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How many grams of \(\mathrm{KOH}\) are present in \(35.0 \mathrm{~mL}\) of a \(5.50 \mathrm{M}\) solution?

Short Answer

Expert verified
The mass of KOH present in 35.0 mL of a 5.50 M solution is 10.80 grams.

Step by step solution

01

Convert Volume to Liters

The given volume of the solution is in milliliters. However, the unit of volume in molarity is liter. Therefore, we need to convert the volume from milliliters to liters. Since 1 L = 1000 mL, we have \(35.0 \, \text{mL} = 35.0 / 1000 = 0.035 \, \text{L}\)
02

Calculate the number of moles of KOH

Use the formula for molarity (M = moles/L) to find the number of moles in the solution. Since \(M = \text{moles} / \text{L}\),... we can find the number of moles by rearranging the formula as: moles = \(M \times \text{L}\). So, the moles of KOH = 5.50 M * 0.035 L = 0.1925 moles
03

Convert moles to grams

We'll use the molar mass of KOH to convert the amount from moles to grams. The molar mass of KOH is 56.105 g/mol. So, grams of KOH = moles * molar mass = 0.1925 moles * 56.105 g/mol = 10.80 g

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Converting Milliliters to Liters
Understanding how to convert milliliters (mL) to liters (L) is critical for making precise calculations in chemistry, especially when dealing with solutions. One liter is equivalent to 1000 milliliters. The conversion is relatively straightforward: to convert milliliters to liters, you divide the number of milliliters by 1000.

For example, if you have 35.0 mL of a solution, and you want to know how many liters that is, you'd perform the following calculation: \[\begin{equation} 35.0\, \text{mL} = \frac{35.0}{1000} = 0.035\, \text{L} \end{equation}\]
. This step is paramount as molarity calculations require volumes in liters.
Molarity Formula
The molarity of a solution is one of the most common methods to express concentration. It is denoted by the symbol 'M' and is defined as the number of moles of solute per liter of solution. The formula for calculating molarity is:\[\begin{equation} M = \frac{\text{moles of solute}}{\text{liters of solution}} \end{equation}\]
. To find the molarity, you divide the moles of the solute by the volume of the solution in liters. Conversely, if molarity and volume are known, you can find the number of moles by rearranging the formula as: \[\begin{equation} \text{moles} = M \times \text{L} \end{equation}\]
. For instance, if a solution has a molarity of 5.50 M and there is 0.035 L of it, the number of moles would be calculated as 5.50 M multiplied by 0.035 L, giving you 0.1925 moles of the solute.
Molar Mass Conversion
After determining the number of moles of a substance, the next step is often to convert that quantity into grams. The molar mass is the weight of one mole of a substance and is expressed in grams per mole (g/mol). Each element's molar mass can be found on the periodic table, and the molar mass of a compound is the sum of the individual molar masses of each element in it.

To convert moles to grams, you multiply the number of moles by the molar mass: \[\begin{equation} \text{grams} = \text{moles} \times \text{molar mass} \end{equation}\]
. So, if you have 0.1925 moles of KOH and the molar mass of KOH is 56.105 g/mol, you would calculate the grams of KOH as follows: \[\begin{equation} \text{grams of KOH} = 0.1925 \text{ moles} \times 56.105 \text{ g/mol} = 10.80 \text{ g} \end{equation}\]
. This conversion from moles to grams allows you to understand the actual amount of substance in a tangible form.

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Most popular questions from this chapter

Give a chemical explanation for each of these: (a) When calcium metal is added to a sulfuric acid solution, hydrogen gas is generated. After a few minutes, the reaction slows down and eventually stops even though none of the reactants is used up. Explain. (b) In the activity series aluminum is above hydrogen, yet the metal appears to be unreactive toward steam and hydrochloric acid. Why? (c) Sodium and potassium lie above copper in the activity series. Explain why \(\mathrm{Cu}^{2+}\) ions in a \(\mathrm{CuSO}_{4}\) solution are not converted to metallic copper upon the addition of these metals. (d) A metal M reacts slowly with steam. There is no visible change when it is placed in a pale green iron(II) sulfate solution. Where should we place \(\mathrm{M}\) in the activity series?

Identify each of the following substances as a strong electrolyte, weak electrolyte, or nonelectrolyte: (a) \(\mathrm{H}_{2} \mathrm{O},\) (b) \(\mathrm{KCl}\) (c) \(\mathrm{HNO}_{3}\) (d) \(\mathrm{CH}_{3} \mathrm{COOH}\) (e) \(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\).

Before aluminum was obtained by electrolytic reduction from its ore \(\left(\mathrm{Al}_{2} \mathrm{O}_{3}\right)\), the metal was produced by chemical reduction of \(\mathrm{AlCl}_{3}\). Which metals would you use to reduce \(\mathrm{Al}^{3+}\) to \(\mathrm{Al} ?\)

The passage of electricity through an electrolyte solution is caused by the movement of (a) electrons only, (b) cations only, (c) anions only, (d) both cations and anions.

For the complete redox reactions given here, write the half-reactions and identify the oxidizing and reducing agents: (a) \(4 \mathrm{Fe}+3 \mathrm{O}_{2} \longrightarrow 2 \mathrm{Fe}_{2} \mathrm{O}_{3}\) (b) \(\mathrm{Cl}_{2}+2 \mathrm{NaBr} \longrightarrow 2 \mathrm{NaCl}+\mathrm{Br}_{2}\) (c) \(\mathrm{Si}+2 \mathrm{~F}_{2} \longrightarrow \mathrm{SiF}_{4}\) (d) \(\mathrm{H}_{2}+\mathrm{Cl}_{2} \longrightarrow 2 \mathrm{HCl}\)

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