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Why do you have to first determine the heat change of the surroundings for a chemical reaction?

Short Answer

Expert verified
The determination of the heat change in the surroundings during a chemical reaction is important since it allows us to follow the principle of conservation of energy. By knowing the heat change in the surroundings, we can calculate the heat change in the system, ensuring the total energy prior and post-reaction remains constant.

Step by step solution

01

Understanding the Concept of Thermodynamics

In order to answer the exercise, it's crucial to understand the principles of thermodynamics. Thermodynamics is about the study of heat energy transfer, energy conservation and how it affects matter. This branch of physics also involves the concept of entropy, which is the degree of disorder or randomness in the system.
02

Principle of Conservation of Energy

The Principle of Conservation of Energy is the key to this question. According to this principle, energy cannot be created or destroyed, but can only be transferred or converted from one form to another. In the context of a chemical reaction, this principle implies that the total energy before and after the reaction must be the same. Thus, any energy change in the system must be compensated by an equal and opposite energy change in the surroundings.
03

Meaning of Heat Change in Surroundings

Finally, deriving from the principle explained in Step 2, the heat change in the surroundings during a chemical reaction is the energy that is either absorbed from or released to the surroundings by the system (chemical reaction). This is why we need to determine it first. By quantifying the heat change in the surroundings, we can determine the heat change of the system itself, ensuring that the total energy remains the same before and after the reaction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Principle of Conservation of Energy
Imagine you are at a magic show, and the magician claims to make something vanish into thin air; you'd probably be skeptical because we know from experience that objects don't just disappear. That's similar to the principle of conservation of energy in thermodynamics. It tells us that in the universe, energy is like the 'ultimate magician' that cannot truly vanish; it only transforms or moves from one place to another.

The principle of conservation of energy states that the total amount of energy in an isolated system remains constant over time. This is fundamental to understanding chemical reactions because it means that during a reaction, energy is neither created nor lost. Instead, it is converted from one form to another - chemical energy might become heat energy, for example. This principle allows scientists and engineers to predict how much energy is needed to start a reaction and what the energy output will be. It's like a cosmic accounting system, where the energy 'books' must always balance.
Heat Energy Transfer
Have you ever touched a metal spoon that was sitting in a hot pot of soup and quickly pulled away because it was too hot? That's heat energy transfer at work. Heat transfer is a pathway for energy to flow from hotter objects to cooler ones. In thermodynamics, there are three main ways this can happen: conduction (like the spoon in the soup), convection (like warm air rising), and radiation (like feeling the sun's warmth).

When we talk about chemical reactions, energy transfer, particularly heat, is a central player. A reaction might release heat, warming up its surroundings, or absorb heat, causing the surroundings to cool down. Understanding the direction and amount of heat transfer is crucial because it can affect the rate and extent of the reaction. Think of heat as the currency in a chemical marketplace; different reactions have specific 'costs' or 'profits' of heat, altering the conditions under each reaction can proceed.
Entropy
Entropy may sound like a complex concept, and in some ways, it is, but it can also be understood through everyday experience. Picture a child's room that starts off clean and tidy, but quickly becomes disordered with toys strewn about; that increase in disorder is similar to entropy. In thermodynamics, entropy is a measure of the amount of disorder, or randomness, in a system.

The second law of thermodynamics states that the total entropy of an isolated system can never decrease over time. This means that in nature, systems tend to move towards more disorder, rather than less. During chemical reactions, the entropy of the reactants and products plays an important role in determining whether a reaction is favorable. Reactions often proceed in a direction that increases entropy. For a student studying chemical reactions, understanding entropy helps to predict the spontaneity of those reactions and how they might behave under different conditions.

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Most popular questions from this chapter

Certain drain cleaners are a mixture of sodium hydroxide and powdered aluminum. When dissolved in water, the sodium hydroxide reacts with the aluminum and the water to produce hydrogen gas. $$ 2 \mathrm{Al}(s)+2 \mathrm{NaOH}(a q)+6 \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow 2 \mathrm{NaAl}(\mathrm{OH})_{4}(a q)+3 \mathrm{H}_{2}(g) $$ The sodium hydroxide helps dissolve grease, and the hydrogen gas provides a mixing and scrubbing action. What mass of hydrogen gas would be formed from a reaction of \(2.48 \mathrm{~g} \mathrm{Al}\) and \(4.76 \mathrm{~g} \mathrm{NaOH}\) in water?

The reaction that produces the water gas mixture, described in Question 6.99, is $$ \mathrm{C}(s)+\mathrm{H}_{2} \mathrm{O}(g) \longrightarrow \mathrm{CO}(g)+\mathrm{H}_{2}(g) $$ This reaction requires an input of \(131 \mathrm{~kJ}\) of heat for every mole of carbon that reacts. (a) Is this reaction endothermic or exothermic? (b) What is the energy change for this reaction in units of \(\mathrm{kJ} / \mathrm{mol}\) of carbon?

When the solids ammonium thiocyanate and barium hydroxide are mixed in a beaker, a solution forms, and the temperature of the solution drops to \(-5^{\circ} \mathrm{C}\). Is this an endothermic or exothermic reaction? Explain.

The balanced equation for the reaction of phosplorus and oxygen gas to form tetraphosphorus decoxide is $$ \mathrm{P}_{4}(\mathrm{~g})+5 \mathrm{O}_{2}(\mathrm{~g}) \longrightarrow \mathrm{P}_{4} \mathrm{O}_{u(s)} $$ What is the limiting reactant when each of the following sets of quantities of reactants is mixed? (a) \(0.50 \mathrm{~mol} \mathrm{P}_{4}\) and \(5.0 \mathrm{~mol} \mathrm{O}_{2}\) (b) \(0.20 \mathrm{~mol} \mathrm{P}_{4}\) and \(1.0 \mathrm{~mol} \mathrm{O}_{2}\) (c) \(0.25 \mathrm{~mol} \mathrm{P}_{4}\) and \(0.75 \mathrm{~mol} \mathrm{O}_{2}\)

What is the heat change when \(55.0 \mathrm{~g}\) of water cools from \(60.0^{\circ} \mathrm{C}\) to \(25.5^{\circ} \mathrm{C}\) ?

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