Sodium hydroxide \(\text{(NaOH)}\) is a strong base and completely dissociates in water. When solving problems involving \(\text{NaOH}\), the concentration of \(\text{NaOH}\) is equal to the concentration of hydroxide ions \(\text{[OH}^-\text{]}\) it produces. Thus, once \(\text{[OH}^-\text{]}\) is calculated, you directly know the \(\text{NaOH}\) concentration. For example, if \(\text{[OH}^-\text{]}\) is found to be \(0.1\) M, then the concentration of \(\text{NaOH}\) is also \(0.1\) M.
This principle is vital for understanding how strong bases like \(\text{NaOH}\) behave in solutions. They dissociate completely, meaning each formula unit of \(\text{NaOH}\) adds a complete unit of \(\text{OH}^-\text{]}\) to the solution. This direct equivalence simplifies calculations in chemistry, especially when working with strong bases.
Review the process with these steps:
- Understand that \(\text{NaOH}\) dissociates completely in water.
- The \(\text{NaOH}\) concentration equals the \(\text{[OH}^-\text{]}\) concentration.