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Copper(II) chloride is not completely reduced by \(\mathrm{SO}_{2}\) in concentrated HCl solution. Suggest an explanation for this observation and state how you would try to establish if the explanation is correct.

Short Answer

Expert verified
Cu(II) chloride forms stable complexes in concentrated HCl, limiting reduction. Test by adjusting HCl concentration or using spectroscopy.

Step by step solution

01

Understand the Reaction

The reaction in question involves the reduction of Copper(II) chloride (CuCl₂) by sulfur dioxide (SO₂) in a concentrated hydrochloric acid (HCl) solution. The expected product would normally be Copper(I) chloride (CuCl) and potentially elemental sulfur or sulfate compounds, indicating a reduction process.
02

Recognize Limiting Factors

Consider why the reaction might not proceed completely. One possibility is that the concentration of HCl is high enough to stabilize Cu²⁺ ions by forming complex ions, such as \[ \text{{CuCl}}_4^{2-} \]. This would decrease the likelihood of reduction fully occurring, as Cu²⁺ prefers being in its stable complex form.
03

Evaluate Competing Reactions

Another aspect to consider is that SO₂ may react with available H⁺ ions in the HCl solution to form sulfurous acid (H₂SO₃), which reduces the number of SO₂ molecules available to react with the copper ions. This could further explain incomplete reduction.
04

Plan an Experimental Test

To verify if complex ion formation with Cu²⁺ is the reason for incomplete reduction, conduct an experiment by repeating the reaction under varying concentrations of HCl. If the reduction extends as the concentration of HCl decreases, it suggests complex ion formation is significant. Alternatively, spectroscopic analysis after the reaction could provide evidence of CuCl₄²⁻.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Complex Ion Formation
When Copper(II) chloride is immersed in a concentrated hydrochloric acid solution, the environment is ripe for the formation of complex ions. Copper(II) ions (\(\text{Cu}^{2+}\)) have a propensity to form coordination compounds or complex ions with chloride ions (\(\text{Cl}^-\)).
A common complex ion formed is \(\text{CuCl}_4^{2-}\). This entity is more stable than the simple copper ion, making it less likely for \(\text{Cu}^{2+}\) to reduce to \(\text{Cu}^+\) or other lower oxidation states. This stabilizing effect means less copper ions are available for reduction.
To experimentally explore this, one might vary the concentration of chloride ions in solution and observe any changes in the extent of reduction. This would confirm the degree to which \(\text{CuCl}_4^{2-}\) formation impacts the reduction process.
Incomplete Reduction
The phenomenon of incomplete reduction relates to the inability of a reducing agent to completely change the oxidation state of another compound. In this case, the Copper(II) chloride is not fully reduced to Copper(I) chloride by sulfur dioxide.
The main reasons could include the formation of stable complex ions, as well as other competing reactions within the solution. For example, the reducing agent, sulfur dioxide, can participate in side reactions such as forming sulfurous acid when interacting with the HCl solution.
To deduce the cause of incomplete reduction, one can observe the reaction outcome through different chemical conditions or adjust reactant concentrations to see if the extent of reduction changes.
Spectroscopic Analysis
Spectroscopic analysis serves as a powerful method for investigating the nature of substances formed in a chemical reaction. By analyzing the interaction of light with chemical substances, you can gain indications of the presence of complex ions.
In the context of the copper chloride and sulfur dioxide reaction, spectroscopy can help identify whether complex ions such as \(\text{CuCl}_4^{2-}\) are present. Techniques such as UV-Vis spectroscopy would reveal specific absorption bands indicative of these complexes.
Such analysis allows for confirming hypotheses related to complex ion formation and provides quantitative data on the proportions of different species, facilitating a deeper understanding of the process.
Reaction Conditions
Reaction conditions including temperature, concentration, and pH play a crucial role in determining the path and extent of a chemical reaction. In a concentrated HCl solution, these factors are key to understanding why copper ions are not fully reduced by sulfur dioxide.
A high concentration of HCl can favor the formation of complex ions, limiting the free copper ions available for reduction. Conversely, changing the temperature or altering the medium’s concentration could shift equilibrium positions, providing insights into optimal conditions for maintaining free ions.
Testing varied conditions, such as progressively diluting the HCl concentration, can illustrate the effect of reaction parameters, validating or refuting the explanations proposed for incomplete reduction.

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Most popular questions from this chapter

Give equations for the following reactions: (a) aqueous \(\mathrm{NaOH}\) with \(\mathrm{CuSO}_{4} ;(\mathrm{b}) \mathrm{CuO}\) with \(\mathrm{Cu}\) in concentrated HCl at reflux; (c) Cu with concentrated \(\mathrm{HNO}_{3}\) (d) addition of aqueous \(\mathrm{NH}_{3}\) to a precipitate of \(\mathrm{Cu}(\mathrm{OH})_{2}\) (e) \(\mathrm{ZnSO}_{4}\) with aqueous NaOH followed by addition of excess \(\mathrm{NaOH} ;(\mathrm{f}) \mathrm{ZnS}\) with dilute \(\mathrm{HCl}\)

Dimethyl sulfoxide (DMSO) reacts with cobalt(II) perchlorate in EtOH to give a pink compound A which is a 1: 2 electrolyte and has a magnetic moment of \(4.9 \mu_{\mathrm{B}}\) Cobalt(II) chloride also reacts with DMSO, but in this case the dark blue product, \(\mathbf{B}\), is a 1: 1 electrolyte, and the magnetic moment of \(\mathbf{B}\) is \(4.6 \mu_{\mathrm{B}}\) per Co centre. Suggest a formula and structure for A and B.

Give explanations for the following observations. (a) The complex \(\left[\mathrm{Co}(\mathrm{en})_{2} \mathrm{Cl}_{2}\right]_{2}\left[\mathrm{CoCl}_{4}\right]\) has a room temperature magnetic moment of \(3.71 \mu_{\mathrm{eff}}\) (b) The room temperature magnetic moment of \(\left[\mathrm{CoI}_{4}\right]^{2-}\) (e.g. \(5.01 \mu_{\mathrm{B}}\) for the \(\left[\mathrm{Et}_{4} \mathrm{N}\right]^{+}\) salt) is larger than that of salts of \(\left[\mathrm{CoCl}_{4}\right]^{2-}\)

(a) The value of \(\mu_{\mathrm{eff}}\) for \(\left[\mathrm{CoF}_{6}\right]^{3-}\) is \(5.63 \mu_{\mathrm{B}} .\) Explain why this value does not agree with the value for \(\mu\) calculated from the spin-only formula. (b) By using a simple \(\mathrm{M} \mathrm{O}\) approach, rationalize why oneelectron oxidation of the bridging ligand in \(\left[(\mathrm{CN})_{5} \mathrm{CoOOCo}(\mathrm{CN})_{5}\right]^{6-}\) leads to a shortening of the \(\mathrm{O}-\mathrm{O}\) bond (c) Salts of which of the following complex ions might be expected to be formed as racemates: \(\left[\mathrm{Ni}(\operatorname{acac})_{3}\right]^{-}\) \(\left[\mathrm{CoCl}_{3}(\mathrm{NCMe})\right]^{-},\) cis-\(\left[\mathrm{Co}(\mathrm{en})_{2} \mathrm{Cl}_{2}\right]^{+},\) trans- \(\left[\mathrm{Cr}(\mathrm{en})_{2} \mathrm{Cl}_{2}\right]^{+} ?\)

(a) When \([\mathrm{CN}]^{-}\) is added to aqueous \(\mathrm{Ni}^{2+}\) ions, a green precipitate forms; if excess \(\mathrm{KCN}\) is added, the precipitate dissolves to give a yellow solution and at high concentrations of \([\mathrm{CN}]^{-},\) the solution becomes red. Suggest an explanation for these observations. (b) If the yellow compound from part (a) is isolated and reacted with Na in liquid \(\mathrm{NH}_{3},\) a red, air-sensitive, diamagnetic product can be isolated. Suggest its identity.

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