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The reactions of alkenes are mainly (a) nucleophilic additions (b) nucleophilic substitutions (c) free radical reactions (d) electrophilic additions

Short Answer

Expert verified
Answer: The main type of reaction that alkenes undergo is (d) electrophilic additions.

Step by step solution

01

Identify the nature of alkenes'

Alkenes are characterized by the presence of a carbon-carbon double bond. This double bond is electron-rich and therefore attracts electrophiles or positive species.
02

Consider the different types of reactions presented in the exercise's options and identify the ones that involve electrophiles:

(a) Nucleophilic additions: These are reactions where a nucleophile (electron-rich species) adds to a molecule. This does not fit the nature of alkenes. (b) Nucleophilic substitutions: These reactions involve a nucleophile replacing another group or atom in a molecule. Again, this does not fit the nature of alkenes. (c) Free radical reactions: In these reactions, a species with an unpaired electron reacts with other molecules. Though some alkenes can undergo free-radical reactions (e.g., polymerization), this is not their main type of reaction. (d) Electrophilic additions: These reactions involve an electrophile (electron-poor species) adding across the double bond of alkenes. Since alkenes are electron-rich, this type of reaction aligns with their nature.
03

Choose the correct answer based on the analysis of reaction types.

Since the main reactions of alkenes involve electrophiles, the correct answer is (d) electrophilic additions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electrophilic Additions
Understanding electrophilic additions is crucial when studying the behavior of alkenes in organic chemistry. Alkenes, compounds with at least one carbon-carbon double bond, are characterized by their electron-rich nature. This makes them appealing targets for electrophiles – particles that are electron-deficient and seeking to gain electrons. Electrophilic addition is a two-step process:

  • The electrophile attacks the electron-rich double bond, forming a carbocation intermediate.
  • A nucleophile then quickly attacks the positively charged carbocation, giving rise to the addition product.
This reaction is fundamental in creating a variety of organic compounds with different functional groups.
Improving your grasp of electrophilic additions involves visualizing the electron flow during the reaction. Imagine the double bond as a magnet for electrophiles, and the subsequent steps as a dance where each partner must find its place. When you picture these reactions, remember the role of stability – carbocations favor more substituted, hence stable, configurations.
Reaction Mechanisms
Diving into reaction mechanisms grants us insight into the step-by-step transformation that chemical species undergo during a reaction. It's akin to dissecting the moves of a complex dance, where each step must be clearly understood and executed. For alkenes reacting through electrophilic addition, two major steps define the mechanism: the attack of the electrophile and the capture of the carbocation by a nucleophile.

A crucial element when learning about these mechanisms is to be familiar with terms like 'intermediate', 'transition state', and 'activation energy'. Intermediates, such as carbocations in electrophilic additions, are temporary structures that exist within the course of a reaction. Transition states are fleeting and represent the highest energy point between reactants and products. The concept of activation energy is essential too, as it delineates the energy needed to reach this point from the reactants. To enhance understanding, drawing detailed reaction mechanisms with arrow pushing can elucidate the path electrons take, which is pivotal for mastering organic synthesis.
Organic Chemistry Concepts
Grasping fundamental organic chemistry concepts is indispensable for any student wishing to excel in the field. These concepts include understanding the nature of chemical bonds – with a particular emphasis on the electron-rich double bonds found in alkenes – and how these influence a molecule's reactivity.

Other core concepts include:
  • The properties and behaviors of different functional groups.
  • Isomers and the significance of molecular geometry.
  • Acid-base reactions specific to organic chemistry, such as the role played by Lewis acids and bases.
To simplify these complex concepts, visualize the molecular structures and the potential sites for chemical reactions. Always consider how changes in structure can lead to significant differences in chemical behavior. For instance, the simple addition of a halogen across an alkene’s double bond can transform a non-polar hydrocarbon into a polar halogenated compound. These conceptual building blocks are the basis for understanding all the reactions and mechanisms in the rich tapestry of organic chemistry.

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Most popular questions from this chapter

Complete the following equations showing the stereo chemistry of the product wherever applicable. (i) Cis-2-pentene \(\stackrel{\mathrm{H}_{2} / \mathrm{Pt}}{\longrightarrow}\) (ii) Cis-2-butene \(\stackrel{\mathrm{Br}_{2} / \mathrm{CCl}_{4}}{\longrightarrow}\) (iii) Cis-2-butene \(\stackrel{\mathrm{m}-\mathrm{CPBA}}{\longrightarrow}\) (iv)

Each question in this section has four suggested answers out of which ONE OR MORE answers will be correct. Which of the following statements is correct? (a) Cyclopropane will react with chlorine or bromine at room temperature, in diffused light to give a dihalogen derivative. (b) A hydrocarbon of molecular formula \(\mathrm{C}_{4} \mathrm{H}_{6}\) should contain always a triple bond. (c) The trans isomer of an alkene is generally less polar than the cis isomer. (d) \(\mathrm{H}_{2} \mathrm{C}=\mathrm{CH}-\mathrm{CH}_{2}-\mathrm{CH}=\mathrm{CH}_{2}\) is an example of cumulated diene.

An organic compound (A) \(\mathrm{C}_{5} \mathrm{H}_{8}\) does not react with Tollens reagent but reacts with \(\mathrm{H}_{2}\) in the presence of Lindlar catalyst to give (B). Aqueous chlorine water reacts with (B) to give (C) which when reacted with hot alcoholic KOH gives (D). The compound (D) is (a) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{C} \equiv \mathrm{CH}\) (b) \(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}(\mathrm{OH})-\mathrm{CH}_{3}\) (c) \(\mathrm{H}_{3} \mathrm{C}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}_{2}\) (d)

Match the elements of Column I to elements of Column II. There can be single or multiple matches. Column I (a) Markovnikov addition (b) anti Markovnikov hydration (c) \(\mathrm{OsO}_{4}\) and an alkene (d) Catalytic hydrogenation Column II (p) 1-Butyne and HOCl (q) syn addition (r) Hydroboration-oxidation (s) Addition of HI to but-1-ene in the presence of \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COO}\right)_{2}\)

When propyne reacts with excess of chlorine water, the product obtained is (a) 1,1 -dichloro propan-2-one (b) 1,1 -dichloropropan-2-ol (c) 2,2 -dichloropropan- 1 -al (d) 1,2 -dichloropropane

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