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Convert an energy of \(876 \mathrm{~J}\) to units of Calories.

Short Answer

Expert verified
The equivalent energy in calories for \(876 \mathrm{~Joules}\) is approximately 0.2094 Calories.

Step by step solution

01

Understand the Conversion Constant

As a universally accepted conversion factor, 1 Calorie equals 4184 Joules. This information is necessary to convert one unit of energy to another.
02

Apply the Conversion Factor

Now we have 876 Joules and we need to convert it to Calories. We can start by dividing the number of Joules by the number of Joules in a Calorie. So, the calculation would be \( \frac{876 \mathrm{~Joules}}{4184 \mathrm{~Joules/Calorie}} \).
03

Perform the Calculation and report the result

Perform the division stated above to reveal that \(876 \mathrm{~Joules} \approx 0.2094 \mathrm{~Calories}\). The result should be reported with appropriate significant figures.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Joules to Calories Conversion
Understanding the conversion from Joules to Calories is essential for many applications in chemistry, nutrition, physics, and more. To convert energy from Joules (J) to Calories (cal), we need a conversion constant. This constant is 4.184 Joules per 1 small calorie (cal), or 4184 Joules for a nutritional Calorie (often denoted as Cal or kcal).

Let's put this into practice with an example. If we have an energy amount of 876 Joules, converting this to Calories would require dividing by the conversion factor.\[\frac{876 \text{ J}}{4184 \text{ J/Cal}} = 0.2092 \text{ Cal}\] Hence, 876 Joules is roughly equivalent to 0.2092 nutritional Calories (Cal). Understanding this fundamental conversion can vastly improve the conceptual approach in tackling problems involving energy transactions across various contexts.
Energy Units Conversion
Energy can be expressed in multiple units, including Joules (J), Calories (cal), kilowatt-hours (kWh), and British Thermal Units (BTU). The conversion among these units is a staple in scientific and practical calculations. For instance, knowing how to convert Joules to other forms of energy units is pivotal in fields such as thermodynamics, electrical engineering, and dietary energy consumption.

When converting energy units, always use precise conversion factors. For Calories to Joules, the factor depends on whether it's a small calorie (used in chemistry) or a nutritional Calorie (common in food energy content). Being proficient in these conversions is part of a robust conceptual approach in chemistry as it allows for the seamless transition between different systems of measurement.
Conceptual Approach in Chemistry
Adopting a conceptual approach in chemistry means grasping the underlying principles that govern chemical phenomena rather than just memorizing facts and figures. This approach aids in understanding and predicting chemical behavior across a variety of conditions. When converting energy units, for example, it is crucial to comprehend the principles of energy conservation and thermodynamics.

By conceptualizing energy as a quantifiable substance that cannot be created or destroyed—only transformed—we can begin to appreciate the importance of accurate unit conversion. Thus, when we talk about energy transitions, whether in physical processes or chemical reactions, understanding the efficiency and energy yields in the appropriate units becomes paramount.
Significant Figures in Calculations
In chemistry and other sciences, the precision of measurements is conveyed through significant figures. These are the digits in a number that carry meaning contributing to its measurement resolution. When performing calculations, such as converting energy units from Joules to Calories, it's important to report the final result with the correct number of significant figures to reflect the precision of the measurement.

For the calculated conversion of 876 J to Calories, the initial value has three significant figures. After dividing by the conversion factor, the result should also reflect an appropriate level of precision, which in our case is 0.2092 Calories. This proper handling of significant figures ensures the accuracy and integrity of data in scientific communication.

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Most popular questions from this chapter

A student was synthesizing aspirin in the laboratory. Using the amount of limiting reactant, she calculated the mass of aspirin that should form as \(8.95 \mathrm{~g}\). When she weighed her aspirin product on the balance, its mass was \(7.44 \mathrm{~g}\). (a) What is the actual yield of aspirin? (b) What is the theoretical yield of aspirin? (c) Calculate the percent yield for this synthesis.

Sodium cyclamate, \(\mathrm{NaC}_{6} \mathrm{H}_{12} \mathrm{NSO}_{3}\), was a popular nonsugar sweetener until it was banned by the Food and Drug Administration. Its sweetness is about 30 times that of sugar (or sucrose, \(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\) ). The energy that can be supplied by ingestion of each compound is \(16.03 \mathrm{~kJ} / \mathrm{g}\) for sodium cyclamate and \(16.49 \mathrm{~kJ} / \mathrm{g}\) for sucrose. What is the energy savings in Calories resulting from using \(1.00 \mathrm{~g}\) of sodium cyclamate in place of \(30.0 \mathrm{~g}\) of sucrose?

The heat change that accompanies the formation of \(1.00 \mathrm{~mol}\) of carbon dioxide from its elements is \(-393.7 \mathrm{~kJ} / \mathrm{mol}\). What heat change accompanies the formation of \(0.650 \mathrm{~mol} \mathrm{CO}_{2}\) ?

If energy cannot be created, what is the source of the energy that is released when gasoline is bamed?

When a \(6.00-\mathrm{g}\) sample of coal is burned, it releases enough heat to raise the temperature of \(2010 \mathrm{~g}\) of water from \(24.0^{\circ} \mathrm{C}\) to \(41.5^{\circ} \mathrm{C}\). (a) How much heat did the coal release as it burned? (b) Calculate the heat of combustion of coal in units of \(\mathrm{kJ} / \mathrm{g}\).

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