Chapter 16: Problem 60
An alcohol has the formula \(\mathrm{C}_{5} \mathrm{H}_{11} \mathrm{OH}\). How many isomers can exist for this alcohol?
Short Answer
Expert verified
The formula \(\mathrm{C}_{5} \mathrm{H}_{11} \mathrm{OH}\) can have three isomers.
Step by step solution
01
Identify the carbon chain
In this case, there are five carbon atoms. So, start with the longest and shortest chains. In this case, they are all of length 5 which gives us pentanols.
02
Location of the OH group
Find all the possible locations for the hydroxyl group (\(\mathrm{OH}\)). The \(\mathrm{OH}\) group can attach at the first, second, third, fourth or fifth carbon since there are five carbon atoms.
03
Find isomers
Figure out how many isomers can be formed from each position of the hydroxyl group. If the \(\mathrm{OH}\) group is at the first or fifth carbon, it results in only one possible structure. If it's in the second or fourth carbon, it also results in one structure because the molecule is symmetrical about the center. However, if the \(\mathrm{OH}\) group is at the third carbon, there are two possible structures: one with the \(\mathrm{OH}\) group on the end carbon (1-pentanol) and one with the \(\mathrm{OH}\) group in the middle of the carbon chain (2-methyl-2-butanol).
04
Count the isomers
By adding the number of isomers for each position, we can find the total number of isomers. In this case, there are three isomers.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Isomer Counting
When we talk about isomer counting, we're basically counting the different ways atoms can be arranged in a molecule while keeping the total number the same. For the alcohol with the formula \( \mathrm{C}_{5} \mathrm{H}_{11} \mathrm{OH} \), this involves seeing how many distinct ways we can arrange the carbon and hydroxyl groups.
To break it down:• We find locations on the 5-carbon backbone.• Then we examine the symmetry because some placements will mirror each other, reducing the total count of unique isomers.
- The total number of carbon atoms set the backbone structure.
- We consider different configurations based on where bonds are placed.
To break it down:• We find locations on the 5-carbon backbone.• Then we examine the symmetry because some placements will mirror each other, reducing the total count of unique isomers.
Alcohol Isomers
Alcohol isomers are different configurations of molecules that contain the same molecular formula but differ in the structure of their atoms.
In alcohol molecules, this is specifically about where the \( \mathrm{OH} \) group is attached to the carbon atoms.
In alcohol molecules, this is specifically about where the \( \mathrm{OH} \) group is attached to the carbon atoms.
- "Pentanols" as a category has isomers based on attachment points.
- For molecular formulas like \( \mathrm{C}_{5} \mathrm{H}_{11} \mathrm{OH} \), each connection point leads to a distinct structural isomer.
Hydroxyl Group Positioning
The position of the hydroxyl group (\( \mathrm{OH} \)) in an alcohol molecule significantly affects its structure and properties.
Here's why positioning is important:
Here's why positioning is important:
- The "end" carbon position might create a straight-chained alcohol like 1-pentanol.
- A central carbon attachment, such as on the second or third carbon, provides more internal isomer variations.
- Symmetry around the carbon chain can reduce the number of distinguishable isomers, as in placing the \( \mathrm{OH} \) on the second and fourth carbons resulting in structurally identical alcohols.