Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Compare the physical and chemical properties of \(\alpha\) - and \(\gamma\) -alumina, choosing examples that highlight why it is important not to call \(\mathrm{Al}_{2} \mathrm{O}_{3}\) simply 'alumina'

Short Answer

Expert verified
\(\alpha\)-alumina is hard and chemically inert, used for abrasives; \(\gamma\)-alumina is porous and reactive, used in catalysis. This distinction is critical for correct application.

Step by step solution

01

Understand the Problem

We need to compare the properties of two forms of alumina, i.e., \(\alpha\)-alumina and \(\gamma\)-alumina. These are both forms of \(\mathrm{Al}_2\mathrm{O}_3\), but they have different structures and properties.
02

Identify Physical Properties

\(\alpha\)-alumina, also known as corundum, has a hexagonal close-packed structure and is known for its exceptional hardness, making it useful as an abrasive and in cutting tools. \(\gamma\)-alumina, however, has a defect spinel structure, is less dense, and is used for its larger surface area in catalysis.
03

Identify Chemical Properties

\(\alpha\)-alumina is chemically inert, stable at high temperatures, and resistant to chemical corrosion. \(\gamma\)-alumina, on the other hand, is reactive due to its high surface area and porosity, which makes it suitable for use as a catalyst support in industrial applications.
04

Highlight Application Differences

Due to its hardness and stability, \(\alpha\)-alumina is commonly used in industrial applications such as polishing, grinding, and in the production of refractory materials. \(\gamma\)-alumina, with its surface properties, is often used in applications requiring catalysis and adsorption.
05

Summarize Importance

The significant differences in the structure and properties of \(\alpha\)- and \(\gamma\)-alumina underscore the importance of specifying which form of alumina is being used. The choice of alumina type can drastically affect its suitable applications and performance characteristics.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Physical Properties of Alumina
When we talk about alumina, we refer to aluminum oxide, (\(\mathrm{Al}_2\mathrm{O}_3\)), which comes in different forms, primarily \(\alpha\)-alumina and \(\gamma\)-alumina. Understanding the physical properties of these two forms is crucial as they determine the use and effectiveness in various applications.
\(\alpha\)-alumina is known for its hardness, ranking just below diamond. This remarkable hardness, attributed to its hexagonal close-packed structure, makes \(\alpha\)-alumina perfect for use in abrasive and cutting tools. This form of alumina has a very dense configuration and is clear, like a gemstone when pure.
In contrast, \(\gamma\)-alumina exhibits a defect spinel structure, which results in lower density. This less dense state allows for a higher surface area and porosity, making it significantly different from its \(\alpha\) counterpart. The higher surface area of \(\gamma\)-alumina makes it suitable for applications such as catalysts in chemical reactors.
The distinct structural differences between these forms underscore why simply calling it 'alumina' fails to capture their unique characteristics.
Chemical Properties of Alumina
The chemical behavior of alumina also varies significantly between its \(\alpha\) and \(\gamma\) forms. \(\alpha\)-alumina is known for its chemical inertness, which means it does not react easily with other substances. This stability is a result of the strong bonds and compact structure in \(\alpha\)-alumina, which makes it resistant to corrosion and high temperatures. Such chemical stability is why \(\alpha\)-alumina is noted for its durability and long-lasting nature in severe environments.
On the flip side, \(\gamma\)-alumina presents a contrasting picture. Due to its high surface area and porosity, \(\gamma\)-alumina is quite reactive. This reactivity is an advantage in processes where interaction with various chemicals is desired, such as in catalysis.
\(\gamma\)-alumina's chemical properties make it an excellent choice for adsorption processes where substances cling onto a surface. This form of alumina serves as an ideal support material in catalysts, helping speed up chemical reactions in industries.
Applications of α-alumina and γ-alumina
Knowing the applications of \(\alpha\)-alumina and \(\gamma\)-alumina helps in appreciating their industrial importance.
\(\alpha\)-alumina’s robustness and enduring nature drives its use in industrial settings. This form is often employed to make cutting and polishing tools due to its toughness. Furthermore, \(\alpha\)-alumina is used significantly in creating refractory materials which are essential for withstanding high temperatures without degrading.
\(\gamma\)-alumina plays a different role, leveraging its high surface area and porosity. It's prominently used where catalysis is essential, such as in catalytic converters in automobile exhausts, where it helps break down harmful emissions.
\(\gamma\)-alumina also finds use in adsorption applications for instance, in water treatment plants where it aids in purifying water by adsorbing pollutants.
Importance of Alumina Specification
Choosing the right form of alumina is crucial because each has unique properties, affecting how they perform in applications. It’s important not just to generically call \(\mathrm{Al}_2\mathrm{O}_3\) 'alumina,' but to be precise about which type is being employed.
Using the incorrect form can lead to suboptimal results or even failure in applications. For instance, employing \(\gamma\)-alumina for tasks demanding maximum hardness would be unwise due to its lesser density and hardness compared to \(\alpha\)-alumina. Similarly, using \(\alpha\)-alumina in processes relying on high surface area and reactivity might render it ineffective.
Clear specification of alumina form ensures its properties align with application requirements maximizing efficiency, durability, and functionality. This emphasizes the importance of understanding and specifying alumina variations to avoid mishaps and capitalize fully on their individual strengths.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Write a brief account of the bonding and reactivity of borazine which emphasizes the ways in which this compound is similar or dissimilar to benzene.

Write equations for the following processes, involved in the extraction of the elements from their ores: (a) the reduction of boron oxide by \(\mathrm{Mg}\) (b) the result of the addition of hot aqueous \(\mathrm{NaOH}\) to a mixture of solid \(\mathrm{Al}_{2} \mathrm{O}_{3}\) and \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) (c) the reaction of \(\mathrm{CO}_{2}\) with aqueous \(\mathrm{Na}\left[\mathrm{Al}(\mathrm{OH})_{4}\right]\)

Suggest likely products for the following reactions: (a) \(\mathrm{BCl}_{3}+\mathrm{EtOH} \rightarrow\) (b) \(\mathrm{BF}_{3}+\mathrm{EtOH} \rightarrow\) (c) \(\mathrm{BCl}_{3}+\mathrm{PhNH}_{2} \rightarrow\) (d) \(\mathrm{BF}_{3}+\mathrm{KF} \rightarrow\)

(a) Write down the formula of cryolite. (b) Write down the formula of perovskite. (c) Cryolite is described as possessing a 3 -dimensional structure closely related to that of perovskite. Suggest how this is possible when the stoichiometries of the two compounds do not appear to be compatible.

The ordering of the relative stabilities of adducts \(\mathrm{L} \cdot \mathrm{BH}_{3}\) for some common adducts is, according to L: \(\mathrm{Me}_{2} \mathrm{O}<\mathrm{THF}<\mathrm{Me}_{2} \mathrm{S}<\mathrm{Me}_{3} \mathrm{N}<\mathrm{Me}_{3} \mathrm{P}<\mathrm{H}^{-}\). In addition to answering each of the following, indicate how you could use NMR spectroscopy to confirm your proposals. (a) What happens when \(\mathrm{Me}_{3} \mathrm{N}\) is added to a THF solution of THF.BH \(_{3}\) ? (b) Will \(\mathrm{Me}_{2} \mathrm{O}\) displace \(\mathrm{Me}_{3} \mathrm{P}\) from \(\mathrm{Me}_{3} \mathrm{P} \cdot \mathrm{BH}_{3} ?\) (c) Is \(\left[\mathrm{BH}_{4}\right]^{-}\) stable in THF solution with respect to a displacement reaction? (d) Suggest what may be formed when \(\mathrm{Ph}_{2} \mathrm{PCH}_{2} \mathrm{CH}_{2} \mathrm{PPh}_{2}\) is added to a THF solution of THF. \(\mathrm{BH}_{3},\) the latter remaining in excess.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free