Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Convert an energy of \(526 \mathrm{cal}\) to units of joules.

Short Answer

Expert verified
The energy in joules is approximately \(2199.984 \, Joules\).

Step by step solution

01

Understand the conversion factor

The first step is to understand the conversion factor between calories and joules. One calorie (\(1 \, cal\)) is equal to approximately \(4.184 \, Joules\).
02

Apply the conversion factor

The next step is to apply the conversion factor to the given energy. We can do this by simply multiplying the given energy in calories by the conversion factor. Hence, \(526 \, cal = 526 \times 4.184 \, Joules\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Calories to Joules
When you are converting energy from calories to joules, you're essentially changing one unit of energy measure to another. Understanding this conversion is very important in chemistry and physics as both units are used in different contexts.
To express calories in joules, we use a simple mathematical relationship: that one calorie is equal to approximately 4.184 joules. This means anytime you have a value in calories, you can find its equivalent in joules by multiplying it by 4.184.
This conversion is crucial when dealing with energy changes in chemical reactions or when calculating energy consumption. It helps bridge the gap between the science of nutrition, which often uses calories, and physics or chemistry that often deals with joules.
Conversion Factor
A conversion factor is a numerical value that is used to convert a measurement expressed in one set of units to another set of units. The concept of conversion factors is useful when translating between different systems or dimensions in science.
To convert from calories to joules, the conversion factor is 4.184. This is a constant value and it signifies how many joules one calorie contains. Using conversion factors makes calculations easier, since you just multiply the original measurement by the right conversion factor.
  • Identify the units you want to convert from and to.
  • Find the conversion factor between these units.
  • Multiply the original value by the conversion factor to get the converted value.
This approach ensures precision and consistency in scientific calculations, particularly in chemistry calculations where appropriate unit conversions are often necessary for accurate results.
Chemistry Calculations
Chemistry calculations often involve conversions as they deal with various measurements and dimensions. Converting energy units like calories to joules is a common task. In chemistry, understanding energy conversions is essential when analyzing reactions that release or absorb energy.
Practically, when engaging in chemistry calculations, it is important to not only know the conversion factors but to apply them correctly. For example, when converting 526 calories into joules, you would calculate it as follows:
\[ 526 imes 4.184 = 2200.384 ext{ Joules} \]
Firstly, you identify the conversion factor—here, 4.184. Then, multiply it by the given number of calories to find the energy in joules.
This systematic process is a cornerstone of solving chemistry problems accurately, ensuring all data is in a manageable and comparable form throughout your calculations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Suppose you want to convert iron ore to a specific amount of pure iron using the following reaction: $$ \mathrm{Fe}_{3} \mathrm{O}_{4}(s)+4 \mathrm{CO}(g) \longrightarrow 3 \mathrm{Fe}(s)+4 \mathrm{CO}_{2}(g) $$ (a) What mole ratio would you use in the following equation to determine the number of moles of \(\mathrm{CO}\) needed to react with a known amount of \(\mathrm{Fe}_{3} \mathrm{O}_{4}\) ? \(\mathrm{mol} \mathrm{Fe}_{3} \mathrm{O}_{4} \times=\mathrm{mol} \mathrm{CO}\) (b) If you add more than enough \(\mathrm{CO}\) so that all the \(\mathrm{Fe}_{3} \mathrm{O}_{4}\) reacts, what mole ratio would you use in the following equation to determine the moles of \(\mathrm{CO}_{2}\) produced? \(\mathrm{mol} \mathrm{Fe}_{3} \mathrm{O}_{4} \times=\mathrm{mol} \mathrm{CO}_{2}\) (c) Suppose you know the number of moles of \(\mathrm{Fe}\) product formed and you want to know the number of moles of \(\mathrm{CO}\) that reacted. What mole ratio would you use in the following equation? \(\mathrm{mol} \mathrm{Fe} \times \overline{\mathrm{F}}=\mathrm{mol}\)

Sulfuric acid is commonly used as an electrolyte in car batteries. Suppose you spill some on your garage floor. Before cleaning it up, you wisely decide to neutralize it with sodium bicarbonate (baking soda) from your kitchen. The reaction of sodium bicarbonate and sulfuric acid is $$ 2 \mathrm{NaHCO}_{3}(s)+\mathrm{H}_{2} \mathrm{SO}_{4}(a q) \underset{\mathrm{Na}_{2} \mathrm{SO}_{4}(a q)}{\longrightarrow}+2 \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(l) $$ You estimate that your acid spill contains about \(2.0 \mathrm{~mol}\) \(\mathrm{H}_{2} \mathrm{SO}_{4}\). What mass of \(\mathrm{NaHCO}_{3}\) do you need to neutralize the acid?

An aqueous solution containing \(10.0 \mathrm{~g} \mathrm{NaOH}\) is added to an aqueous solution containing \(10.0 \mathrm{~g} \mathrm{HNO}_{2}\) (a) Write a balanced equation for the acid-base reaction that should occur. (b) Identify the limiting reactant. (c) Will the solution be acidic or basic when the reaction is complete?

When copper(II) sulfate pentahydrate, \(\mathrm{CuSO}_{4}+\mathrm{SH}_{2} \mathrm{O}\), is heated, it decomposes to the dehydrated form. The waters of hydration are released from the solid crystal and form water vapor. The hydrated form is medium blue, and the dehydrated solid is light blue. The balanced equation is $$ \operatorname{CuSO}_{4} \cdot \mathrm{SH}_{2} \mathrm{O}(s) \stackrel{\text { heat }}{\longrightarrow} \mathrm{CuSO}_{4}(s)+5 \mathrm{H}_{2} \mathrm{O}(g) $$ (a) What is the molar mass of \(\mathrm{CuSO}_{4}+5 \mathrm{H}_{2} \mathrm{O}\) ? (b) What is the molar mass of \(\mathrm{CuSO}_{4}\) ? (c) If \(1.00 \mathrm{~g} \mathrm{CuSO}_{4} 5 \mathrm{H}_{2} \mathrm{O}\) is decomposed to \(\mathrm{CuSO}_{4}\) predict the mass of the remaining light blue solid.

Convert an energy of \(225 \mathrm{cal}\) to units of joules.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free