Question

Identify the reaction in which the equation is represented correctly (a) \(\mathrm{CF}_{3} \mathrm{CH}=\mathrm{CH}_{2}+\mathrm{HBr} \rightarrow \mathrm{CF}_{3} \mathrm{CHBr} \mathrm{CH}_{3}\)

Short answer

Answer: No, the given chemical equation is not correctly balanced as the number of Hydrogen atoms is unequal on both sides of the equation.

Step-by-step solution

Identify and count the atoms on the reactant side

The reactant side of the equation is: \(\mathrm{CF}_{3}\mathrm{CH}=\mathrm{CH}_{2}+\mathrm{HBr}\). From this, we can see that we have 1 Carbon (C), 3 Fluorines (F), 3 Hydrogens (H), and 1 Bromine (Br) atom.

Identify and count the atoms on the product side

The product side of the equation is: \(\mathrm{CF}_{3}\mathrm{CHBr}\mathrm{CH}_{3}\). In the product, we can count 2 Carbon (C), 3 Fluorines (F), 4 Hydrogens (H), and 1 Bromine (Br) atom.

Compare the number of atoms on both sides

From our analysis of the reactant and product side of the equation, we can see that the number of Carbon atoms, Fluorine atoms, and Bromine atoms are the same, but the number of Hydrogen atoms is different. Reactant side: 1 C, 3 F, 3 H, 1 Br Product side: 2 C, 3 F, 4 H, 1 Br Since the number of Hydrogen atoms is unequal on both sides, the given chemical equation is not correctly balanced.

Key concepts

Chemical Reaction Balancing

Balancing chemical reactions is fundamental to understanding chemical equations. Each reaction must follow the Law of Conservation of Mass, which states that matter is neither created nor destroyed in a chemical reaction. Thus, the number of each type of atom on the reactant side must be equal to the number on the product side.

When balancing the given IIT JEE Organic Chemistry question, you need to ensure that each reactant atom finds its rightful place in the products. If we analyze the exercise provided, the reaction with the organic compound and HBr isn't balanced. There's an inconsistency in the number of hydrogen atoms. A balanced reaction reflects the actual quantities and species involved in the chemical process, provides insight into the stoichiometry, and is essential for the correct calculation of the reactants and products.

Balancing requires a stepwise approach: counting the number of each atom in both reactants and products and adjusting coefficients to equalize them. Sometimes, like in organic reactions, additional challenges such as preserving the structure of complex molecules come into play. Therefore, close attention to detail and systematic adjustment are keys to success in balancing chemical reactions.

Organic Reaction Mechanisms

Organic reaction mechanisms map out the step-by-step transformation of reactants to products, showing how electrons move during a reaction. For an IIT JEE aspirant, understanding these mechanisms is critical as they are the beacon that guides one through the complexity of Organic Chemistry.

Each mechanism involves bond-breaking and bond-forming steps. The type of bonds involved and how they reorganize define the mechanism's path. In our example exercise, the mechanism would likely proceed via electrophilic addition. HBr adds across the alkene's double bond; the electron-rich double bond attacks the electrophil, H⁺, which, in turn, leads to the formation of a carbocation intermediate that reacts with Br^-.

Understanding these mechanisms enables one to predict the products of unknown reactions, determine reaction kinetics, and design synthesis pathways for organic compounds. Study patterns, such as nucleophile/electrophile behavior and electron movement, to develop a clear understanding of various mechanisms.

Halogenation Reactions

Halogenation is a type of chemical reaction in which a halogen is introduced into a molecule, often an organic compound. In the exercise, we're dealing with the addition of Bromine (Br), a halogen, to an alkene. It's a specific case of an addition reaction where a halogen molecule adds across the double bond of an unsaturated hydrocarbon.

The halogenation process is highly relevant in IIT JEE Organic Chemistry for designing syntheses and understanding reaction pathways. It involves multiple steps, starting with the formation of a halonium ion intermediate followed by nucleophilic attack. This reaction is generally regioselective, meaning the position where the halogen adds depends on the stability of the resultant intermediates.

For students, grasping the concept of halogenation is essential for predicting outcomes of organic reactions and understanding how complex molecules can be modified. When analyzing halogenation reactions, consider the type of halogen, the nature of the organic compound, and the conditions under which the reaction takes place, as these factors influence the rate and the outcome of the reaction.