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What factors may contribute to a percent yield less than \(100 \%\) ?

Short Answer

Expert verified
Factors that can contribute to a percent yield less than 100% include improper or insufficient reactant quantities, impurity in reactants, and loss of product during purification.

Step by step solution

01

Identify Factors Affecting the Completion of a Reaction

There are several reasons why a reaction might not go to completion and thus factors that would influence the yield. Improper or insufficient reactant quantities, impure reactants, and loss of product during purification are some examples.
02

Discuss the Role of Reactant Quantities

When performing a reaction, it is crucial to precisely control the quantity of reactants. If there isn't enough of a particular reactant to react with the others, the reaction will not produce as much as it theoretically could, reducing the percent yield. This concept is tied in with stoichiometry, where the ratio of the reactants determines the amount of product formed.
03

Discuss the Role of Reactant Purity

Impurities can also reduce the percent yield. If the reactants are not pure, they may not react as anticipated. For example, an impurity might react with one of the reactants, thereby reducing the amount available for the desired reaction.
04

Discuss the Role of Product Loss During Purification

Finally, during product isolation and purification, some of the product could be lost, causing a lower yield. Purification processes sometimes require filtering, washing, or other separations, during which some of the product may precipitate out or be lost in the filtrate.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reaction Completion
A reaction is considered complete when the reactants have fully transformed into products under given conditions. However, achieving full reaction completion is often difficult. Several factors can prevent a reaction from going all the way.

- **Insufficient Reactant Quantities**: Without enough of one or more reactants, the reaction may stop prematurely. This imbalance limits the reaction’s progress.

- **Reaction Conditions**: Sometimes, external conditions like temperature and pressure might not be ideal for a reaction to proceed. Even slight variations can impact completion rates.

- **Side Reactions**: Competing reactions might consume reactants or form different products. These side paths reduce the amount of intended product made.
Understanding these factors can help control processes better and guide adjustments to enhance reaction completion.
Stoichiometry
Stoichiometry is the bedrock of understanding the relationships between reactants and products in chemical reactions. It helps to predict the amount of product which can be formed from given reactants.

- **Molar Ratios**: This field revolves around the concept of molar ratios, which are derived from balanced chemical equations. These ratios help ensure that the correct quantities of substances are used in reactions.

- **Limiting Reactant**: The limiting reactant is the substance that is completely consumed first, limiting the extent of the reaction. Identifying it is crucial because it determines the maximum amount of product possible.
Precisely measuring and adhering to stoichiometric ratios is essential in maximizing product yield and minimizing waste.
Reactant Purity
Purity of reactants is vital for ensuring both the efficiency and yield of chemical reactions. Impure reactants can skew expected outcomes.

- **Impurities Influence on Yield**: Impurities may react unexpectedly or not at all, diluting the effective concentration of the desired reactant. This misestimate can result in lower product yield.

- **Sources of Contaminants**: Contaminants might come from extraction, handling, or storage of chemicals. Identifying and minimizing these sources helps maintain reactant quality.
Keeping reactants pure not only ensures better yield but can also be crucial in sensitive or high-stakes reactions.
Product Purification
Product purification is the process of isolating the desired product from a mixture of substances following a chemical reaction. This step is key to achieving high percent yields.

- **Yield Loss through Filtration**: During purification, filtration might cause loss if the product is not fully collected or if some dissolves. Care must be taken to optimize the process.

- **Washing and Precipitation**: Similar issues arise here, as some product might be discarded accidentally. Methods like recrystallization are careful to avoid this.
Efficient purification processes target retrieval of the maximum amount of product, hence playing a crucial role in determining the final percent yield.

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Most popular questions from this chapter

What are some characteristics of a good calorimeter?

The reaction that produces the water gas mixture, described in Question 6.99, is $$ \mathrm{C}(s)+\mathrm{H}_{2} \mathrm{O}(g) \longrightarrow \mathrm{CO}(g)+\mathrm{H}_{2}(g) $$ This reaction requires an input of \(131 \mathrm{~kJ}\) of heat for every mole of carbon that reacts. (a) Is this reaction endothermic or exothermic? (b) What is the energy change for this reaction in units of \(\mathrm{kJ} / \mathrm{mol}\) of carbon?

Ammonia is synthesized commercially from nitrogen gas and hydrogen gas for the production of fertilizers: $$ \mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \longrightarrow 2 \mathrm{NH}_{3}(g) $$ If \(100.0 \mathrm{~g}\) of nitrogen reacts completely with excess hydrogen, and \(34.0 \mathrm{~g}\) of \(\mathrm{NH}_{3}\) are obtained, what is the percent yield of ammonia?

The balanced equation for the dissolving of sodium phosphate in water is $$ \mathrm{Na}_{3} \mathrm{PO}_{4}(s) \stackrel{\mathrm{H}_{\mathrm{O}} \mathrm{O}}{\longrightarrow} 3 \mathrm{Na}^{+}(a q)+\mathrm{PO}_{4}{ }^{3}{ }^{-}(a q) $$ (a) How many \(\mathrm{Na}^{+}\)and \(\mathrm{PO}_{4}{ }^{3}\) ions form for each \(\mathrm{Na}_{3} \mathrm{PO}_{4}\) formula unit that dissolves? (b) How many moles of \(\mathrm{Na}^{+}\)and \(\mathrm{PO}_{4}{ }^{3}\) form for each mole of \(\mathrm{Na}_{3} \mathrm{PO}_{4}\) that dissolves?

Suppose you want to convert iron ore to a specific amount of pure iron using the following reaction: $$ \mathrm{Fe}_{3} \mathrm{O}_{4}(s)+4 \mathrm{CO}(g) \longrightarrow 3 \mathrm{Fe}(s)+4 \mathrm{CO}_{2}(g) $$ (a) What mole ratio would you use in the following equation to determine the number of moles of \(\mathrm{CO}\) needed to react with a known amount of \(\mathrm{Fe}_{3} \mathrm{O}_{4}\) ? \(\mathrm{mol} \mathrm{Fe}_{3} \mathrm{O}_{4} \times=\mathrm{mol} \mathrm{CO}\) (b) If you add more than enough \(\mathrm{CO}\) so that all the \(\mathrm{Fe}_{3} \mathrm{O}_{4}\) reacts, what mole ratio would you use in the following equation to determine the moles of \(\mathrm{CO}_{2}\) produced? \(\mathrm{mol} \mathrm{Fe}_{3} \mathrm{O}_{4} \times=\mathrm{mol} \mathrm{CO}_{2}\) (c) Suppose you know the number of moles of \(\mathrm{Fe}\) product formed and you want to know the number of moles of \(\mathrm{CO}\) that reacted. What mole ratio would you use in the following equation? \(\mathrm{mol} \mathrm{Fe} \times \overline{\mathrm{F}}=\mathrm{mol}\)

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