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Why is a balanced equation important when determining the amount of product that can be produced from a given amount of reactant?

Short Answer

Expert verified
A balanced equation is important when determining the amount of product that can be produced from a given reactant because it accurately reflects the stoichiometric relationships, or precise measurement ratios, between the reactants and products in a chemical reaction. Without a balanced equation, these ratios would be misrepresented, leading to incorrect calculations of product yield.

Step by step solution

01

Understanding Balanced Equations

A balanced chemical equation is one where the number of each type of atom is the same on both sides of the equation. It means that the equation follows the law of conservation of mass, where mass is neither created nor destroyed during a chemical reaction.
02

Relating Balanced Equations to Stoichiometry

Stoichiometry is the calculation of reactants and products in chemical reactions. It's based on the balanced equation for the chemical reaction. The coefficients in the balanced equation indicate the molar ratio between different reactants and products. Therefore, a balanced equation allows us to determine the amounts of substances needed or produced in a chemical reaction.
03

Relevance of Balanced Equations in Determining Product Amount

A balanced equation is used to calculate the amount of product produced from a given reactant based on its stoichiometry. Unbalanced equations do not accurately reflect the ratios in which substances react and so cannot be used to determine quantities of the products. Ensuring an equation is balanced is compulsory to accurately predict yield of products in a chemical reaction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Stoichiometry
When discussing chemical reactions, stoichiometry serves as a crucial concept that assists in connecting the world of chemistry with mathematics. Essentially, stoichiometry involves calculating the amounts of reactants and products involved in a chemical reaction. It translates the symbolic language of chemical formulas into equations that allow chemists to predict how much of a product will form from given reactants.

At the heart of stoichiometry is the balanced chemical equation, which provides the molar relationship between the reactants and products. These molar relationships are depicted through coefficients in the balanced equation, which helps in determining how substances interact and transform.
  • The coefficients tell us about the relative integers for each participating substance.
  • These integers showcase the proportions needed or expected in a reaction.
Possessing a balanced equation allows us to use these ratios to convert between masses, moles, and particles through various calculations, making stoichiometry an essential tool in chemical analysis and applications.
Law of Conservation of Mass Explained
The law of conservation of mass is an underpinning principle of stoichiometry and chemistry. This fundamental law states that mass is neither created nor destroyed in a chemical reaction. In more practical terms, the total mass of the reactants must equal the total mass of the products. This principle ensures that chemical equations can be balanced.

To achieve this balance, one must ensure that each elemental atom appears in the same quantity on both sides of the reaction equation.
  • This requires counting and sometimes adjusting the coefficients in the chemical equation.
  • The goal is to create the simplest whole-number ratio that preserves mass across the reaction.
Understanding this law helps students appreciate how atoms are rearranged during reactions, maintaining the stability of matter in different forms. This conservation is vital for making accurate stoichiometric calculations and predicting the outcomes of chemical reactions with certainty.
Chemical Reaction Yield and Its Importance
In chemistry, the yield is an important term that refers to the amount of product obtained from a chemical reaction. Yield helps us understand the efficiency and capability of a chemical process. Theoretical yield is the amount of product expected based on stoichiometric calculations if everything proceeds perfectly.

This is different from the actual yield obtained from the reaction, often influenced by various real-world conditions such as incomplete reactions, impurities, and measurement errors.
  • The relationship between the theoretical and actual yield is quantified as percent yield, calculated as:
\[\text{Percent Yield} = \left( \frac{\text{Actual Yield}}{\text{Theoretical Yield}} \right) \times 100\]
  • A balanced chemical equation is necessary to determine the theoretical yield accurately.
  • An unbalanced reaction leads to incorrect assumptions about reactants and products, providing misleading information about the yield.
Understanding the yield in reactions helps industry and laboratories maximize efficiency and minimize waste, which is crucial for sustainable practices and cost-effectiveness in producing chemical products.

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Most popular questions from this chapter

The reaction of lithium metal and water to form lithium hydroxide and hydrogen gas is represented by the following balanced equation: $$ 2 \mathrm{Li}(s)+2 \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow 2 \mathrm{LiOH}(\mathrm{aq})+\mathrm{H}_{2}(g) $$ When \(\mathrm{Li}\) is mixed with excess water, \(0.30 \mathrm{~mol} \mathrm{H}_{2}\) gas is isolated in the laboratory. If this reaction occurs to give an \(85 \%\) yield of \(\mathrm{H}_{2}\), how many moles of \(\mathrm{L}\) reacted?

The balanced equation for the reaction of aluminum metal and chlorine gas is $$ 2 \mathrm{Al}(s)+3 \mathrm{Cl}_{2}(g) \longrightarrow 2 \mathrm{AlCl}_{3}(s) $$ Assume that \(0.40 \mathrm{~g} \mathrm{Al}\) is mixed with \(0.60 \mathrm{~g} \mathrm{Cl}_{2}\). (a) What is the limiting reactant? (b) What is the maximum amount of \(\mathrm{AlCl}_{2}\), in grams, that can be produced?

What are some characteristics of a good calorimeter?

When a \(6.00-\mathrm{g}\) sample of coal is burned, it releases enough heat to raise the temperature of \(2010 \mathrm{~g}\) of water from \(24.0^{\circ} \mathrm{C}\) to \(41.5^{\circ} \mathrm{C}\). (a) How much heat did the coal release as it burned? (b) Calculate the heat of combustion of coal in units of \(\mathrm{kJ} / \mathrm{g}\).

A student carried out the following precipitation reaction: $$ \mathrm{BaCl}_{2}(a q)+\mathrm{Na}_{2} \mathrm{CO}_{3}(a q) \longrightarrow \mathrm{BaCO}_{3}(s)+2 \mathrm{NaCl}(a q) $$ After no more precipitate appeared to form, he filtered the barium carbonate solid and then immediately weighed it. Using this mass, he calculated the percent yield as \(105 \%\). Is this possible? Explain.

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