter 12: Problem 11
For a given aqueous solution, if \(\left[\mathrm{OH}^{-}\right]=1.0 \times 10^{-5} \mathrm{M},\) what is \(\left[\mathrm{H}^{+}\right] ?\)
Short Answer
Expert verified
\([\text{H}^+] = 1.0 \times 10^{-9} \, \text{M}\).
Step by step solution
01
Understand the Relationship
The ion product constant of water, \[K_w = [ ext{H}^+][ ext{OH}^-] = 1.0 \times 10^{-14} \, \text{M}^2 \]relates the concentrations of hydrogen ions and hydroxide ions in water.
02
Insert Given Values
Given that \([\text{OH}^-] = 1.0 \times 10^{-5} \, \text{M}\), we can substitute this value into the equation.\[K_w = [\text{H}^+](1.0 \times 10^{-5} \, \text{M}) = 1.0 \times 10^{-14} \, \text{M}^2\]
03
Solve for \\(\\left[\mathrm{H}^{+}\\right]\\)
To find \([\text{H}^+]\), divide both sides of the equation by \([\text{OH}^-]\):\[[\text{H}^+] = \frac{1.0 \times 10^{-14} \, \text{M}^2}{1.0 \times 10^{-5} \, \text{M}}\]
04
Calculate \\(\\left[\mathrm{H}^{+}\\right]\\) Value
Perform the division:\[[\text{H}^+] = 1.0 \times 10^{-9} \, \text{M}\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ion Product Constant of Water
The ion product constant of water, denoted by \(K_w\), is a crucial concept in understanding the chemistry of aqueous solutions. It represents the product of the concentrations of hydrogen ions \([\text{H}^+]\) and hydroxide ions \([\text{OH}^-]\) in water. For water at 25°C, \(K_w\) is a constant value of \(1.0 \times 10^{-14} \, \text{M}^2\). This means that regardless of the state of the solution—whether it is acidic, neutral, or basic—the product of the concentrations of hydrogen ions and hydroxide ions will always equal this constant.
This relationship is fundamental for calculating either the hydroxide ion concentration or the hydrogen ion concentration in a solution when the other is known. Knowing this can help us predict the acidity or basicity of a given solution.
This relationship is fundamental for calculating either the hydroxide ion concentration or the hydrogen ion concentration in a solution when the other is known. Knowing this can help us predict the acidity or basicity of a given solution.
- If a solution is neutral, \([\text{H}^+]=[\text{OH}^-]\).
- If it is acidic, \([\text{H}^+]>[\text{OH}^-]\).
- If it is basic, \([\text{H}^+]<[\text{OH}^-]\).
Hydroxide Ion Concentration
The hydroxide ion concentration, \([\text{OH}^-]\), is a key factor in determining the basicity of a solution. In basic solutions, there is a higher concentration of hydroxide ions compared to hydrogen ions. The concentration of \([\text{OH}^-]\) helps in computing \([\text{H}^+]\) using the ion product constant of water, \(K_w\).
For example, when you know the \([\text{OH}^-]\) is \(1.0 \times 10^{-5} \, \text{M}\), you use the relationship
\[ K_w = [\text{H}^+][\text{OH}^-] = 1.0 \times 10^{-14} \, \text{M}^2 \] to find the \([\text{H}^+]\) concentration. By dividing \(K_w\) by \([\text{OH}^-]\), you can solve for \([\text{H}^+]\).
This process showcases the inverse relationship between \([\text{OH}^-]\) and \([\text{H}^+]\):
For example, when you know the \([\text{OH}^-]\) is \(1.0 \times 10^{-5} \, \text{M}\), you use the relationship
\[ K_w = [\text{H}^+][\text{OH}^-] = 1.0 \times 10^{-14} \, \text{M}^2 \] to find the \([\text{H}^+]\) concentration. By dividing \(K_w\) by \([\text{OH}^-]\), you can solve for \([\text{H}^+]\).
This process showcases the inverse relationship between \([\text{OH}^-]\) and \([\text{H}^+]\):
- A high \([\text{OH}^-]\) indicates a low \([\text{H}^+]\), meaning the solution is basic.
- A low \([\text{OH}^-]\) suggests a higher \([\text{H}^+]\), pointing to an acidic solution.
Hydrogen Ion Concentration
The hydrogen ion concentration, \([\text{H}^+]\), serves as an indicator of a solution's acidity. In an aqueous solution, \([\text{H}^+]\) is inversely related to \([\text{OH}^-]\) as governed by the ion product constant of water, \(K_w\).
To find \([\text{H}^+]\), especially when dealing with an alkaline solution where \([\text{OH}^-]\) is known, you apply:
\[ [\text{H}^+] = \frac{K_w}{[\text{OH}^-]}\]
In the exercise provided, the \([\text{OH}^-]\) concentration is \(1.0 \times 10^{-5} \, \text{M}\). To find \([\text{H}^+]\), you divide the \(K_w\) value of \(1.0 \times 10^{-14}\) by \(1.0 \times 10^{-5}\), giving \([\text{H}^+]\) as \(1.0 \times 10^{-9} \, \text{M}\).
To find \([\text{H}^+]\), especially when dealing with an alkaline solution where \([\text{OH}^-]\) is known, you apply:
\[ [\text{H}^+] = \frac{K_w}{[\text{OH}^-]}\]
In the exercise provided, the \([\text{OH}^-]\) concentration is \(1.0 \times 10^{-5} \, \text{M}\). To find \([\text{H}^+]\), you divide the \(K_w\) value of \(1.0 \times 10^{-14}\) by \(1.0 \times 10^{-5}\), giving \([\text{H}^+]\) as \(1.0 \times 10^{-9} \, \text{M}\).
- This indicates the solution's nature based on how \([\text{H}^+]\) compares to neutral conditions (\([\text{H}^+]=1.0 \times 10^{-7} \, \text{M}\)).
- A \([\text{H}^+]\) below \(1.0 \times 10^{-7} \, \text{M}\) confirms a basic solution.